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Question 1
ప్రశ్న 1
A rectangular building has outside plan dimensions 13.45 m along its long walls and 9.45 m along its short walls. The external superstructure walls are uniformly 0.25 m thick. A symmetrical foundation trench of breadth 0.90 m follows the same wall axes. What are the long-wall out-to-out and short-wall in-to-in trench lengths respectively?
Explanation:
The long-wall centre-to-centre dimension is 13.45 - 0.25 = 13.20 m. The short-wall centre-to-centre dimension is 9.45 - 0.25 = 9.20 m. At excavation level, the relevant breadth is 0.90 m rather than the superstructure thickness. The long-wall out-to-out length is 13.20 + 0.90 = 14.10 m. The short-wall in-to-in length is 9.20 - 0.90 = 8.30 m.
వివరణ:
Question 2
ప్రశ్న 2
For a symmetrical rectangular foundation, the centre-to-centre lengths of the long and short walls are 11.60 m and 7.40 m respectively. Excavation trenches are 1.20 m wide, while the separate PCC bed is 0.70 m wide. What are the respective long-wall out-to-out and short-wall in-to-in lengths at excavation and PCC levels?
Explanation:
The wall-axis distances remain unchanged because both foundation layers are symmetrically centred. For excavation, the long-wall length is 11.60 + 1.20 = 12.80 m. The corresponding short-wall length is 7.40 - 1.20 = 6.20 m. At PCC level, the long-wall length is 11.60 + 0.70 = 12.30 m. The short-wall length is 7.40 - 0.70 = 6.70 m, so the two layers require different payable lengths.
వివరణ:
Question 3
ప్రశ్న 3
A rectangular foundation consists of TWO long trenches of centre-to-centre length 12.50 m each and TWO short trenches of centre-to-centre length 8.50 m each. All trenches are 1.10 m wide and 1.40 m deep. Assuming vertical sides, symmetrical alignment and no internal trenches, what is the total in-situ excavation volume?
Explanation:
Each long trench has an out-to-out length of 12.50 + 1.10 = 13.60 m. Each short trench has an in-to-in length of 8.50 - 1.10 = 7.40 m. The total payable trench length is 2(13.60) + 2(7.40) = 42.00 m. The excavation cross-sectional area is 1.10 x 1.40 = 1.54 m2. Hence the total excavation volume is 42.00 x 1.54 = 64.68 m3.
వివరణ:
Question 4
ప్రశ్న 4
A closed rectangular foundation has two long-wall centre-to-centre lengths of 9.80 m each and two short-wall centre-to-centre lengths of 6.20 m each. A symmetrical PCC bed is 0.90 m wide and 0.18 m thick throughout, with no internal branches. What is its total concrete quantity?
Explanation:
The long-wall out-to-out length is 9.80 + 0.90 = 10.70 m for each long wall. The short-wall in-to-in length is 6.20 - 0.90 = 5.30 m for each short wall. Their total measured length is 2(10.70) + 2(5.30) = 32.00 m. The PCC cross-sectional area is 0.90 x 0.18 = 0.162 m2. Multiplying 32.00 by 0.162 gives a total PCC volume of 5.184 m3.
వివరణ:
Question 5
ప్రశ్న 5
A simple rectangular foundation has centre-to-centre dimensions 10.50 m and 7.50 m, with TWO long walls and TWO short walls. The excavation trench is 1.10 m wide and 1.50 m deep, while the separate PCC bed is 0.85 m wide and 0.20 m thick. All strips are centred on the same axes and have no internal branches. What are the excavation and PCC quantities respectively?
Explanation:
The total effective length of a regular closed rectangular circuit is 2(10.50 + 7.50) = 36.00 m. At excavation level, the same total is obtained using long-wall lengths of 11.60 m and short-wall lengths of 6.40 m. Excavation volume is 36.00 x 1.10 x 1.50 = 59.40 m3. At PCC level, the long-wall and short-wall lengths are 11.35 m and 6.65 m respectively. The PCC volume is 36.00 x 0.85 x 0.20 = 6.120 m3.
వివరణ:
Question 6
ప్రశ్న 6
A rectangular building has centre-to-centre wall dimensions 11.00 m and 7.00 m, with two walls in each direction and no internal walls. Two vertically separate masonry footing courses are symmetrically centred: the lower course is 0.80 m wide and 0.35 m high, and the upper course is 0.60 m wide and 0.25 m high. What is their combined masonry volume?
Explanation:
The regular closed circuit has total effective wall length 2(11.00 + 7.00) = 36.00 m at each symmetrical footing level. The lower-course long and short lengths are 11.80 m and 6.20 m respectively. Its masonry volume is 36.00 x 0.80 x 0.35 = 10.080 m3. The upper course uses lengths 11.60 m and 6.40 m, giving volume 36.00 x 0.60 x 0.25 = 5.400 m3. Adding the separate courses gives 10.080 + 5.400 = 15.480 m3.
వివరణ:
Question 7
ప్రశ్న 7
A symmetrical rectangular foundation has centre-to-centre dimensions 9.40 m along the long walls and 6.60 m along the short walls. Three successive footing widths, from lower to upper, are 1.00 m, 0.80 m and 0.60 m. Which sequence correctly gives the long-wall out-to-out and short-wall in-to-in lengths at all three levels?
Explanation:
The centre-to-centre distances remain constant through symmetrically stepped footing courses. Long-wall out-to-out length equals 9.40 m plus the breadth of the relevant footing. Therefore the long-wall lengths are 10.40 m, 10.20 m and 10.00 m. Short-wall in-to-in length equals 6.60 m minus the corresponding breadth. The short-wall lengths are consequently 5.60 m, 5.80 m and 6.00 m.
వివరణ:
Question 8
ప్రశ్న 8
At the lowest level of a symmetrical rectangular foundation, a 1.20 m wide strip has a long-wall out-to-out length of 12.60 m and a short-wall in-to-in length of 6.40 m. The next two centred courses have widths of 0.90 m and 0.50 m. What are the corresponding long-wall and short-wall lengths at these two upper levels?
Explanation:
At the lowest level, the long-wall centre-to-centre length is 12.60 - 1.20 = 11.40 m. The short-wall centre-to-centre length is 6.40 + 1.20 = 7.60 m. At 0.90 m width, the out-to-out and in-to-in lengths are 11.40 + 0.90 = 12.30 m and 7.60 - 0.90 = 6.70 m. At 0.50 m width, they become 11.40 + 0.50 = 11.90 m and 7.60 - 0.50 = 7.10 m. The progressive reduction in footing width decreases the long-wall length and increases the short-wall length.
వివరణ:
Question 9
ప్రశ్న 9
A rectangular building has two long walls with centre-to-centre length 8.80 m each and two short walls with centre-to-centre length 5.20 m each. The plinth masonry is 0.23 m thick and 0.75 m high throughout, without openings or internal walls. What is its total volume?
Explanation:
Each long plinth wall measures 8.80 + 0.23 = 9.03 m out-to-out. Each short plinth wall measures 5.20 - 0.23 = 4.97 m in-to-in. The combined length is 2(9.03) + 2(4.97) = 28.00 m. The plinth cross-sectional area is 0.23 x 0.75 = 0.1725 m2. Hence the plinth masonry volume is 28.00 x 0.1725 = 4.830 m3.
వివరణ:
Question 10
ప్రశ్న 10
A rectangular building has long-wall and short-wall centre-to-centre dimensions of 12.00 m and 8.00 m, with two walls in each direction. The superstructure walls are 0.30 m thick and 3.00 m high. Deduct in FULL one through-wall doorway 1.00 m by 2.10 m and two through-wall windows each 1.50 m by 1.20 m, without any other adjustment. What is the net masonry volume?
Explanation:
The total payable wall length is 2(12.00 + 8.00) = 40.00 m. Gross superstructure masonry volume is 40.00 x 0.30 x 3.00 = 36.00 m3. The specified opening area is 1.00 x 2.10 + 2(1.50 x 1.20) = 5.70 m2. The full through-wall volume deduction is 5.70 x 0.30 = 1.710 m3. Therefore the net masonry volume is 36.00 - 1.710 = 34.290 m3.
వివరణ:
Question 11
ప్రశ్న 11
A rectangular building has outside dimensions 11.73 m by 7.73 m and uniform external wall thickness 0.23 m. A continuous RCC ring beam of width 0.23 m and depth 0.30 m follows the closed wall circuit. Assume no branches or overlap with other separately measured RCC items. What concrete volume is required?
Explanation:
The centre-to-centre dimensions are 11.73 - 0.23 = 11.50 m and 7.73 - 0.23 = 7.50 m. The long-wall out-to-out length is 11.50 + 0.23 = 11.73 m. The short-wall in-to-in length is 7.50 - 0.23 = 7.27 m. Their combined length is 2(11.73 + 7.27) = 38.00 m. Multiplying by the ring-beam section of 0.23 x 0.30 gives 2.622 m3 of concrete.
వివరణ:
Question 12
ప్రశ్న 12
A building has TWO continuous external long walls and TWO external short walls, with centre-to-centre dimensions of 10.00 m and 8.00 m respectively. All external walls are 0.30 m thick and 3.00 m high. TWO additional internal short partitions, each 0.20 m thick and 3.00 m high, run separately between the INSIDE FACES of the continuous external long walls. The partitions do not intersect one another. What is the combined masonry volume, assuming no openings?
Explanation:
The external closed-wall circuit has total measured length 2(10.00 + 8.00) = 36.00 m. Its masonry volume is 36.00 x 0.30 x 3.00 = 32.40 m3. Each internal partition has clear length 8.00 - 0.30 = 7.70 m because the continuous external long walls are already measured. The two partitions together contain 2 x 7.70 x 0.20 x 3.00 = 9.24 m3. The combined masonry volume is therefore 32.40 + 9.24 = 41.64 m3.
వివరణ:
Question 13
ప్రశ్న 13
A rectangular building has two continuous external long walls and two external short walls, with centre-to-centre dimensions 12.00 m and 6.00 m. One additional internal short wall extends BETWEEN THE INSIDE FACES of the continuous long walls. All walls, including the internal wall, are uniformly 0.25 m thick and 3.00 m high. What is the total masonry volume without openings?
Explanation:
The external closed-wall circuit has total effective length 2(12.00 + 6.00) = 36.00 m. The additional internal short wall extends between the inner faces of the continuous long walls. Its in-to-in length is 6.00 - 0.25 = 5.75 m. The combined payable wall length is 36.00 + 5.75 = 41.75 m. Multiplying by 0.25 m thickness and 3.00 m height gives 31.3125 m3.
వివరణ:
Question 14
ప్రశ్న 14
An excavation plan has two continuous external long trenches and two external short trenches with centre-to-centre dimensions 10.00 m and 7.00 m. One additional internal short trench extends BETWEEN THE INSIDE FACES of the continuous long trenches. Every trench is uniformly 1.20 m wide and 1.00 m deep, without other branches or overlaps. What is the total excavation volume?
Explanation:
The effective total length of the external trench circuit is 2(10.00 + 7.00) = 34.00 m. The internal short trench meets the inner faces of the two continuous long trenches. Its clear length is 7.00 - 1.20 = 5.80 m. The combined excavation length is therefore 34.00 + 5.80 = 39.80 m. Multiplication by 1.20 m width and 1.00 m depth gives 47.76 m3.
వివరణ:
Question 15
ప్రశ్న 15
A PCC foundation bed follows a rectangular layout whose external long-wall and short-wall centre-to-centre dimensions are 10.00 m and 7.00 m. It consists of two continuous external long strips, two external short strips and one additional internal short strip ending at the INSIDE FACES of the long strips. All PCC strips are 0.80 m wide and 0.20 m thick, with no other overlaps. What is the PCC quantity?
Explanation:
The external rectangular circuit has an effective measured length of 2(10.00 + 7.00) = 34.00 m. At PCC level, the internal short strip has an in-to-in length of 7.00 - 0.80 = 6.20 m. The combined PCC strip length is therefore 34.00 + 6.20 = 40.20 m. The PCC cross-sectional area is 0.80 x 0.20 = 0.16 m2. Consequently the total PCC quantity is 40.20 x 0.16 = 6.432 m3.
వివరణ:
Question 16
ప్రశ్న 16
A rectangular building has continuous external long and short wall axes with centre-to-centre dimensions of 9.00 m and 6.00 m. One internal short wall joins the continuous long walls between their inside faces. At each vertically separate course, ALL strips have the same specified breadth: lower foundation masonry 0.80 m wide and 0.30 m high; upper foundation masonry 0.60 m wide and 0.25 m high; plinth masonry 0.25 m wide and 0.60 m high. All courses are centred on the corresponding wall axes, and there are no openings. What is the combined masonry quantity?
Explanation:
The external closed circuit has a total payable length of 2(9.00 + 6.00) = 30.00 m at each course. For the lower course, the internal short-wall length is 6.00 - 0.80 = 5.20 m, giving volume 35.20 x 0.80 x 0.30 = 8.448 m3. For the upper course, the combined length is 30.00 + 5.40 = 35.40 m and volume is 35.40 x 0.60 x 0.25 = 5.310 m3. At plinth level, the combined length is 30.00 + 5.75 = 35.75 m and volume is 35.75 x 0.25 x 0.60 = 5.3625 m3. Adding the three vertically separate courses gives 8.448 + 5.310 + 5.3625 = 19.1205 m3.
వివరణ:
Question 17
ప్రశ్న 17
A rectangular foundation contains TWO long trenches of centre-to-centre length 12.00 m and TWO short trenches of centre-to-centre length 7.00 m. The excavation width is 1.00 m, with ordinary soil extending through the upper 0.80 m and rock extending through the lower 0.50 m. The material classes are separately priced, and trench sides are vertical with no extra excavation. What are the soil and rock excavation quantities?
Explanation:
The closed rectangular trench system has total measured length 2(12.00 + 7.00) = 38.00 m. Its width is 1.00 m at both excavation depths. The ordinary-soil quantity is 38.00 x 1.00 x 0.80 = 30.40 m3. The rock quantity is 38.00 x 1.00 x 0.50 = 19.00 m3. The total is 49.40 m3, but the two classifications must be recorded separately.
వివరణ:
Question 18
ప్రశ్న 18
A building has an external closed rectangular wall circuit with centre-to-centre dimensions 12.00 m and 8.00 m. Its external walls are 0.30 m thick and 2.80 m high. One additional internal partition, 0.15 m thick and 2.80 m high, extends between the INSIDE FACES of the continuous external long walls. No openings or other deductions occur. What is the combined masonry volume?
Explanation:
The external wall circuit has total effective length 2(12.00 + 8.00) = 40.00 m. Its masonry volume is 40.00 x 0.30 x 2.80 = 33.600 m3. The additional partition clear length is determined using the 0.30 m thickness of the continuous external long walls. This gives a partition length of 8.00 - 0.30 = 7.70 m and volume 7.70 x 0.15 x 2.80 = 3.234 m3. The combined masonry volume is 33.600 + 3.234 = 36.834 m3.
వివరణ:
Question 19
ప్రశ్న 19
A rectangular foundation has TWO long-wall centre-to-centre lengths of 10.00 m and TWO short-wall centre-to-centre lengths of 6.00 m. Its excavation trench is 1.10 m wide and 1.25 m deep, while a separate PCC layer is 0.90 m wide and 0.20 m thick. Both layers follow the same symmetrically centred closed circuit without branches. What is the NUMERICAL DIFFERENCE between excavation volume and PCC volume, without assuming it is entirely backfill?
Explanation:
The closed circuit has total effective length 2(10.00 + 6.00) = 32.00 m. Excavation volume is 32.00 x 1.10 x 1.25 = 44.00 m3. The separate PCC quantity is 32.00 x 0.90 x 0.20 = 5.76 m3. Their numerical difference is 44.00 - 5.76 = 38.24 m3. This difference cannot automatically be treated as backfilling because other foundation components may occupy part of the excavated space.
వివరణ:
Question 20
ప్రశ్న 20
A building has TWO long walls with centre-to-centre length 9.00 m each and TWO short walls with centre-to-centre length 6.00 m each, without internal partitions. Three vertically separate masonry portions are provided: lower foundation course 0.80 m wide by 0.35 m high, upper course 0.60 m wide by 0.25 m high, and superstructure walls 0.23 m thick by 3.00 m high. Deduct in FULL one superstructure doorway of 1.00 m by 2.10 m and one window of 1.20 m by 1.20 m, both passing through the 0.23 m wall. What is the combined net masonry volume?
Explanation:
The total effective length of each regular closed circuit is 2(9.00 + 6.00) = 30.00 m. The lower foundation-course volume is 30.00 x 0.80 x 0.35 = 8.400 m3. The upper-course volume is 30.00 x 0.60 x 0.25 = 4.500 m3, while gross superstructure masonry is 30.00 x 0.23 x 3.00 = 20.700 m3. The full opening deduction is [1.00 x 2.10 + 1.20 x 1.20] x 0.23 = 0.8142 m3. Therefore the combined net masonry is 8.400 + 4.500 + 20.700 - 0.8142 = 32.7858 m3.
వివరణ:
Question 21
ప్రశ్న 21
A regular rectangular building has centre-to-centre wall dimensions 10.00 m and 7.00 m, with two walls in each direction and no internal partitions. Excavation is 1.00 m wide and 1.10 m deep at Rs 850/m3; a separate PCC bed is 0.80 m wide and 0.15 m thick at Rs 6,500/m3; and superstructure masonry is 0.30 m thick and 2.80 m high at Rs 6,000/m3. No openings or other allowances apply. What is the combined estimated cost?
Explanation:
The total payable length at each symmetrical closed-circuit layer is 2(10.00 + 7.00) = 34.00 m. Excavation volume is 34.00 x 1.00 x 1.10 = 37.40 m3, costing Rs 31,790. PCC volume is 34.00 x 0.80 x 0.15 = 4.08 m3, costing Rs 26,520. Superstructure masonry is 34.00 x 0.30 x 2.80 = 28.56 m3, costing Rs 1,71,360. The total estimated cost is Rs 31,790 + Rs 26,520 + Rs 1,71,360 = Rs 2,29,670.
వివరణ:
Question 22
ప్రశ్న 22
A rectangular building has continuous external long and short walls with centre-to-centre dimensions 11.00 m and 7.00 m. All external walls are 0.30 m thick and 3.00 m high. One internal short partition, 0.20 m thick and 3.00 m high, terminates against the INSIDE FACES of the continuous external long walls. There are no openings. What is the combined external-wall and partition masonry volume?
Explanation:
The closed external-wall circuit has measured length 2(11.00 + 7.00) = 36.00 m. The external masonry volume is 36.00 x 0.30 x 3.00 = 32.40 m3. The additional partition runs between the inside faces of the continuous external long walls. Its net length is 7.00 - 0.30 = 6.70 m, giving volume 6.70 x 0.20 x 3.00 = 4.02 m3. Hence the combined masonry volume is 32.40 + 4.02 = 36.42 m3.
వివరణ:
Question 23
ప్రశ్న 23
A rectangular foundation has two long walls with centre-to-centre length 10.00 m and two short walls with centre-to-centre length 6.00 m. The symmetrical excavation trench is 1.20 m wide and 1.00 m deep. A vertically separate upper masonry footing course is 0.60 m wide and 0.35 m high, centred on the same axes. No internal branches or deductions occur. What are the excavation and upper-footing masonry quantities?
Explanation:
The centre-to-centre dimensions produce a closed-circuit effective length of 2(10.00 + 6.00) = 32.00 m. At excavation level, each long trench is 11.20 m and each short trench is 4.80 m. Excavation quantity is therefore 32.00 x 1.20 x 1.00 = 38.40 m3. At the narrower footing level, the respective lengths are 10.60 m and 5.40 m. Their total is again 32.00 m, giving footing masonry volume 32.00 x 0.60 x 0.35 = 6.72 m3.
వివరణ:
Question 24
ప్రశ్న 24
In a closed rectangular foundation with TWO long and TWO short walls, the centre-to-centre dimensions remain unchanged. The symmetrical strip breadth decreases from 1.20 m at a lower level to 0.80 m at an upper level. What is the change in the SUM of the two long-wall out-to-out lengths and in the SUM of the two short-wall in-to-in lengths?
Explanation:
Each long-wall out-to-out length equals its centre-to-centre length plus the strip breadth. Reducing the breadth by 1.20 - 0.80 = 0.40 m decreases each long-wall length by 0.40 m. For two long walls, the combined decrease is 0.80 m. Each short-wall in-to-in length increases by 0.40 m because its length is obtained by subtracting the breadth. Therefore the two short walls gain 0.80 m in total, and the combined payable length of the closed circuit remains unchanged.
వివరణ:
Question 25
ప్రశ్న 25
A rectangular building has two continuous external long walls and two external short walls, with centre-to-centre dimensions 11.00 m and 7.00 m. TWO additional internal short walls, separated from one another, extend BETWEEN THE INSIDE FACES of the continuous long walls. At each vertically separate course, all strips have the same specified breadth: lower foundation masonry 0.75 m wide and 0.30 m high; plinth masonry 0.30 m wide and 0.60 m high; and superstructure masonry 0.23 m thick and 3.00 m high. ONLY the superstructure has full through-wall deductions for one doorway 1.00 m by 2.10 m and two windows each 1.20 m by 1.20 m. What is the combined net masonry volume before rounding?
Explanation:
The closed external-wall circuit has an effective measured length of 2(11.00 + 7.00) = 36.00 m. At lower foundation level, each internal short wall measures 7.00 - 0.75 = 6.25 m, so the total length is 48.50 m and volume is 48.50 x 0.75 x 0.30 = 10.9125 m3. At plinth level, the total length is 36.00 + 2(7.00 - 0.30) = 49.40 m and volume is 49.40 x 0.30 x 0.60 = 8.8920 m3. At superstructure level, the total length is 36.00 + 2(7.00 - 0.23) = 49.54 m, giving gross masonry of 49.54 x 0.23 x 3.00 = 34.1826 m3. The specified openings require deduction of [1.00 x 2.10 + 2(1.20 x 1.20)] x 0.23 = 1.1454 m3, so the combined net masonry is 10.9125 + 8.8920 + 34.1826 - 1.1454 = 52.8417 m3.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: C. 14.10 m and 8.30 m. సమాధానం: C.
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Question 2 ప్రశ్న 2Answer: D. Excavation: 12.80 m and 6.20 m; PCC: 12.30 m and 6.70 m. సమాధానం: D.
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Question 3 ప్రశ్న 3Answer: B. 64.68 m3. సమాధానం: B.
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Question 4 ప్రశ్న 4Answer: A. 5.184 m3. సమాధానం: A.
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Question 5 ప్రశ్న 5Answer: C. Excavation 59.40 m3; PCC 6.120 m3. సమాధానం: C.
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Question 6 ప్రశ్న 6Answer: D. 15.480 m3. సమాధానం: D.
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Question 7 ప్రశ్న 7Answer: B. Long walls: 10.40, 10.20, 10.00 m; short walls: 5.60, 5.80, 6.00 m. సమాధానం: B.
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Question 8 ప్రశ్న 8Answer: A. 0.90 m course: 12.30 m and 6.70 m; 0.50 m course: 11.90 m and 7.10 m. సమాధానం: A.
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Question 9 ప్రశ్న 9Answer: C. 4.83 m3. సమాధానం: C.
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Question 10 ప్రశ్న 10Answer: D. 34.29 m3. సమాధానం: D.
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Question 11 ప్రశ్న 11Answer: B. 2.622 m3. సమాధానం: B.
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Question 12 ప్రశ్న 12Answer: A. 41.64 m3. సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: D. 31.3125 m3. సమాధానం: D.
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Question 14 ప్రశ్న 14Answer: B. 47.76 m3. సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: C. 6.432 m3. సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: A. 19.1205 m3. సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: D. Soil 30.40 m3; rock 19.00 m3. సమాధానం: D.
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Question 18 ప్రశ్న 18Answer: B. 36.834 m3. సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: C. 38.24 m3. సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: A. 32.7858 m3. సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: D. Rs 2,29,670. సమాధానం: D.
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Question 22 ప్రశ్న 22Answer: B. 36.42 m3. సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. Excavation 38.40 m3; footing masonry 6.72 m3. సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: A. The combined long-wall length decreases by 0.80 m, while the combined short-wall length increases by 0.80 m. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: D. 52.8417 m3. సమాధానం: D.
