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Question 1
ప్రశ్న 1
In the conventional long-wall and short-wall method for a rectangular building with uniform strip breadth b and known centre-to-centre wall lengths, which pair of expressions is correct?
Explanation:
In this method, the long wall is booked out-to-out and the short wall is booked in-to-in. The out-to-out length includes half the strip breadth beyond the centreline at each end. These halves add to one complete breadth for a long wall. The in-to-in short-wall length excludes the corresponding half-breadths at both ends. The formulas therefore apply to the particular strip breadth used at that level.
వివరణ:
Question 2
ప్రశ్న 2
A rectangular building has external dimensions 12.30 m along the long direction and 8.30 m along the short direction, with uniform external wall thickness 0.30 m. For superstructure masonry, what are the long-wall out-to-out and short-wall in-to-in lengths, respectively?
Explanation:
The centre-to-centre distances are obtained by subtracting one wall thickness from each external dimension. The long-wall centre-to-centre length is 12.30 - 0.30 = 12.00 m. Adding the wall breadth gives its out-to-out length of 12.30 m. The short-wall centre-to-centre distance is 8.30 - 0.30 = 8.00 m. Subtracting the wall breadth gives the short-wall in-to-in length of 7.70 m.
వివరణ:
Question 3
ప్రశ్న 3
The centre-to-centre length of a designated long wall is 9.00 m, and that of a designated short wall is 6.00 m. Both are uniform 0.40 m wide strips bounded by the same outer wall lines. What are their respective payable lengths under the standard long-wall and short-wall convention?
Explanation:
A long wall is measured from outside face to outside face of the relevant strip. Its out-to-out length is 9.00 + 0.40 = 9.40 m. A short wall is measured between the inside faces of the corresponding continuous long walls. Its in-to-in length is 6.00 - 0.40 = 5.60 m. The same specified width must be used consistently in these two length corrections.
వివరణ:
Question 4
ప్రశ్న 4
A simple rectangular closed building has TWO long walls with centre-to-centre length 10.00 m each and TWO short walls with centre-to-centre length 7.00 m each. All walls have uniform thickness 0.30 m and height 3.00 m, with no openings or cross walls. What masonry volume results from the long-wall and short-wall method?
Explanation:
Each long wall has out-to-out length 10.00 + 0.30 = 10.30 m. Each short wall has in-to-in length 7.00 - 0.30 = 6.70 m. The combined measured length is 2(10.30) + 2(6.70) = 34.00 m. The wall cross-sectional area is 0.30 x 3.00 = 0.90 m2. Multiplication gives 34.00 x 0.90 = 30.60 m3 of masonry.
వివరణ:
Question 5
ప్రశ్న 5
For a symmetrical rectangular foundation, the long-wall and short-wall centre-to-centre distances remain 10.00 m and 7.00 m at all levels. Excavation strips are 1.20 m wide and an upper footing course is 0.90 m wide. What are the long-wall out-to-out and short-wall in-to-in lengths at the TWO levels, respectively?
Explanation:
The centres of symmetrically stepped foundation strips remain aligned with the wall axes. At excavation level, the long-wall length is 10.00 + 1.20 = 11.20 m. The corresponding short-wall length is 7.00 - 1.20 = 5.80 m. At the narrower upper course, the lengths are 10.00 + 0.90 = 10.90 m and 7.00 - 0.90 = 6.10 m. Hence the long-wall length decreases while the short-wall length increases as the strip breadth narrows.
వివరణ:
Question 6
ప్రశ్న 6
A rectangular foundation layout contains TWO long trenches whose centre-to-centre length is 9.00 m and TWO short trenches whose centre-to-centre length is 6.00 m. All trenches are uniformly 0.90 m wide and 1.20 m deep, with no additional branches. What is the net in-situ excavation quantity?
Explanation:
Each long trench measures 9.00 + 0.90 = 9.90 m out-to-out. Each short trench measures 6.00 - 0.90 = 5.10 m in-to-in. The sum of payable lengths is 2(9.90) + 2(5.10) = 30.00 m. Its cross-sectional area is 0.90 x 1.20 = 1.08 m2. The in-situ excavation volume is 30.00 x 1.08 = 32.40 m3.
వివరణ:
Question 7
ప్రశ్న 7
A closed rectangular foundation has TWO long strips with centre-to-centre length 10.00 m and TWO short strips with centre-to-centre length 7.00 m. Its centred PCC bed is 0.80 m wide and 0.15 m thick throughout. What is the PCC volume with no internal branches?
Explanation:
At PCC level the long-wall out-to-out length is 10.00 + 0.80 = 10.80 m. The short-wall in-to-in length is 7.00 - 0.80 = 6.20 m. The total effective length is 2(10.80) + 2(6.20) = 34.00 m. The bed cross-sectional area is 0.80 x 0.15 = 0.12 m2. Therefore the concrete volume is 34.00 x 0.12 = 4.08 m3.
వివరణ:
Question 8
ప్రశ్న 8
A rectangular building has centre-to-centre dimensions 9.00 m by 6.00 m and no internal walls. Two centred footing-masonry courses are provided: a lower course 0.75 m wide and 0.30 m high, and an upper course 0.55 m wide and 0.25 m high. What is the combined footing-masonry volume?
Explanation:
For a closed rectangular circuit the corrected total lengths of long and short walls sum to 2(9.00 + 6.00) = 30.00 m at either uniform-width course. The lower-course volume is 30.00 x 0.75 x 0.30 = 6.750 m3. The upper-course volume is 30.00 x 0.55 x 0.25 = 4.125 m3. The courses lie at separate vertical levels, so both volumes are included. Their combined volume equals 6.750 + 4.125 = 10.875 m3.
వివరణ:
Question 9
ప్రశ్న 9
A rectangular closed plinth-wall layout has centre-to-centre dimensions 11.00 m along the long direction and 7.00 m along the short direction. Each wall is 0.30 m thick and the plinth masonry height is 0.60 m, without openings. What is the masonry volume?
Explanation:
The long-wall out-to-out length is 11.00 + 0.30 = 11.30 m. The short-wall in-to-in length is 7.00 - 0.30 = 6.70 m. With two walls of each type, their total length is 2(11.30 + 6.70) = 36.00 m. The plinth-wall cross-sectional area is 0.30 x 0.60 = 0.18 m2. Hence the masonry volume is 36.00 x 0.18 = 6.48 m3.
వివరణ:
Question 10
ప్రశ్న 10
A building has outer dimensions 10.23 m along its designated long walls and 7.23 m along its designated short walls. The external superstructure walls are uniformly 0.23 m thick. What are the LONG-wall out-to-out and SHORT-wall in-to-in dimensions?
Explanation:
The out-to-out length of an external long wall is its full exterior dimension of 10.23 m. The centre-to-centre long-wall length is 10.23 - 0.23 = 10.00 m. The centre-to-centre distance between the transverse main walls is 7.23 - 0.23 = 7.00 m. The in-to-in short-wall length is 7.00 - 0.23 = 6.77 m. These are the two lengths used under the stated wall-by-wall convention.
వివరణ:
Question 11
ప్రశ్న 11
In a symmetrically centred stepped footing, the long-wall and short-wall centre-to-centre dimensions are 11.00 m and 6.00 m. The widths of successive courses from lower to upper are 1.00 m, 0.80 m and 0.60 m. Which sequence of long-wall out-to-out and short-wall in-to-in lengths is correct?
Explanation:
The geometrical centre-to-centre lengths remain unchanged because the widening is symmetrical. Long-wall out-to-out lengths equal 11.00 m plus the breadth of the relevant course. They are therefore 12.00 m, 11.80 m and 11.60 m. Short-wall in-to-in lengths equal 6.00 m minus the corresponding breadth. They are therefore 5.00 m, 5.20 m and 5.40 m.
వివరణ:
Question 12
ప్రశ్న 12
Consider the following statements for a simple uniform-width rectangular layout: (1) A long-wall out-to-out length equals its centre-to-centre length plus one work-layer breadth. (2) A short-wall in-to-in length equals its centre-to-centre length minus one work-layer breadth. (3) In symmetrically stepped foundations, the centre-to-centre wall-axis spacing must change whenever a footing becomes narrower. Which statements are correct?
Explanation:
The long-wall formula adds half a breadth at each end of its centre-to-centre length. The short-wall formula deducts the half-breadths at its two junctions. Both formulas use the breadth of the particular layer being measured. Symmetrical footing offsets keep the geometric wall axes fixed despite changing strip widths. Therefore the first two statements are true, while the third is false.
వివరణ:
Question 13
ప్రశ్న 13
A closed rectangular building has wall centre-to-centre dimensions 10.00 m and 7.00 m, with 0.23 m thick superstructure masonry 3.00 m high. There are no internal walls. Deduct in FULL one through-wall door 1.00 m by 2.10 m and two through-wall windows each 1.20 m by 1.50 m, without any other adjustment. What is the net masonry volume?
Explanation:
The two long-wall lengths together with the two short-wall lengths total 2(10.00 + 7.00) = 34.00 m. Gross masonry volume is 34.00 x 0.23 x 3.00 = 23.460 m3. The stated openings have a combined face area of 2.10 + 2(1.20 x 1.50) = 5.70 m2. The expressly required through-wall deduction is 5.70 x 0.23 = 1.311 m3. Subtracting this gives a net masonry volume of 22.149 m3.
వివరణ:
Question 14
ప్రశ్న 14
A 0.20 m thick, 3.00 m high internal partition is booked from the centreline of one continuous 0.30 m thick main wall to that of another parallel main wall. The centre-to-centre distance is 5.00 m, and BOTH continuous main walls have already been measured in full. What additional partition masonry volume is needed?
Explanation:
The partition terminates at the centreline of a previously measured main wall at each end. Each overlap extends half the main-wall thickness, or 0.15 m. The additional in-to-in length is 5.00 - 0.15 - 0.15 = 4.70 m. The partition cross-sectional area is 0.20 x 3.00 = 0.60 m2. Its additional masonry volume is consequently 4.70 x 0.60 = 2.820 m3.
వివరణ:
Question 15
ప్రశ్న 15
A centred foundation course becomes 0.30 m NARROWER than the course immediately below it, with 0.15 m reduction on EACH side. If the lower course has a long-wall out-to-out length of 12.00 m and a short-wall in-to-in length of 5.00 m, what are the respective upper-course lengths?
Explanation:
The footing is centred, so the axis spacing remains unchanged between courses. Narrowing the breadth by 0.30 m reduces the long-wall external projection by 0.15 m at each end. Its out-to-out length therefore falls from 12.00 m to 11.70 m. The available clear in-to-in span increases by 0.15 m at each side. The short-wall length consequently rises from 5.00 m to 5.30 m.
వివరణ:
Question 16
ప్రశ్న 16
A rectangular foundation has TWO long walls whose centre-to-centre length is 8.00 m and TWO short walls whose centre-to-centre length is 5.00 m. Excavation strips are 1.00 m wide and 1.00 m deep. A separate PCC bed along the same axes is 0.80 m wide and 0.20 m thick. There are no branches or extra excavations. What are the excavation and PCC quantities?
Explanation:
The excavation length total is 2(8.00 + 1.00) + 2(5.00 - 1.00) = 26.00 m. Excavation volume is 26.00 x 1.00 x 1.00 = 26.00 m3. For the PCC layer, long and short wall lengths total 2(8.00 + 0.80) + 2(5.00 - 0.80) = 26.00 m. The PCC cross-sectional area is 0.80 x 0.20 = 0.16 m2. The PCC quantity is therefore 26.00 x 0.16 = 4.16 m3.
వివరణ:
Question 17
ప్రశ్న 17
A uniform closed rectangular foundation layer has two long walls with centre-to-centre length 11.00 m each and two short walls with centre-to-centre length 7.00 m each. The strip breadth is 0.60 m and its depth is 0.40 m. What volume results from the long-wall and short-wall method?
Explanation:
Each long-wall out-to-out length is 11.00 + 0.60 = 11.60 m. Each short-wall in-to-in length is 7.00 - 0.60 = 6.40 m. Their sum is 2(11.60) + 2(6.40) = 36.00 m. The cross-sectional area is 0.60 x 0.40 = 0.24 m2. The resulting volume is 36.00 x 0.24 = 8.64 m3.
వివరణ:
Question 18
ప్రశ్న 18
In an irregular foundation plan, one continuous strip is eccentrically widened on only one side, while nearby branch walls have different thicknesses. What is the safest way to apply the long-wall and short-wall method?
Explanation:
The simple plus-or-minus one-breadth expressions assume a regular centred arrangement with compatible widths at the junctions. An eccentric widening changes some actual face locations without necessarily shifting all other boundaries. Unequal adjoining wall widths can alter the correct short-wall clear distance. Measuring the relevant faces directly or using a carefully reconciled hybrid method avoids double counting. Each foundation course should be checked against its own plan and section geometry.
వివరణ:
Question 19
ప్రశ్న 19
A closed rectangular foundation has long-wall and short-wall centre-to-centre dimensions of 10.00 m and 6.00 m, with two walls in each direction. Excavation is 1.00 m wide and 1.00 m deep at Rs 800/m3. A separate PCC bed is 0.80 m wide and 0.20 m thick at Rs 6,000/m3. There are no branches or other allowances. What is the combined excavation and PCC amount?
Explanation:
For the closed rectangle, the combined payable wall length at either uniform-width layer is 2(10.00 + 6.00) = 32.00 m. Excavation volume is 32.00 x 1.00 x 1.00 = 32.00 m3, costing Rs 25,600. PCC volume is 32.00 x 0.80 x 0.20 = 5.12 m3. The PCC amount is 5.12 x Rs 6,000 = Rs 30,720. Adding these two costs gives Rs 56,320.
వివరణ:
Question 20
ప్రశ్న 20
A long wall changes thickness midway along its length, and its adjoining short walls terminate against different wall faces. Which estimating practice is correct?
Explanation:
A change in wall thickness alters the footprint of the work being measured. It can also alter the clear dimensions at the junctions with transverse walls. A single uniform-width correction may no longer represent the true geometry. Subdividing the work into consistent sections allows lengths, widths and depths to be checked individually. The resulting item quantities can then be combined without duplicating intersection volumes.
వివరణ:
Question 21
ప్రశ్న 21
Only the TWO long-wall foundation strips of a rectangular building are being measured in this item. Each has centre-to-centre length 13.00 m, breadth 0.50 m and depth 0.40 m; the short-wall strips will be measured separately. What is the excavation volume for these two long strips alone?
Explanation:
Each of the two long walls requires the out-to-out length. Adding the strip breadth gives 13.00 + 0.50 = 13.50 m per wall. The two-wall combined length is 27.00 m. The rectangular excavation cross-section is 0.50 x 0.40 = 0.20 m2. Multiplying 27.00 by 0.20 gives 5.40 m3 for the two long strips alone.
వివరణ:
Question 22
ప్రశ్న 22
Only TWO short-wall masonry strips are to be measured, each between two previously accounted continuous long-wall strips. The short-wall centre-to-centre length is 8.00 m, the relevant uniform breadth is 0.40 m and height is 0.60 m. What is their combined in-to-in masonry volume?
Explanation:
The in-to-in length of each short wall is its centre-to-centre distance less one full strip breadth. Hence each length is 8.00 - 0.40 = 7.60 m. Both short walls have a combined length of 15.20 m. The section area is 0.40 x 0.60 = 0.24 m2. Their combined masonry volume is 15.20 x 0.24 = 3.648 m3.
వివరణ:
Question 23
ప్రశ్న 23
A rectangular foundation has TWO long strips of centre-to-centre length 12.00 m and TWO short strips of centre-to-centre length 8.00 m. The trench breadth is 1.00 m and depth 1.20 m, with no other branches. An estimator mistakenly uses the 0.23 m superstructure wall thickness to determine trench lengths. What is the CORRECT trench excavation volume?
Explanation:
The trench length adjustments must use the excavation breadth, which is 1.00 m. Each long trench is 12.00 + 1.00 = 13.00 m out-to-out. Each short trench is 8.00 - 1.00 = 7.00 m in-to-in. The combined trench length is 2(13.00) + 2(7.00) = 40.00 m. Multiplying by 1.00 m breadth and 1.20 m depth gives 48.00 m3.
వివరణ:
Question 24
ప్రశ్న 24
The long-wall and short-wall method and the centreline method are applied correctly to the SAME regular rectangular foundation layer, with matching item boundaries and no omitted or duplicate intersections. Which conclusion follows?
Explanation:
Both methods are alternative ways to account for the same physical construction geometry. The long-wall and short-wall method allocates the corner regions through out-to-out and in-to-in dimensions. The centreline method uses effective axis lengths and the work-section breadth. If all junctions and item boundaries are handled consistently, neither method creates extra material volume. A difference in results indicates that the geometry or measurement assumptions should be rechecked.
వివరణ:
Question 25
ప్రశ్న 25
A rectangular building has TWO long walls of centre-to-centre length 9.00 m each and TWO short walls of centre-to-centre length 6.00 m each, with no internal walls. A centred foundation-masonry course is 0.60 m wide and 0.30 m high. Above it, a superstructure wall is 0.23 m thick and 3.00 m high. Deduct in FULL one through-wall door 1.00 m by 2.10 m and two through-wall windows 1.20 m by 1.50 m each from SUPERSTRUCTURE MASONRY ONLY, with no other deductions. What is the combined net masonry volume of these two separate levels?
Explanation:
The total payable length for each regular closed rectangular course is 2(9.00 + 6.00) = 30.00 m. The foundation-masonry volume is 30.00 x 0.60 x 0.30 = 5.400 m3. Gross superstructure masonry is 30.00 x 0.23 x 3.00 = 20.700 m3. The specified openings have area 2.10 + 2(1.20 x 1.50) = 5.70 m2 and deduct 5.70 x 0.23 = 1.311 m3. The combined net masonry volume is 5.400 + 20.700 - 1.311 = 24.789 m3.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Long-wall out-to-out length = centre-to-centre length + b; short-wall in-to-in length = centre-to-centre length - b. సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: D. 12.30 m and 7.70 m. సమాధానం: D.
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Question 3 ప్రశ్న 3Answer: A. 9.40 m and 5.60 m. సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: C. 30.60 m3. సమాధానం: C.
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Question 5 ప్రశ్న 5Answer: D. Excavation 11.20 m and 5.80 m; upper footing 10.90 m and 6.10 m. సమాధానం: D.
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Question 6 ప్రశ్న 6Answer: B. 32.40 m3. సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: C. 4.08 m3. సమాధానం: C.
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Question 8 ప్రశ్న 8Answer: A. 10.875 m3. సమాధానం: A.
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Question 9 ప్రశ్న 9Answer: D. 6.48 m3. సమాధానం: D.
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Question 10 ప్రశ్న 10Answer: B. 10.23 m and 6.77 m. సమాధానం: B.
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Question 11 ప్రశ్న 11Answer: C. Long walls: 12.00, 11.80, 11.60 m; short walls: 5.00, 5.20, 5.40 m. సమాధానం: C.
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Question 12 ప్రశ్న 12Answer: A. 1 and 2 only. సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: B. 22.149 m3. సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: D. 2.820 m3. సమాధానం: D.
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Question 15 ప్రశ్న 15Answer: C. 11.70 m and 5.30 m. సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: A. 26.00 m3 and 4.16 m3. సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: D. 8.64 m3. సమాధానం: D.
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Question 18 ప్రశ్న 18Answer: B. Determine the actual out-to-out and in-to-in boundaries for each affected strip and course, with overlap corrections reflecting unequal widths and eccentricity. సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: C. Rs 56,320. సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: A. Split the work at the change, determine the actual out-to-out and in-to-in dimensions for each applicable portion, and price separately where descriptions differ. సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: D. 5.40 m3. సమాధానం: D.
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Question 22 ప్రశ్న 22Answer: B. 3.648 m3. సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. 48.00 m3. సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: A. Both methods should yield the same net measurable quantity because they describe the same physical work. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: D. 24.789 m3. సమాధానం: D.
