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Question 1
ప్రశ్న 1
A congested commercial corridor has vehicles parked along its carriageway edge, while a separate municipal parking facility is proposed on an adjoining plot. Which description correctly distinguishes the two parking arrangements?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
On-street parking occupies designated space along the street or its kerb. Off-street parking is provided away from the main street carriageway, such as in a separate lot or structure. The two types can serve the same land uses but have different operational effects. Kerbside parking may affect effective roadway width and manoeuvring conflicts. Off-street facilities require attention to entry points, internal circulation and pedestrian access.
వివరణ:
Question 2
ప్రశ్న 2
For a given usable kerb length, compare typical parallel parking with angle parking of passenger cars, assuming both layouts are geometrically feasible. Which statement is most defensible?
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Explanation:
Parallel parking places vehicles approximately along the kerb and usually uses less lateral road space. Angle parking generally reduces the kerb frontage required per car when appropriate stall geometry is used. It correspondingly requires more depth and may create additional reversing or manoeuvring conflicts. Neither arrangement is universally preferable regardless of road width and operating conditions. Safety, traffic movement and available space must guide the selection.
వివరణ:
Question 3
ప్రశ్న 3
At the beginning of a parking-count interval, 24 vehicles are parked. During that interval, 11 vehicles enter and park and 7 parked vehicles depart. What is the parking accumulation at the end of the interval?
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Explanation:
Parking accumulation is the number of vehicles occupying the facility at a specified instant. The initial accumulation is 24 vehicles. Arrivals increase this number by 11, while departures reduce it by 7. Therefore the ending accumulation is 24 + 11 - 7 = 28 vehicles. This result is an instantaneous occupied-vehicle count, not the total parking volume served during the interval.
వివరణ:
Question 4
ప్రశ్న 4
A survey plots the number of occupied parking spaces against time. Which statistic is represented by the area under this accumulation-time curve, provided time is expressed in hours?
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Explanation:
The accumulation curve shows how many vehicles are parked at each time. Integrating the vehicle count with respect to time yields the parking load. When the horizontal axis is in hours, the unit is vehicle-hours. A peak accumulation is only the largest ordinate of this curve. Parking turnover instead relates the number of parking sessions to the number of parking spaces.
వివరణ:
Question 5
ప్రశ్న 5
A parking lot is empty at the beginning of a four-hour survey. During the survey, 36 different vehicles enter and park exactly once, and 28 of these vehicles depart before the survey ends. What are the observed parking volume and the final parking accumulation, respectively?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
Parking volume represents the number of parking sessions recorded over the stated observation period. Since the lot is initially empty and 36 different vehicles enter and park exactly once, the observed parking volume is 36 sessions. Parking accumulation represents the number of vehicles parked at a particular instant. The final accumulation is obtained by subtracting 28 departures from 36 arrivals, giving 8 vehicles. Thus parking volume and final accumulation are 36 sessions and 8 vehicles, respectively, and these two statistics must not be confused.
వివరణ:
Question 6
ప్రశ్న 6
A parking facility has a constant accumulation of 8, 12, 10 and 6 vehicles during four successive 30-minute intervals. What is the total parking load over these two hours?
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Explanation:
Each interval lasts 30 minutes, which equals 0.5 hour. Parking load is obtained by summing occupied vehicles multiplied by the time for which they remain. The sum of the four constant accumulations is 8 + 12 + 10 + 6 = 36. Multiplying 36 by 0.5 hour gives 18 vehicle-hours. The stated constant-accumulation assumption avoids any need for an unprovided accumulation graph.
వివరణ:
Question 7
ప్రశ్న 7
Thirty-six complete parking sessions have a combined parking load of 54 vehicle-hours. What is their average parking duration?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
Average parking duration equals the total duration of all parking sessions divided by their number. The total duration is given as 54 vehicle-hours. There are 36 complete parking sessions in the stated dataset. Dividing 54 by 36 gives 1.5 hours per session. This calculation does not require any correction for sessions cut off by the survey boundary because all sessions are specified as complete.
వివరణ:
Question 8
ప్రశ్న 8
A parking facility has 42 marked bays and serves 126 separate vehicle parking sessions during a six-hour survey. What is its parking turnover for the entire six-hour period, expressed as sessions per bay?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
Parking turnover over a defined study period is the number of parking sessions divided by the number of available bays. The facility serves 126 sessions using 42 bays. Therefore its turnover is 126/42 = 3 sessions per bay during six hours. This figure is not yet an hourly turnover rate. For an hourly average rate, the result would additionally be divided by six hours.
వివరణ:
Question 9
ప్రశ్న 9
A 30-bay parking area serves 180 vehicle parking sessions over four hours. What is the average hourly parking turnover rate?
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Explanation:
The period turnover is 180 divided by 30, giving 6 sessions per bay over four hours. The question requires a rate per hour. Dividing the period turnover by four gives 1.5 sessions per bay per hour. Equivalently, 180 can be divided by the product 30 times 4. Keeping the period turnover distinct from the hourly rate prevents a units error.
వివరణ:
Question 10
ప్రశ్న 10
A parking lot contains 35 usable bays and is observed for eight hours. Assuming the bays are continuously available, what is the parking time-capacity during the survey?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
Parking time-capacity equals the number of available bays multiplied by the observation duration. Here 35 bays are available throughout eight hours. Their capacity is therefore 35 times 8 = 280 bay-hours. A bay-hour represents the ability of one bay to accommodate one parked vehicle for one hour. Actual parking load can be smaller than this capacity if some bays remain vacant.
వివరణ:
Question 11
ప్రశ్న 11
At 11:00 a parking area has 48 usable bays, of which 36 are occupied. What is its instantaneous parking occupancy at 11:00?
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Explanation:
Instantaneous occupancy is the occupied-bay count divided by the available-bay count. At 11:00, 36 of the 48 usable bays are occupied. The ratio 36/48 equals 0.75. Multiplication by 100 gives an occupancy of 75%. This single-time observation does not by itself establish the average parking index over a longer survey period.
వివరణ:
Question 12
ప్రశ్న 12
A 30-bay parking facility is available for five hours and records a parking load of 120 vehicle-hours. What is its time-averaged parking index for this period?
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Explanation:
The capacity for the five-hour period is 30 times 5 = 150 bay-hours. The measured load is 120 vehicle-hours. The time-averaged parking index is the load divided by the capacity, multiplied by 100. This gives 120/150 times 100 = 80%. The index measures the proportion of available bay-time that was used during the stated period.
వివరణ:
Question 13
ప్రశ్న 13
During four successive 15-minute intervals, a 20-bay parking area has constant occupied-bay counts of 10, 14, 18 and 14, respectively. What is its parking index over the full one-hour observation?
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Explanation:
The total observation period is one hour, so 20 bays provide 20 bay-hours of capacity. Each of the four intervals lasts 0.25 hour. The parking load is (10 + 14 + 18 + 14) times 0.25 = 14 vehicle-hours. Dividing 14 by 20 and multiplying by 100 gives a parking index of 70%. Because the intervals are equal and the stated counts are constant within them, the same result follows from their arithmetic average occupancy.
వివరణ:
Question 14
ప్రశ్న 14
A shopping district records 250 distinct parking sessions during a survey, while its highest simultaneous accumulation is 65 vehicles. Which inference is justified by these observations alone?
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Explanation:
Parking volume counts parking sessions served over a period. Peak accumulation counts vehicles parked simultaneously at the busiest observed instant. The supplied observations give a peak of 65 parked vehicles and 250 sessions during the survey. The difference between the two figures does not measure illegal parking or rejected demand. Additional information on parking load, supply and unmet demand is needed before fixing a design provision.
వివరణ:
Question 15
ప్రశ్న 15
A completed parking-duration survey records 18 sessions of 20 minutes each and 12 sessions of 50 minutes each. What is the mean duration of these 30 sessions?
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Explanation:
The combined parked time for the first group is 18 times 20 = 360 vehicle-minutes. The second group contributes 12 times 50 = 600 vehicle-minutes. Their total is 960 vehicle-minutes over 30 sessions. Dividing 960 by 30 gives an average of 32 minutes. The mean must be weighted by the number of sessions rather than simply averaging 20 and 50 minutes.
వివరణ:
Question 16
ప్రశ్న 16
A survey records the initial occupancy of a parking lot and thereafter only the aggregate number of vehicles entering and leaving during each interval. What is the main limitation of this in-out counting approach when no vehicle identifiers are collected?
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Explanation:
An in-out survey tracks the aggregate number of parked vehicles using an occupancy balance. Entries and exits are sufficient to update accumulation from the starting count. They do not associate the recorded entry of a particular vehicle with its corresponding exit. Individual parking durations therefore cannot be directly recovered from these aggregate counts alone. Vehicle tracking or matched observations would be needed for that additional information.
వివరణ:
Question 17
ప్రశ్న 17
A parking-duration survey periodically records coded vehicle registration identifiers in each bay and matches them over successive rounds. Which assessment of this method is technically sound?
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Explanation:
Repeated observations of vehicle identifiers help determine whether the same vehicle continues to occupy a bay. They can be used to estimate parking duration and the pattern of bay use. Arrival and departure times are generally bracketed by the observation rounds rather than measured exactly. Longer observation intervals increase the chance that very short parking sessions will be missed. Appropriate privacy protection and consistent data collection are important when identifiers are recorded.
వివరణ:
Question 18
ప్రశ్న 18
A street serving short-stay retail customers is regularly occupied by a small number of all-day parked vehicles. Subject to proper enforcement and accessibility needs, which management measure most directly aims to improve short-stay parking turnover?
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Explanation:
Short-stay retail parking aims to allow multiple customers to use the same bay over the day. Long-duration occupation of limited kerbside spaces can restrict availability for these users. Appropriate time limits can encourage the release of bays after relatively short visits. Enforcement and clear signage are necessary for a time-limit policy to operate as intended. Any scheme should also consider loading, accessible parking and impacts on adjacent streets.
వివరణ:
Question 19
ప్రశ్న 19
A survey shows that designated on-street parking bays are occupied for 95% of the observation period. Which statement best reflects what can be concluded about parking demand?
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Explanation:
An index of 95% shows that most available bay-time was occupied during the observation period. It does not directly report how many drivers searched unsuccessfully for parking. Some demand may appear as illegal parking, spillover, waiting or diverted trips. Conversely, the occupied spaces might represent long stays with relatively low turnover. Estimating unmet demand requires additional field evidence such as search activity and nearby parking conditions.
వివరణ:
Question 20
ప్రశ్న 20
A proposed facility is expected to have 102 simultaneously parked cars at its design peak. If the planning target is to keep peak occupancy at or below 85% of the provided bays, what minimum whole number of bays is required?
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Explanation:
The number of parked cars divided by the number of bays must be no greater than the target fraction. With peak demand of 102 cars and maximum occupancy of 0.85, the required bay count is at least 102/0.85. This calculation gives exactly 120 bays. Providing 120 bays yields 102/120 = 85% peak occupancy. A smaller whole number of bays would exceed the specified maximum occupancy.
వివరణ:
Question 21
ప్రశ్న 21
For a simplified kerb-length exercise, 150 m of usable kerb is available. Assume each parallel bay needs 6.0 m of kerb frontage and each feasible angled bay needs 3.75 m, with all end clearances and access requirements already accounted for. How many more angled bays than parallel bays fit under these stated assumptions?
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Explanation:
The number of complete bays is the usable kerb length divided by the assumed frontage per bay. For parallel parking, 150/6.0 provides 25 bays. For angle parking, 150/3.75 provides 40 bays. The difference is 40 - 25 = 15 bays. This simplified comparison does not remove the need to check roadway depth, manoeuvring clearance and safety before choosing the angled layout.
వివరణ:
Question 22
ప్రశ్న 22
A 40-bay parking facility is available throughout a three-hour survey and achieves an average parking occupancy of 75%. What parking load does this imply?
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Explanation:
The three-hour time-capacity is 40 multiplied by 3 = 120 bay-hours. An average occupancy of 75% means that 0.75 of that capacity is utilized. Parking load is therefore 0.75 multiplied by 120. The result is 90 vehicle-hours. A single instantaneous occupancy measurement of 75% would not establish this load, but the question explicitly specifies the average occupancy for the period.
వివరణ:
Question 23
ప్రశ్న 23
A hospital campus needs a parking-demand study covering outpatient visitors and employees. Which survey design is best suited to evaluating both short-stay visitor demand and long-stay staff demand?
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Explanation:
Different hospital user groups can produce different parking arrival and duration patterns. Employees may occupy bays for long work shifts, while many visitors may stay for shorter periods. A representative survey should record occupancy, entry and exit activity and parking durations. Separating user groups helps identify when their demands overlap and whether shared use is feasible. Day selection and survey coverage matter because the busiest parking conditions may not occur during a single convenient observation interval.
వివరణ:
Question 24
ప్రశ్న 24
Two parking facilities each have 20 bays available for four hours and each serve 40 separate parking sessions. Facility P records 60 vehicle-hours of parking load, while Facility Q records 40 vehicle-hours. Which comparison is correct?
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Explanation:
Each facility serves 40 sessions using 20 bays, so each has a turnover of 40/20 = 2 sessions per bay. The four-hour capacity of either facility is 20 times 4 = 80 bay-hours. Facility P has an index of 60/80 times 100 = 75%. Facility Q has an index of 40/80 times 100 = 50%. Equal turnover does not imply equal occupancy because the total duration of the parking sessions can differ.
వివరణ:
Question 25
ప్రశ్న 25
A 20-bay lot is observed for four hours. All 80 recorded parking sessions are complete within the period and together account for 48 vehicle-hours of parking load. Which set of parking statistics is correct, in the order period turnover, parking index and average duration?
Select an option first. || ముందుగా ఒక సమాధానాన్ని ఎంచుకోండి.
Explanation:
Period turnover is 80 sessions divided by 20 bays, or 4 sessions per bay. The four-hour bay-time capacity is 20 times 4 = 80 bay-hours. Parking index is 48/80 multiplied by 100, which is 60%. Average duration is 48 vehicle-hours divided by 80 sessions, or 0.6 hour. Converting 0.6 hour to minutes gives 36 minutes, so only the final option contains all three correct values.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Kerbside spaces constitute on-street parking, while spaces within the separate plot constitute off-street parking. సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: D. Angle parking generally accommodates more cars per metre of kerb but requires greater depth and careful manoeuvring arrangements. సమాధానం: D.
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Question 3 ప్రశ్న 3Answer: C. 28 vehicles. సమాధానం: C.
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Question 4 ప్రశ్న 4Answer: A. Parking load in vehicle-hours. సమాధానం: A.
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Question 5 ప్రశ్న 5Answer: B. 36 parking sessions and 8 vehicles. సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: B. 18 vehicle-hours. సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: C. 1.50 hours. సమాధానం: C.
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Question 8 ప్రశ్న 8Answer: A. 3 sessions per bay. సమాధానం: A.
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Question 9 ప్రశ్న 9Answer: D. 1.5 sessions per bay per hour. సమాధానం: D.
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Question 10 ప్రశ్న 10Answer: B. 280 bay-hours. సమాధానం: B.
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Question 11 ప్రశ్న 11Answer: A. 75%. సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: C. 80%. సమాధానం: C.
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Question 13 ప్రశ్న 13Answer: D. 70%. సమాధానం: D.
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Question 14 ప్రశ్న 14Answer: B. The observed peak accumulation is 65 vehicles, and the total of 250 sessions must not be mistaken for simultaneous demand. సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: C. 32 minutes. సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: A. It cannot directly determine the individual parking duration of each vehicle. సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: D. Matched bay observations help estimate parking durations, but very short stays may be missed and durations are limited by the observation frequency. సమాధానం: D.
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Question 18 ప్రశ్న 18Answer: B. Introduce and enforce suitable short-stay time limits for the relevant bays. సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: C. The designated bays were highly utilized, but unmet demand cannot be quantified from occupancy alone. సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: A. 120 bays. సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: D. 15 bays. సమాధానం: D.
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Question 22 ప్రశ్న 22Answer: B. 90 vehicle-hours. సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. Record representative arrivals, departures, occupancy and stay durations by user group across relevant days and time periods. సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: A. Both have turnover of 2 sessions per bay; P has a 75% parking index and Q has a 50% index. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: D. 4 sessions per bay, 60% and 36 minutes. సమాధానం: D.