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Question 1
ప్రశ్న 1
Which situation most commonly requires a doubly reinforced rectangular RCC beam instead of an ordinary singly reinforced beam?
Explanation:
A singly reinforced section has a limiting flexural capacity associated with its limiting neutral-axis depth. Simply adding tension reinforcement beyond this limiting condition does not provide the required ductile singly reinforced behaviour. If the beam dimensions, particularly its depth, cannot conveniently be increased, compression reinforcement may be introduced. Additional tension reinforcement is then provided to balance the additional compression-steel force. Therefore Option A is correct.
వివరణ:
Question 2
ప్రశ్న 2
In the usual IS 456 Limit State design approach for a doubly reinforced rectangular beam, how is the required ultimate moment conveniently treated?
Explanation:
The conventional design starts with the limiting capacity of the corresponding singly reinforced section. This portion is associated with xu,max and the corresponding limiting tension reinforcement. Any moment exceeding Mu,lim is treated as an additional moment. Compression reinforcement and additional tension reinforcement provide the internal couple needed for this additional resistance. Therefore Option A is correct.
వివరణ:
Question 3
ప్రశ్న 3
For an M25 rectangular beam with Fe415 reinforcement, b = 300 mm and effective depth d = 500 mm, what limiting neutral-axis depth is used as the basis of conventional doubly reinforced design?
Explanation:
For Fe415 reinforcement, the limiting neutral-axis ratio xu,max/d is 0.48. The effective depth in the question is 500 mm. Therefore xu,max = 0.48 × 500 = 240 mm. The limiting singly reinforced portion of the doubly reinforced design is based on this depth. Therefore Option C is correct.
వివరణ:
Question 4
ప్రశ్న 4
If compression reinforcement is located at depth d' from the compression face and the limiting neutral-axis depth is xu,max, which expression gives the compression-steel strain used in the conventional doubly reinforced design?
Explanation:
At the limit state of collapse in flexure, the extreme concrete compression strain is 0.0035. Plane sections are assumed to remain plane, so the strain varies linearly to zero at the neutral axis. Compression reinforcement at depth d' therefore has strain proportional to xu,max - d'. This gives εsc = 0.0035(xu,max - d')/xu,max. Therefore Option A is correct.
వివరణ:
Question 5
ప్రశ్న 5
For a limiting Fe415 section, xu,max/d = 0.48. If compression reinforcement is located at d'/d = 0.10, what is its compression strain approximately?
Explanation:
The compression-steel strain is 0.0035(1 - d'/xu,max). The ratio d'/xu,max is 0.10/0.48 = 0.2083 approximately. Hence εsc = 0.0035(1 - 0.2083). This gives approximately 0.00277. Therefore Option C is correct.
వివరణ:
Question 6
ప్రశ్న 6
Why should the compression-steel design stress fsc not automatically be taken as exactly 0.87fy for every Fe415 or Fe500 doubly reinforced beam?
Explanation:
The stress developed in compression reinforcement depends on its strain at the ultimate condition. That strain depends on the position of the compression steel relative to the neutral axis. For high-yield-strength reinforcement, the corresponding design stress must be obtained from the applicable design stress-strain relationship. It may be below 0.87fy when the available compression strain is insufficient to reach that value. Therefore Option A is correct.
వివరణ:
Question 7
ప్రశ్న 7
According to the IS 456 Annex G design expression for a doubly reinforced rectangular section, what relation represents the additional moment M2 = Mu - Mu,lim?
Explanation:
IS 456 Annex G expresses the moment exceeding the limiting singly reinforced resistance in terms of compression reinforcement. The specified relation is Mu - Mu,lim = fsc Asc(d - d'). Here fsc is the design stress in the compression reinforcement corresponding to its calculated strain. Asc is the area of compression reinforcement and d - d' is the lever arm of the additional steel couple. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
Under the same Annex G doubly reinforced design formulation, which expression gives the additional tensile reinforcement Ast2 required to balance the compression reinforcement?
Explanation:
The additional tensile steel balances the force developed in the compression reinforcement in the Annex G formulation. The compression-steel force is Asc fsc. The corresponding additional tensile force is 0.87fy Ast2. Equating these forces gives Ast2 = Asc fsc/(0.87fy). Therefore Option A is correct.
వివరణ:
Question 9
ప్రశ్న 9
How is the total tensile reinforcement Ast obtained in the conventional Annex G design of a doubly reinforced rectangular beam?
Explanation:
Ast1 is the tensile reinforcement associated with the limiting singly reinforced portion of the beam. Ast2 is the additional tensile reinforcement associated with the compression-steel couple. Both quantities act as tension reinforcement in the final section. The total tensile reinforcement is therefore their sum. Hence Ast = Ast1 + Ast2 and Option A is correct.
వివరణ:
Question 10
ప్రశ్న 10
For an M25 rectangular beam with b = 300 mm, d = 500 mm and Fe415 reinforcement, what is the limiting singly reinforced moment capacity approximately?
Explanation:
For Fe415 steel, xu,max = 0.48d = 240 mm. The limiting moment is 0.36fck b xu,max(d - 0.42xu,max). Substitution gives 0.36 × 25 × 300 × 240 × [500 - 0.42(240)] N·mm. The result is approximately 258.68 kN·m. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
For the M25, b = 300 mm, d = 500 mm, Fe415 section in the previous question, what is the tensile reinforcement Ast1 associated with the limiting singly reinforced moment approximately?
Explanation:
At the limiting condition, the tensile force balances the concrete compression resultant. Thus 0.87fyAst1 = 0.36fck b xu,max. Substituting fy = 415 N/mm², fck = 25 N/mm², b = 300 mm and xu,max = 240 mm gives Ast1 approximately 1794.8 mm². This rounds to 1795 mm². Therefore Option C is correct.
వివరణ:
Question 12
ప్రశ్న 12
The M25-Fe415 beam with b = 300 mm and d = 500 mm must resist a factored bending moment of 350 kN·m. If Mu,lim = 258.68 kN·m, what additional moment must be resisted by the compression-steel and additional-tension-steel couple?
Explanation:
The additional moment is the amount by which the required factored moment exceeds the limiting singly reinforced capacity. Thus M2 = 350 - 258.68 kN·m. This gives approximately 91.32 kN·m. Only this excess portion is assigned to the additional steel couple in the conventional design decomposition. Therefore Option C is correct.
వివరణ:
Question 13
ప్రశ్న 13
For the beam in the previous question, take d' = 50 mm and compression-steel design stress fsc = 353 N/mm². What compression-steel area Asc is required approximately to resist the additional moment of 91.32 kN·m?
Explanation:
Annex G gives M2 = fsc Asc(d - d'). The steel-couple lever arm is 500 - 50 = 450 mm. Therefore Asc = 91.32 × 10^6/[353 × 450]. This gives approximately 574.9 mm². Hence the nearest value is 575 mm² and Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
For the same 350 kN·m beam, what additional Fe415 tensile reinforcement Ast2 is required when Asc = 574.9 mm² and fsc = 353 N/mm²?
Explanation:
The additional tension steel balances the compression-steel force. Hence 0.87fyAst2 = Asc fsc. Substitution gives Ast2 = 574.9 × 353/[0.87 × 415]. This evaluates to approximately 562 mm². Therefore Option B is correct.
వివరణ:
Question 15
ప్రశ్న 15
For the M25-Fe415 doubly reinforced beam designed for 350 kN·m, if Ast1 = 1795 mm² and Ast2 = 562 mm², what total tension reinforcement is required approximately?
Explanation:
The total tensile reinforcement consists of the limiting singly reinforced portion and the additional steel-couple portion. The two areas are Ast1 = 1795 mm² and Ast2 = 562 mm². Their sum is 2357 mm². Practical bar selection would then provide at least the required calculated area while satisfying detailing requirements. Therefore Option C is correct.
వివరణ:
Question 16
ప్రశ్న 16
An M25-Fe415 beam has d = 500 mm, d' = 50 mm and 600 mm² of compression reinforcement. If fsc = 353 N/mm², what additional ultimate moment can the compression reinforcement resist according to the Annex G expression?
Explanation:
The additional moment is M2 = fsc Asc(d - d'). Substitution gives 353 × 600 × 450 N·mm. This equals 95.31 × 10^6 N·mm. Thus the additional moment is approximately 95.3 kN·m. Therefore Option D is correct.
వివరణ:
Question 17
ప్రశ్న 17
For the 600 mm² compression reinforcement in the previous question, what additional Fe415 tension reinforcement Ast2 is required approximately?
Explanation:
Force equilibrium of the additional steel couple gives 0.87fyAst2 = Asc fsc. Thus Ast2 = 600 × 353/[0.87 × 415]. This evaluates to approximately 586.6 mm². The area is close to but not identical to Asc because the design stresses in the two steel forces are different. Therefore Option C is correct.
వివరణ:
Question 18
ప్రశ్న 18
An M20 rectangular beam has b = 250 mm, d = 450 mm and Fe415 reinforcement. What is its limiting singly reinforced moment capacity approximately?
Explanation:
For Fe415 steel, xu,max = 0.48 × 450 = 216 mm. The limiting moment is 0.36fck b xu,max(d - 0.42xu,max). Substituting fck = 20 N/mm², b = 250 mm and d = 450 mm gives approximately 139.69 kN·m. This is the maximum moment assigned to the singly reinforced limiting part. Therefore Option B is correct.
వివరణ:
Question 19
ప్రశ్న 19
The M20 beam in the previous question must resist a factored moment of 220 kN·m. If d' = 45 mm and fsc = 353 N/mm², what compression-steel area is required approximately?
Explanation:
The additional moment is 220 - 139.69 = approximately 80.31 kN·m. The lever arm of the additional steel couple is 450 - 45 = 405 mm. Annex G gives Asc = M2/[fsc(d - d')]. Substitution gives Asc = 80.31 × 10^6/[353 × 405] = approximately 561.8 mm². Therefore Option C is correct.
వివరణ:
Question 20
ప్రశ్న 20
For the same M20-Fe415 beam designed for 220 kN·m, Ast1 is approximately 1077 mm² and Ast2 is approximately 549 mm². What total tension reinforcement is required approximately?
Explanation:
The limiting singly reinforced component requires approximately 1077 mm² of tensile reinforcement. The additional compression-steel couple requires approximately 549 mm² of additional tension reinforcement. These areas are added to obtain the total tension steel. Their sum is approximately 1626 mm². Therefore Option C is correct.
వివరణ:
Question 21
ప్రశ్న 21
For an analysis exercise, a doubly reinforced M25 rectangular beam has b = 300 mm, d = 500 mm, d' = 50 mm, Ast = 2200 mm² and Asc = 500 mm² of Fe415 steel. Taking fsc = 350 N/mm², assuming the tension steel develops 0.87fy, and using the Annex G simplification that the concrete area displaced by compression steel is neglected, what neutral-axis depth satisfies force equilibrium approximately?
Explanation:
The tensile force is 0.87fyAst = 0.87 × 415 × 2200 = 794310 N. The compression-steel force is Asc fsc = 500 × 350 = 175000 N. The remaining compression is provided by the concrete block, so 0.36fckb xu = 794310 - 175000. Solving gives xu approximately 229.37 mm, which is below the Fe415 limiting depth of 240 mm. Therefore Option C is correct.
వివరణ:
Question 22
ప్రశ్న 22
For the doubly reinforced beam in the previous question with xu = 229.37 mm, what is its ultimate moment capacity approximately under the stated assumptions?
Explanation:
The concrete contribution is 0.36fckb xu(d - 0.42xu). The compression-steel contribution is fscAsc(d - d'). Substituting the stated dimensions, material values and xu = 229.37 mm gives a total of approximately 328.74 kN·m. Both contributions must be included in the section moment capacity. Therefore Option C is correct.
వివరణ:
Question 23
ప్రశ్న 23
Which statement about load reversal and doubly reinforced beams is most appropriate?
Explanation:
Moment reversal changes which face of a beam is subjected to tension and which is subjected to compression. Reinforcement that acts as compression reinforcement in one loading direction may become tension reinforcement when the moment reverses. Providing reinforcement near both faces can therefore be beneficial in members exposed to reversed bending. The effective depths, force equilibrium and required reinforcement still have to be checked for each relevant loading direction. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
Which statement concerning compression reinforcement in a doubly reinforced beam is correct?
Explanation:
Longitudinal bars subjected to compression require adequate detailing and lateral restraint. Transverse reinforcement helps maintain the bar arrangement and restrains compression bars against undesirable lateral movement. Proper detailing is particularly important when the compression reinforcement is relied upon for structural resistance. Compression reinforcement can also be useful where beam depth is restricted or bending may reverse. Therefore Option A is correct.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about doubly reinforced beams under the IS 456 Annex G Limit State formulation:
1. A common design procedure first assigns Mu,lim to the limiting singly reinforced part of the section.
2. The additional moment is represented by Mu - Mu,lim = fsc Asc(d - d').
3. The additional tension reinforcement is obtained from Ast2 = Asc fsc/(0.87fy).
4. For Fe415 and Fe500 compression reinforcement, fsc may always be assumed equal to 0.87fy without checking the compression-steel strain.
Which statements are correct?
1. A common design procedure first assigns Mu,lim to the limiting singly reinforced part of the section.
2. The additional moment is represented by Mu - Mu,lim = fsc Asc(d - d').
3. The additional tension reinforcement is obtained from Ast2 = Asc fsc/(0.87fy).
4. For Fe415 and Fe500 compression reinforcement, fsc may always be assumed equal to 0.87fy without checking the compression-steel strain.
Which statements are correct?
Explanation:
Statement 1 correctly describes the conventional decomposition used for doubly reinforced beam design. Statement 2 reproduces the Annex G expression for the additional moment carried through compression reinforcement. Statement 3 correctly gives the corresponding additional tensile-steel relation. Statement 4 is incorrect because compression-steel design stress depends on the strain developed at the level of that reinforcement. Therefore Statements 1, 2 and 3 are correct and Option B is the unique answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: A. The required factored moment exceeds the limiting moment of a singly reinforced section and the available beam depth cannot conveniently be increased. సమాధానం: A.
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Question 2 ప్రశ్న 2Answer: A. As the limiting moment of a singly reinforced section plus an additional moment resisted by a compression-steel and additional-tension-steel couple సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: C. 240 mm సమాధానం: C.
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Question 4 ప్రశ్న 4Answer: A. εsc = 0.0035(1 - d'/xu,max) సమాధానం: A.
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Question 5 ప్రశ్న 5Answer: C. 0.00277 సమాధానం: C.
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Question 6 ప్రశ్న 6Answer: A. Because fsc depends on the compression-steel strain, which depends on d' and the neutral-axis depth. సమాధానం: A.
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Question 7 ప్రశ్న 7Answer: A. M2 = fsc Asc(d - d') సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: A. Ast2 = Asc fsc/(0.87fy) సమాధానం: A.
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Question 9 ప్రశ్న 9Answer: A. Ast = Ast1 + Ast2 సమాధానం: A.
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Question 10 ప్రశ్న 10Answer: C. 258.7 kN·m సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: C. 1795 mm² సమాధానం: C.
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Question 12 ప్రశ్న 12Answer: C. 91.32 kN·m సమాధానం: C.
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Question 13 ప్రశ్న 13Answer: B. 575 mm² సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: B. 562 mm² సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: C. 2357 mm² సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: D. 95.3 kN·m సమాధానం: D.
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Question 17 ప్రశ్న 17Answer: C. 587 mm² సమాధానం: C.
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Question 18 ప్రశ్న 18Answer: B. 139.7 kN·m సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: C. 562 mm² సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: C. 1626 mm² సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: C. 229.4 mm సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: C. 328.7 kN·m సమాధానం: C.
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Question 23 ప్రశ్న 23Answer: A. Reinforcement near both faces can be beneficial when bending reverses, but the member must be checked separately for the demands in each bending direction. సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: A. Compression reinforcement should be properly restrained by transverse reinforcement to maintain its position and provide lateral restraint to compression bars. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: B. 1, 2 and 3 only సమాధానం: B.
