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Question 1
ప్రశ్న 1
In a two-dimensional potential-flow problem, what constitutes a flow net?
Explanation:
A flow net for two-dimensional potential flow consists of two families of curves. One family contains streamlines, which are everywhere tangent to the local velocity vector. The other family contains equipotential lines, along which the velocity potential has a constant value. For an incompressible and irrotational potential flow, these two families intersect orthogonally at regular points. Therefore Option B correctly identifies the fundamental components of a flow net.
వివరణ:
Question 2
ప్రశ్న 2
Which combination of conditions most directly supports the classical construction of an orthogonal flow net from a stream function ψ and velocity potential φ in a two-dimensional region?
Explanation:
A two-dimensional incompressible flow permits introduction of the conventional stream function ψ. An irrotational flow permits introduction of a velocity potential φ, subject to the usual local or global existence conditions. When the flow is both incompressible and irrotational, both functions satisfy Laplace's equation in a regular region. Their constant-value curves form mutually orthogonal families and can therefore be represented as a classical potential-flow net. Hence Option B is correct.
వివరణ:
Question 3
ప్రశ్న 3
Why do a streamline and an equipotential line intersect at right angles at an ordinary point of a two-dimensional potential flow where the velocity is nonzero?
Explanation:
The velocity vector is tangent to a streamline by definition. With the convention V = ∇φ, the velocity vector is normal to a line on which φ is constant. Therefore the tangent to the streamline is perpendicular to the tangent to the equipotential line. This orthogonality applies at regular points where the velocity direction is well defined. Consequently, Option B is correct.
వివరణ:
Question 4
ప్రశ్న 4
Which statement concerning intersections within a regular flow net is correct?
Explanation:
A regular velocity field has a unique velocity direction at an ordinary point, so two distinct streamlines cannot cross there with different tangents. Distinct equipotential contours corresponding to different values of the same scalar potential also cannot pass through the same point because φ cannot simultaneously possess two different values. Streamlines do cross equipotential lines, but the intersection is orthogonal in potential flow. Singular and stagnation points require separate mathematical care and do not invalidate the regular-point rule. Therefore Option C is correct.
వివరణ:
Question 5
ప్రశ్న 5
What is meant by a curvilinear square in a well-constructed flow net?
Explanation:
A flow-net cell is bounded by two neighbouring streamlines and two neighbouring equipotential lines. Because the two curve families are orthogonal, adjacent sides meet approximately at right angles in a carefully constructed net. The net is refined so that the local dimensions of a cell in the two orthogonal directions are approximately equal, giving the appearance of a distorted or curvilinear square. The boundaries need not be straight and the cell need not be an exact Euclidean square. Therefore Option B correctly describes a curvilinear square.
వివరణ:
Question 6
ప్రశ్న 6
Which procedure is most appropriate when constructing a flow net manually for a known two-dimensional potential-flow region?
Explanation:
Flow-net construction begins with the physical and mathematical boundary conditions of the problem. Streamlines and equipotential lines are then sketched in a manner consistent with those boundaries. The two families should cross orthogonally in a potential-flow region. The network is normally adjusted iteratively until the curves are smooth and the cells have approximately curvilinear-square proportions. Hence Option B describes the appropriate construction procedure.
వివరణ:
Question 7
ప్రశ్న 7
Adjacent equipotential lines in a flow net are drawn for equal increments of velocity potential Δφ. What does a smaller normal spacing between two such adjacent equipotential lines generally indicate?
Explanation:
Velocity magnitude in potential flow is related to the spatial gradient of the velocity potential. Between closely spaced equipotential lines having the same potential increment, a smaller normal distance corresponds to a larger potential gradient. For a sufficiently small spacing, the local magnitude can be estimated by V ≈ Δφ/Δn. Thus crowding of equal-increment equipotential lines indicates a region of comparatively high velocity. Therefore Option B is correct.
వివరణ:
Question 8
ప్రశ్న 8
In a small region of a potential-flow net, adjacent equipotential lines differ by Δφ = 0.60 m²/s and their normal separation is approximately 0.15 m. What is the approximate local velocity magnitude?
Explanation:
The velocity magnitude is the magnitude of the spatial gradient of the velocity potential. For a sufficiently small cell, the normal gradient can be approximated by V ≈ Δφ/Δn. Substituting the given values gives V ≈ 0.60/0.15 = 4.0 m/s. The units are consistent because m²/s divided by m gives m/s. Therefore Option C is correct.
వివరణ:
Question 9
ప్రశ్న 9
Two regions of the same flow net have equal potential increments of 0.50 m²/s between adjacent equipotential lines. The normal spacings are 0.10 m in Region A and 0.25 m in Region B. Approximately what is the ratio VA/VB?
Explanation:
For equal potential increments, the local speed varies approximately inversely with the normal spacing between equipotential lines. Region A therefore has VA ≈ 0.50/0.10 = 5.0 m/s. Region B has VB ≈ 0.50/0.25 = 2.0 m/s. Their ratio is VA/VB = 5/2 = 2.5. Hence Option C is correct.
వివరణ:
Question 10
ప్రశ్న 10
In a two-dimensional incompressible flow, two streamlines have stream-function values ψ1 = 0.75 m²/s and ψ2 = 3.25 m²/s. What is the magnitude of discharge per unit depth between the two streamlines?
Explanation:
The difference in stream-function values between two streamlines equals the volumetric flow rate per unit depth between them. The magnitude is therefore |ψ2 - ψ1|. Here this gives |3.25 - 0.75| = 2.50 m²/s. The sign of the difference would depend on orientation and the adopted stream-function convention, but the requested discharge magnitude is positive. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
A flow net contains five equal flow channels, and the stream-function increment across each channel is 1.20 m²/s. What is the total volumetric discharge per unit depth represented by the five channels?
Explanation:
Each flow channel is bounded by two adjacent streamlines. A stream-function difference of 1.20 m²/s therefore represents a discharge of 1.20 m²/s per unit depth through each channel. With five equal channels, the total discharge per unit depth is 5 × 1.20 = 6.00 m²/s. This calculation uses the direct physical interpretation of the stream function in two-dimensional incompressible flow. Hence Option C is correct.
వివరణ:
Question 12
ప్రశ్న 12
A two-dimensional incompressible flow carries a total discharge per unit depth of 9.0 m²/s through six flow channels that have been selected to carry equal discharge. What stream-function increment separates each adjacent pair of streamlines?
Explanation:
If the six flow channels carry equal discharge, each carries one-sixth of the total flow per unit depth. The discharge in one channel is therefore 9.0/6 = 1.50 m²/s. In two-dimensional incompressible flow, this channel discharge equals the magnitude of the stream-function difference between its bounding streamlines. Thus adjacent streamlines should differ by 1.50 m²/s. Therefore Option B is correct.
వివరణ:
Question 13
ప్రశ్న 13
The velocity-potential difference between two boundary equipotentials is 24 m²/s. If the flow net divides this range into eight equal potential intervals, what is the potential increment between successive equipotential lines?
Explanation:
Equal potential intervals divide the total velocity-potential difference uniformly. The increment is therefore Δφ = 24/8 m²/s. This gives Δφ = 3 m²/s between successive equipotential lines. The value is a potential difference and should not be confused directly with velocity, which also requires division by an appropriate spatial distance. Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
A flow net is bounded by five streamline curves, including the two outer boundary streamlines, and by seven equipotential curves, including the two terminal equipotential boundaries. How many flow channels and potential intervals does the net contain?
Explanation:
A flow channel is the region between two adjacent streamline curves. Therefore five streamline curves create four spaces, or four flow channels. Similarly, a potential interval is the region between two adjacent equipotential curves. Seven equipotential curves therefore create six potential intervals. Hence Option B gives the correct counts.
వివరణ:
Question 15
ప్రశ్న 15
For a uniform potential flow of speed U in the positive x-direction, which flow-net pattern is expected when equal increments of φ and ψ are used?
Explanation:
For uniform flow in the positive x-direction, one may write φ = Ux and ψ = Uy under the convention used in this unit. Constant ψ therefore gives horizontal straight streamlines. Constant φ gives vertical straight equipotential lines. The two families are parallel within themselves and perpendicular to the other family. Thus Option B correctly describes the uniform-flow net.
వివరణ:
Question 16
ప్రశ్న 16
Away from its singular origin, a two-dimensional point-source potential flow has velocity directed radially outward. What flow-net geometry is expected?
Explanation:
A point source produces radial velocity directed away from the source. Consequently, its streamlines are rays of constant angular coordinate extending outward from the origin. The velocity potential of a two-dimensional source varies logarithmically with radius, so constant-potential curves have constant radius. Those curves are concentric circles around the source. Therefore Option B correctly describes the orthogonal flow-net pattern away from the singular origin.
వివరణ:
Question 17
ప్రశ్న 17
In an inviscid potential-flow model around a stationary impermeable solid boundary satisfying the no-penetration condition, how is the boundary represented in the flow net?
Explanation:
The no-penetration boundary condition requires the velocity component normal to a stationary impermeable surface to be zero. The velocity is therefore tangent to the surface in the potential-flow model. A curve everywhere tangent to the local velocity direction is a streamline. Hence the solid boundary can be represented by a constant-stream-function line. Therefore Option A is correct.
వివరణ:
Question 18
ప్రశ్న 18
At a regular point of a two-dimensional potential-flow net, which statement correctly relates the velocity vector to the two families of curves?
Explanation:
A streamline is defined so that its tangent has the direction of the local velocity vector. An equipotential line is a level curve of φ. Because V = ∇φ, the velocity is normal to the level curve of the potential. These two properties are mutually consistent with the orthogonality of the flow-net families. Hence Option B is correct.
వివరణ:
Question 19
ప్రశ్న 19
What is the effect on a flow net of adding an arbitrary constant C1 to the velocity potential φ and another constant C2 to the stream function ψ?
Explanation:
Velocity components depend on spatial derivatives of φ and ψ rather than on their absolute numerical values. Adding a constant to either scalar function therefore does not alter any derivative. The physical velocity field consequently remains unchanged. The same geometrical level curves remain present, although their assigned numerical constant values are shifted. Therefore Option C is correct.
వివరణ:
Question 20
ప్రశ్న 20
For a potential flow described by φ = x² - y² and ψ = 2xy, consider the point (x,y) = (2,1). What are the slopes of the streamline and equipotential line through that point?
Explanation:
The velocity components are u = ∂φ/∂x = 2x and v = ∂φ/∂y = -2y. At (2,1), u = 4 and v = -2, so the streamline slope is dy/dx = v/u = -0.5. For an equipotential, dφ = 2x dx - 2y dy = 0, giving dy/dx = x/y = 2 at the stated point. The product of the two slopes is -1, confirming their orthogonal intersection. Therefore Option A is correct.
వివరణ:
Question 21
ప్రశ్న 21
For φ = x² - y² and ψ = 2xy, which pair gives the equipotential and streamline passing through the point (2,1)?
Explanation:
At the point (2,1), the velocity potential has the value φ = 2² - 1² = 3. Thus the equipotential through that point is x² - y² = 3. The stream-function value there is ψ = 2(2)(1) = 4. Hence 2xy = 4, which is equivalently xy = 2. Therefore Option A correctly identifies both curves.
వివరణ:
Question 22
ప్రశ్న 22
A flow channel in a steady two-dimensional incompressible flow becomes narrower as measured normal to the local streamlines. If the channel is bounded by the same two streamlines throughout, what qualitative change is expected in the average velocity where the channel becomes narrower?
Explanation:
Two fixed bounding streamlines define a flow channel through which fluid does not cross the side boundaries. For steady incompressible flow, the discharge carried by that channel remains constant from one section to another. If the effective width normal to the local flow direction decreases, the average velocity must increase to preserve the same discharge per unit depth. This is the two-dimensional form of continuity applied to a narrow stream tube. Therefore Option B is correct.
వివరణ:
Question 23
ప్రశ్న 23
A narrow channel in a steady two-dimensional incompressible flow carries nearly uniform velocity across its width. At one section its width normal to the flow is 0.30 m and the average velocity is 2.0 m/s. If the same flow channel narrows to 0.15 m, what is the approximate average velocity at the narrower section?
Explanation:
For unit depth normal to the two-dimensional plane, the discharge is approximately q = Vb when the velocity is nearly uniform across the narrow channel. At the first section, q = 2.0 × 0.30 = 0.60 m²/s. In steady incompressible flow, the same flow channel carries the same discharge at the second section. Thus V2 = 0.60/0.15 = 4.0 m/s. Therefore Option C is correct.
వివరణ:
Question 24
ప్రశ్న 24
Which statement best describes what can be inferred directly from a properly constructed potential-flow net?
Explanation:
Streamlines in a flow net directly show the local flow direction. Spacing of equal-increment equipotential lines can be used to infer the magnitude of the potential gradient and therefore velocity. Differences in stream function can also quantify discharge per unit depth between streamlines. Pressure is not encoded as an independent flow-net coordinate and normally requires additional information together with an appropriate governing relation under its applicable conditions. Therefore Option B correctly describes both the usefulness and limitation of a flow net.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about a two-dimensional potential-flow net: I. Streamlines and equipotential lines intersect orthogonally at regular points. II. A well-constructed net is commonly refined into approximate curvilinear squares. III. The difference in stream-function values between two streamlines gives discharge per unit depth between them. IV. For equal potential increments, closer equipotential spacing indicates a larger local velocity magnitude. Which option is correct?
Explanation:
Statement I is correct because the velocity is tangent to streamlines and normal to equipotential lines in potential flow. Statement II is correct because flow-net construction is commonly refined so that neighbouring members of the two orthogonal families form approximate curvilinear squares. Statement III is correct because the stream-function difference represents volumetric flow rate per unit depth in a two-dimensional incompressible flow. Statement IV is correct because a fixed potential increment over a smaller normal distance corresponds to a larger potential gradient and hence a larger velocity magnitude. Therefore all four statements are correct and Option D is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. A family of streamlines together with a family of equipotential lines సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: B. Incompressible and irrotational flow సమాధానం: B.
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Question 3 ప్రశ్న 3Answer: B. Because the velocity is tangent to the streamline and normal to the equipotential line సమాధానం: B.
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Question 4 ప్రశ్న 4Answer: C. Distinct streamlines do not cross at an ordinary point, and distinct equipotential lines corresponding to different potential values also cannot cross సమాధానం: C.
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Question 5 ప్రశ్న 5Answer: B. A cell bounded by two adjacent streamlines and two adjacent equipotential lines that intersect approximately orthogonally and whose corresponding side dimensions are approximately equal సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: B. Respect the boundary conditions, sketch one family of curves, introduce the orthogonal family, and iteratively refine both until the cells are smooth approximate curvilinear squares సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: B. A higher local velocity magnitude సమాధానం: B.
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Question 8 ప్రశ్న 8Answer: C. 4.0 m/s సమాధానం: C.
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Question 9 ప్రశ్న 9Answer: C. 2.50 సమాధానం: C.
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Question 10 ప్రశ్న 10Answer: C. 2.50 m²/s సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: C. 6.00 m²/s సమాధానం: C.
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Question 12 ప్రశ్న 12Answer: B. 1.50 m²/s సమాధానం: B.
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Question 13 ప్రశ్న 13Answer: B. 3 m²/s సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: B. 4 flow channels and 6 potential intervals సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: B. Parallel straight streamlines and perpendicular parallel straight equipotential lines సమాధానం: B.
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Question 16 ప్రశ్న 16Answer: B. Streamlines are radial rays and equipotential lines are concentric circles సమాధానం: B.
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Question 17 ప్రశ్న 17Answer: A. As a streamline సమాధానం: A.
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Question 18 ప్రశ్న 18Answer: B. Velocity is tangent to a streamline and normal to an equipotential line సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: C. Only the numerical labels of the equipotential and streamline curves shift; the velocity field and curve geometry remain unchanged సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: A. Streamline slope = -0.5 and equipotential slope = 2 సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: A. Equipotential: x² - y² = 3; streamline: xy = 2 సమాధానం: A.
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Question 22 ప్రశ్న 22Answer: B. The velocity increases so that the same discharge per unit depth can pass through the narrower channel సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. 4.0 m/s సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: B. It provides flow direction and allows qualitative or quantitative interpretation of velocity and flow distribution, while pressure generally requires additional governing relations and data సమాధానం: B.
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Question 25 ప్రశ్న 25Answer: D. I, II, III and IV సమాధానం: D.
