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Question 1
ప్రశ్న 1
A uniform prismatic bar is heated uniformly and is completely free to expand without any external axial load or restraint. Which statement is correct within the linear thermal-expansion range?
Explanation:
A freely heated bar undergoes thermal strain εt = αΔT. Because its expansion is not restrained, no mechanical strain is required to enforce compatibility with a support. Consequently no thermal stress develops in the bar under the stated conditions. Its free change in length is δt = αLΔT. Therefore Option C correctly distinguishes free thermal deformation from restrained thermal stress.
వివరణ:
Question 2
ప్రశ్న 2
A 2.5 m long steel bar is heated uniformly through 40°C and is completely free to expand. If α = 12 × 10^-6/°C, what is its increase in length?
Explanation:
For free thermal expansion, δ = αLΔT. The length is 2.5 m = 2500 mm. Substitution gives δ = 12 × 10^-6 × 2500 × 40 = 1.20 mm. Since the bar is free to expand, this deformation does not generate thermal stress. Therefore Option B is correct.
వివరణ:
Question 3
ప్రశ్న 3
A uniform bar is fully restrained against axial deformation and undergoes a uniform temperature rise ΔT while remaining linearly elastic. Which expression gives the thermal stress, taking tension as positive?
Explanation:
The free thermal strain of the bar would be +αΔT during heating. Complete restraint requires the total axial strain to remain zero. A mechanical compressive strain of -αΔT must therefore be generated by the restraint. Hooke's law gives the corresponding stress as σ = E(-αΔT) = -EαΔT. Hence Option B is correct under the stated tension-positive convention.
వివరణ:
Question 4
ప్రశ్న 4
A steel bar is completely restrained between rigid supports and is heated uniformly by 75°C. If E = 200 GPa and α = 12 × 10^-6/°C, what thermal stress develops?
Explanation:
For complete restraint during heating, the thermal stress magnitude is EαΔT. Using E = 200000 MPa, α = 12 × 10^-6/°C and ΔT = 75°C gives 200000 × 12 × 10^-6 × 75. The result is 180 MPa. Heating would cause free expansion, so preventing that expansion creates compression. Therefore the stress is 180 MPa compressive and Option C is correct.
వివరణ:
Question 5
ప్రశ్న 5
An aluminium bar is fully restrained and then cooled uniformly by 40°C. If E = 70 GPa and α = 23 × 10^-6/°C, what thermal stress develops, assuming linear-elastic behaviour?
Explanation:
Cooling causes a free thermal contraction of the aluminium bar. Full restraint prevents that contraction, so the supports must stretch the bar relative to its free cooled state. The thermal stress magnitude is Eα|ΔT| = 70000 × 23 × 10^-6 × 40 = 64.4 MPa. Because the restraint opposes contraction, the induced stress is tensile. Therefore Option A is correct.
వివరణ:
Question 6
ప్రశ్న 6
A steel bar of area 600 mm² is fully restrained and subjected to a uniform temperature rise of 50°C. If E = 200 GPa and α = 12 × 10^-6/°C, what is the magnitude of the axial restraining force?
Explanation:
The fully restrained thermal stress is EαΔT. Its magnitude is 200000 × 12 × 10^-6 × 50 = 120 MPa. The restraining force is stress multiplied by cross-sectional area, giving 120 × 600 = 72000 N. This equals 72 kN. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
A 2 m long steel bar is fixed at its left end and initially has a 0.72 mm gap between its right end and a rigid stop. The bar is heated by 80°C. If E = 200 GPa and α = 12 × 10^-6/°C, what compressive stress develops after contact with the stop?
Explanation:
The unrestricted thermal expansion would be αLΔT = 12 × 10^-6 × 2000 × 80 = 1.92 mm. The bar can expand freely through the initial 0.72 mm gap before the rigid stop provides restraint. The remaining restrained expansion is 1.92 - 0.72 = 1.20 mm, corresponding to a prevented strain of 1.20/2000 = 0.0006. The resulting compressive stress is 200000 × 0.0006 = 120 MPa. Hence Option C is correct.
వివరణ:
Question 8
ప్రశ్న 8
A 2.5 m long bar has one end fixed and a 1.2 mm gap at the other end before a rigid stop. If α = 12 × 10^-6/°C, what temperature rise is just sufficient to close the gap without producing stress?
Explanation:
No stress develops until the free thermal expansion has completely closed the gap. At first contact, αLΔT equals the gap of 1.2 mm. Thus ΔT = 1.2/[12 × 10^-6 × 2500]. This gives ΔT = 40°C. Therefore Option C is correct, and stress would begin to develop only for a further temperature rise.
వివరణ:
Question 9
ప్రశ్న 9
A steel bar 1000 mm long and 500 mm² in area has E = 200 GPa and α = 12 × 10^-6/°C. Its left end is fixed, while its right end is in contact with an initially unstressed axial spring of stiffness 50 kN/mm whose far end is fixed. If the bar is heated by 60°C, what compressive force develops?
Explanation:
The free thermal expansion of the bar is αLΔT = 12 × 10^-6 × 1000 × 60 = 0.72 mm. The axial stiffness of the bar is AE/L = 500 × 200000/1000 = 100 kN/mm. If the compressive force is P, the actual bar expansion is 0.72 - P/100 mm and the spring compression is P/50 mm. Compatibility requires 0.72 - P/100 = P/50, which gives P = 24 kN. Therefore Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
For the bar-and-spring system described by a heated bar pressing against a finite-stiffness spring, which statement is generally correct when the spring stiffness is positive and finite?
Explanation:
A finite-stiffness spring permits some movement of the heated bar. Because part of the free thermal expansion is accommodated by spring displacement, the prevented thermal strain is smaller than under perfectly rigid restraint. The resulting compressive thermal stress is therefore generally below the full-restraint value EαΔT. As the spring becomes extremely stiff, the response approaches complete restraint. Hence Option B is correct.
వివరణ:
Question 11
ప్రశ్న 11
A two-segment member is held between rigid supports. The steel segment has L = 1000 mm, A = 500 mm², E = 200 GPa and α = 12 × 10^-6/°C. The aluminium segment has L = 500 mm, A = 1000 mm², E = 70 GPa and α = 23 × 10^-6/°C. If the entire member is heated uniformly by 50°C, what compressive axial force develops?
Explanation:
The two segments are in series, so the same axial compressive force acts through both segments. Their combined free thermal expansion is 12 × 10^-6 × 50 × 1000 + 23 × 10^-6 × 50 × 500 = 1.175 mm. The total axial compliance is 1000/(500 × 200000) + 500/(1000 × 70000) = approximately 1.7143 × 10^-5 mm/N. Complete restraint requires the mechanical shortening caused by the compressive force to equal the 1.175 mm free expansion. Hence P = 1.175/(1.7143 × 10^-5) ≈ 68.5 kN, so Option B is correct.
వివరణ:
Question 12
ప్రశ్న 12
In a two-segment series member of different materials held between rigid supports and heated uniformly, with no intermediate external axial load, which statement is correct after restraint forces develop?
Explanation:
With no intermediate external axial load, equilibrium requires the same axial force to pass through both series segments. Stress equals force divided by area, so unequal areas produce unequal stresses. The individual mechanical strains also depend on both stress and Young's modulus and therefore need not be equal. Compatibility applies to the algebraic sum of the segment deformations because the overall support spacing is fixed. Consequently Option B is correct.
వివరణ:
Question 13
ప్రశ్న 13
An equal-length compound member consists of a steel core and an aluminium tube arranged concentrically, perfectly bonded so that they undergo the same axial strain, and assumed to remain straight without bending. The member is free from external axial load. Steel has A = 400 mm², E = 200 GPa and α = 12 × 10^-6/°C; aluminium has A = 600 mm², E = 70 GPa and α = 23 × 10^-6/°C. If the temperature rises uniformly by 50°C and both materials remain linearly elastic, what axial stresses develop approximately?
Explanation:
The concentric bonded arrangement is treated as a one-dimensional compound member, so both materials undergo the same total axial strain and bending is excluded. Aluminium has the larger coefficient of thermal expansion and would expand more than steel if it were free. Compatibility therefore restrains the aluminium relative to its free expansion and stretches the steel beyond its own free expansion, producing aluminium compression and steel tension. Combining equal-strain compatibility with zero resultant external axial force gives a common strain of approximately 0.0007893, which produces about +37.9 MPa in steel and -25.2 MPa in aluminium. Therefore Option A is correct.
వివరణ:
Question 14
ప్రశ్న 14
An equal-length concentric compound member consists of a steel core with A = 500 mm², E = 200 GPa and α = 12 × 10^-6/°C and an aluminium tube with A = 800 mm², E = 70 GPa and α = 23 × 10^-6/°C. The constituents are perfectly bonded and the member is completely restrained against any axial change in length. If its temperature rises uniformly by 40°C, what is the magnitude of the axial reaction at either rigid support?
Explanation:
Complete axial restraint makes the total longitudinal strain of each bonded constituent zero. The steel compressive thermal stress is 200000 × 12 × 10^-6 × 40 = 96 MPa, which corresponds to a force of 96 × 500 = 48.0 kN. The aluminium compressive thermal stress is 70000 × 23 × 10^-6 × 40 = 64.4 MPa, which corresponds to 64.4 × 800 = 51.52 kN. The resultant compressive force transmitted by the compound section is therefore 48.0 + 51.52 = 99.52 kN, so each end support provides an equal and opposite axial reaction of this magnitude. Hence Option D is correct.
వివరణ:
Question 15
ప్రశ్న 15
Two equal-length elastic materials with different Young's moduli but identical coefficients of thermal expansion are perfectly bonded together. The compound member is heated uniformly and is free from external axial load and external restraint. Which statement is correct?
Explanation:
Both materials have the same coefficient of thermal expansion and experience the same temperature change. Their free thermal strains αΔT are therefore identical. Perfect bonding does not require either constituent to deviate from its own free thermal strain in this situation. With no external restraint or axial load, no balancing internal thermal stresses are needed. The compound member does expand, so zero stress must not be confused with zero thermal deformation.
వివరణ:
Question 16
ప్రశ్న 16
An equal-length compound member consists of a concentric steel core and aluminium tube that are perfectly bonded, remain straight without bending and therefore undergo the same axial strain. Steel has A = 400 mm², E = 200 GPa and α = 12 × 10^-6/°C; aluminium has A = 600 mm², E = 70 GPa and α = 23 × 10^-6/°C. The member is subjected to a uniform temperature rise of 50°C together with a concentric tensile load of 122 kN. Assuming both materials remain linearly elastic, what axial stresses develop approximately?
Explanation:
The bonded concentric constituents have a common total axial strain under the stated one-dimensional model. For each material, total strain equals mechanical strain plus its own free thermal strain, so σi = Ei(ε - αiΔT). Axial equilibrium requires the steel and aluminium forces together to equal the applied 122 kN tensile load. Solving compatibility and equilibrium gives a common strain of approximately 0.0017893, producing about 237.9 MPa tensile stress in steel and 44.8 MPa tensile stress in aluminium. The corresponding constituent forces sum to 122 kN, so Option A is correct.
వివరణ:
Question 17
ప్రశ్న 17
A 1500 mm long steel bar is heated uniformly through 60°C. Its supports permit its length to increase by only 0.60 mm. If E = 200 GPa and α = 12 × 10^-6/°C, what thermal stress develops?
Explanation:
The free thermal strain is αΔT = 12 × 10^-6 × 60 = 0.00072. The permitted actual strain is 0.60/1500 = 0.00040. The mechanical strain required to satisfy the partial restraint is 0.00040 - 0.00072 = -0.00032. Multiplying by E gives σ = 200000 × (-0.00032) = -64 MPa. Therefore the bar develops 64 MPa compression and Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
A uniform bar is heated by ΔT, but its supports permit an actual expansion equal to exactly one-half of its unrestricted free thermal expansion. Assuming linear elasticity, what is the resulting thermal stress magnitude compared with the complete-restraint value EαΔT?
Explanation:
The free thermal strain would be αΔT. If the actual permitted strain is one-half of this amount, the remaining one-half must be suppressed by mechanical compression. The required mechanical strain magnitude is therefore αΔT/2. Hooke's law gives the corresponding stress magnitude as EαΔT/2. Thus the partial-restraint thermal stress is one-half of the complete-restraint value and Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
A 2 m long steel bar is free to expand and has a constant coefficient of thermal expansion α = 12 × 10^-6/°C. The temperature rise varies linearly along the bar from 0°C at one end to 60°C at the other. What is the total free thermal elongation?
Explanation:
For a non-uniform temperature field, free thermal elongation is obtained from the integral of αΔT(x) over the member length. Because the temperature rise varies linearly from 0°C to 60°C, its average value is 30°C. With constant α, the elongation is therefore αLΔTaverage. Substitution gives 12 × 10^-6 × 2000 × 30 = 0.72 mm. Hence Option B is correct.
వివరణ:
Question 20
ప్రశ్న 20
A uniform prismatic bar is completely restrained between rigid supports. Its temperature rise varies linearly along its length from 20°C at one end to 80°C at the other. If E = 210 GPa and α = 11 × 10^-6/°C are constant, what uniform axial stress develops under the one-dimensional linear-elastic model?
Explanation:
With no intermediate axial loads and constant cross-section, the restraint produces a constant axial force and hence uniform axial stress. Compatibility requires the total integrated axial deformation to be zero. The average temperature rise for a linear variation from 20°C to 80°C is 50°C. Therefore the compressive stress magnitude is EαΔTaverage = 210000 × 11 × 10^-6 × 50 = 115.5 MPa. Hence Option C is correct.
వివరణ:
Question 21
ప్రశ్న 21
Which statement about the coefficient of linear thermal expansion α is dimensionally correct?
Explanation:
Thermal strain is expressed as εt = αΔT. Strain is dimensionless, so the product αΔT must also be dimensionless. Consequently α has units reciprocal to temperature, commonly /°C or /K. A temperature interval of one kelvin has the same magnitude as an interval of one degree Celsius, so numerical coefficients may be expressed using either interval unit. Therefore Option C is correct.
వివరణ:
Question 22
ప్రశ్న 22
A fully restrained steel bar has E = 200 GPa and α = 12 × 10^-6/°C. If the magnitude of thermal stress must not exceed 90 MPa, what is the maximum permissible magnitude of a uniform temperature change from the stress-free reference temperature?
Explanation:
For full restraint, the thermal stress magnitude is Eα|ΔT|. Setting this equal to the permitted 90 MPa gives |ΔT| = 90/(200000 × 12 × 10^-6). The denominator equals 2.4 MPa/°C. Hence the allowable temperature-change magnitude is 37.5°C. Therefore Option B is correct.
వివరణ:
Question 23
ప్రశ్న 23
A linearly elastic steel bar held at fixed end separation initially has a uniform tensile stress of 50 MPa due to a pre-existing mechanical condition. Its temperature is then increased uniformly by 30°C while the end separation remains unchanged. If E = 200 GPa and α = 12 × 10^-6/°C, what is the final normal stress, taking tension as positive?
Explanation:
The temperature rise would cause free expansion, so maintaining the same end separation introduces a compressive thermal stress increment. Its magnitude is EαΔT = 200000 × 12 × 10^-6 × 30 = 72 MPa. Taking tension as positive, the stress increment is therefore -72 MPa. Superposition within the stated linear-elastic model gives final stress = +50 - 72 = -22 MPa. Hence the final stress is 22 MPa compression and Option D is correct.
వివరణ:
Question 24
ప్రశ్న 24
Match the thermal-loading condition with the corresponding result for a uniform linearly elastic bar:
1. Free uniform heating
2. Fully restrained uniform heating
3. Fully restrained uniform cooling
4. Partial restraint allowing some but not all free expansion
P. Tensile thermal stress
Q. Thermal strain without thermal stress
R. Compressive stress smaller in magnitude than the complete-restraint value
S. Compressive stress of magnitude EαΔT
Which matching is correct?
1. Free uniform heating
2. Fully restrained uniform heating
3. Fully restrained uniform cooling
4. Partial restraint allowing some but not all free expansion
P. Tensile thermal stress
Q. Thermal strain without thermal stress
R. Compressive stress smaller in magnitude than the complete-restraint value
S. Compressive stress of magnitude EαΔT
Which matching is correct?
Explanation:
Free uniform heating produces thermal strain and expansion without thermal stress, so item 1 matches Q. Fully restrained heating suppresses expansion and therefore creates compression of magnitude EαΔT, so item 2 matches S. Fully restrained cooling suppresses contraction and consequently creates tensile stress, so item 3 matches P. Partial restraint permits some expansion, leaving a smaller prevented thermal strain and therefore a smaller compressive stress than full restraint, so item 4 matches R. Thus Option A gives the correct matching.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about thermal deformation and stress in axially loaded members:
1. A uniform freely heated bar can undergo thermal strain without developing thermal stress.
2. Complete restraint of uniform heating produces compressive stress in an initially stress-free bar.
3. In a one-dimensional, perfectly bonded two-material compound member that remains straight and is free of external axial force, different coefficients of thermal expansion can produce self-equilibrating internal axial stresses.
4. For a fully restrained uniform prismatic bar with constant E and α, the thermal stress EαΔT depends directly on the bar length and cross-sectional area.
Which statements are correct?
1. A uniform freely heated bar can undergo thermal strain without developing thermal stress.
2. Complete restraint of uniform heating produces compressive stress in an initially stress-free bar.
3. In a one-dimensional, perfectly bonded two-material compound member that remains straight and is free of external axial force, different coefficients of thermal expansion can produce self-equilibrating internal axial stresses.
4. For a fully restrained uniform prismatic bar with constant E and α, the thermal stress EαΔT depends directly on the bar length and cross-sectional area.
Which statements are correct?
Explanation:
Statement 1 is correct because thermal stress requires restraint rather than temperature change alone. Statement 2 is correct because heating tends to expand the bar, and complete prevention of that expansion requires compression. Statement 3 is correct under the explicitly stated one-dimensional compound-member assumptions because unequal free thermal strains are reconciled through compatibility, producing self-equilibrating internal axial forces when the external axial resultant is zero. Statement 4 is incorrect because the fully restrained uniform thermal stress is EαΔT and is independent of bar length and area, although the corresponding restraining force depends on area. Therefore Statements 1, 2 and 3 are correct and Option B is the unique answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: C. The bar develops thermal strain αΔT but no thermal stress. సమాధానం: C.
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Question 2 ప్రశ్న 2Answer: B. 1.20 mm సమాధానం: B.
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Question 3 ప్రశ్న 3Answer: B. -EαΔT సమాధానం: B.
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Question 4 ప్రశ్న 4Answer: C. 180 MPa compression సమాధానం: C.
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Question 5 ప్రశ్న 5Answer: A. 64.4 MPa tension సమాధానం: A.
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Question 6 ప్రశ్న 6Answer: C. 72 kN సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: C. 120 MPa సమాధానం: C.
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Question 8 ప్రశ్న 8Answer: C. 40°C సమాధానం: C.
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Question 9 ప్రశ్న 9Answer: B. 24 kN సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: B. The thermal stress is generally less than the complete-restraint value because some thermal movement is permitted. సమాధానం: B.
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Question 11 ప్రశ్న 11Answer: B. 68.5 kN సమాధానం: B.
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Question 12 ప్రశ్న 12Answer: B. Both segments carry the same axial force, but their stresses may differ if their areas differ. సమాధానం: B.
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Question 13 ప్రశ్న 13Answer: A. Steel 37.9 MPa tension and aluminium 25.2 MPa compression సమాధానం: A.
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Question 14 ప్రశ్న 14Answer: D. 99.5 kN సమాధానం: D.
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Question 15 ప్రశ్న 15Answer: C. No thermal stress develops solely from the temperature change because both constituents have the same free thermal strain. సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: A. Steel 237.9 MPa tension and aluminium 44.8 MPa tension సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: B. 64 MPa compression సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. One-half of EαΔT సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: B. 0.72 mm సమాధానం: B.
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Question 20 ప్రశ్న 20Answer: C. 115.5 MPa compression సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: C. It has units reciprocal to temperature, such as /°C or /K. సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: B. 37.5°C సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: D. 22 MPa compression సమాధానం: D.
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Question 24 ప్రశ్న 24Answer: A. 1-Q, 2-S, 3-P, 4-R సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: B. 1, 2 and 3 only సమాధానం: B.
