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Question 1
ప్రశ్న 1
Which statement best describes boundary-layer separation from a solid surface?
Explanation:
Boundary-layer separation occurs when the near-wall fluid can no longer continue moving downstream while remaining attached to the surface. It is commonly associated with an adverse pressure gradient that decelerates the boundary-layer flow. The wall shear decreases as separation is approached. Near-wall reverse flow can develop downstream of the separation point. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
For incompressible external flow with x measured downstream, which combination represents a favourable pressure gradient?
Explanation:
A favourable pressure gradient means that static pressure decreases in the direction of flow. Thus dp/dx is negative. For an incompressible inviscid external stream, this pressure decrease is accompanied by an increase in external velocity. Hence dUe/dx is positive. Therefore Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
Which combination correctly represents an adverse pressure gradient in an incompressible external stream?
Explanation:
An adverse pressure gradient means that pressure rises in the downstream direction. Therefore dp/dx is positive. The corresponding external flow decelerates, so dUe/dx is negative. This pressure rise opposes the motion of the low-momentum fluid near the wall. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
For steady incompressible inviscid flow immediately outside a boundary layer, which relation connects pressure gradient and external velocity Ue?
Explanation:
The external flow can be related to pressure through the streamwise Euler equation. For steady incompressible flow this gives Ue(dUe/dx) = -(1/rho)(dp/dx). Rearranging yields dp/dx = -rho Ue(dUe/dx). Thus acceleration corresponds to falling pressure and deceleration to rising pressure. Therefore Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
For a Newtonian fluid adjacent to a stationary wall, how is the local wall shear stress related to the boundary-layer velocity profile?
Explanation:
For a Newtonian fluid, shear stress is proportional to the velocity gradient normal to the wall. At the surface this gives tau_w = mu(du/dy)_wall. In a normally attached boundary layer the streamwise velocity increases away from the stationary wall, giving positive wall shear under the usual sign convention. The gradient decreases toward zero as classical separation is approached. Therefore Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
Under the classical steady two-dimensional boundary-layer description, what condition identifies the incipient separation point?
Explanation:
At a stationary wall the no-slip condition keeps the fluid velocity itself equal to zero whether the flow is attached or separated. Separation is therefore not identified by u = 0 at the wall. Instead the wall-normal velocity gradient decreases to zero at incipient separation. Since tau_w = mu(du/dy)_wall, the wall shear stress is also zero there. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
What is indicated when the streamwise wall shear stress becomes negative downstream of a separation point under the usual positive-downstream sign convention?
Explanation:
Negative wall shear means that the near-wall velocity gradient has reversed sign relative to the normal attached-flow condition. This is associated with local reverse flow in the separated region. The no-slip condition still applies at the solid wall. Classical simple boundary-layer marching methods become problematic once substantial reverse flow develops. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
For the classical steady two-dimensional laminar boundary-layer equation at a stationary impermeable wall, what does an adverse pressure gradient dp/dx > 0 imply for the wall-normal curvature of the streamwise velocity profile?
Explanation:
For the classical steady two-dimensional laminar boundary-layer equation, the convective terms vanish exactly at a stationary impermeable wall because u = 0 and v = 0 there. The wall equation then reduces to mu(d²u/dy²)_wall = dp/dx. Since dynamic viscosity is positive, an adverse pressure gradient with dp/dx > 0 gives positive wall-normal curvature of the velocity profile at the wall. This change in profile shape is part of the classical approach toward boundary-layer separation. Therefore Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
What is the usual effect of a favourable pressure gradient on an attached boundary layer?
Explanation:
A favourable pressure gradient corresponds to decreasing pressure and increasing external velocity downstream. This acceleration assists the streamwise motion of fluid in the boundary layer. The near-wall fluid therefore has less difficulty remaining attached to the surface. Classical separation is consequently associated primarily with adverse rather than favourable pressure gradients. Therefore Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
Which statement about an adverse pressure gradient is most accurate?
Explanation:
An adverse pressure gradient opposes the motion of the boundary-layer fluid and therefore promotes separation. However, the mere existence of dp/dx > 0 does not mean that the flow must separate immediately. If the near-wall fluid retains sufficient momentum, the boundary layer can remain attached through a moderate adverse gradient. Separation occurs when the wall shear is finally reduced to zero under the classical description. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
Why is a turbulent boundary layer generally more resistant to separation than a laminar boundary layer under a comparable adverse pressure gradient?
Explanation:
Turbulent mixing transfers momentum strongly across the boundary layer. Higher-momentum fluid from farther away from the wall is continually transported toward the near-wall region. The resulting mean velocity profile is fuller than a comparable laminar profile. This gives near-wall fluid greater ability to move against a rising pressure. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
What is a common flow-field consequence after boundary-layer separation from a bluff or strongly curved body?
Explanation:
When the boundary layer separates, the main stream no longer follows the body surface over the separated region. A shear layer forms between the outer flow and the slower or reversing fluid near the body. Recirculating and vortical motion commonly appears within the wake. The wake also contains a substantial velocity deficit relative to the surrounding stream. Therefore Option D is correct.
వివరణ:
Question 13
ప్రశ్న 13
How does extensive boundary-layer separation commonly affect the drag of a bluff body?
Explanation:
A separated wake often has relatively low pressure compared with the high pressure near the forward portion of a bluff body. This creates a substantial streamwise pressure-force imbalance. The resulting component is commonly called pressure drag or form drag. For bluff bodies this contribution may dominate the total drag. Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
Why can streamlining a body help delay boundary-layer separation?
Explanation:
A streamlined shape is designed to guide the external flow through gradual acceleration and deceleration. A gradual pressure recovery produces a less severe adverse pressure gradient than an abrupt expansion of the outer stream. The boundary-layer fluid therefore loses streamwise momentum less abruptly. This allows attached flow to persist farther downstream. Therefore Option C is correct.
వివరణ:
Question 15
ప్రశ్న 15
How can boundary-layer suction through a porous surface delay separation?
Explanation:
Fluid very close to the wall has relatively low streamwise momentum and is therefore most vulnerable to an adverse pressure gradient. Suction removes part of this low-momentum fluid through the surface. The remaining boundary layer can become thinner and better able to resist downstream pressure rise. Separation can consequently be delayed under suitable conditions. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
What is the principal purpose of vortex generators used for separation control?
Explanation:
Vortex generators intentionally create streamwise vortical structures. These structures enhance mixing between the outer flow and the near-wall region. Higher-momentum fluid is transported toward the wall. The energized boundary layer can withstand a stronger adverse pressure gradient before separating. Therefore Option D is correct.
వివరణ:
Question 17
ప్రశ్న 17
Which statement best describes deliberately triggering an earlier transition to turbulence as a possible separation-control strategy?
Explanation:
A turbulent boundary layer usually contains more near-wall momentum than a comparable laminar layer because of turbulent mixing. Deliberately promoting transition can therefore delay separation in some engineering applications. The tradeoff is that turbulent boundary layers generally have greater skin-friction drag. The overall benefit depends on whether the reduction in separation-related pressure drag outweighs the friction penalty. Therefore Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
Water of density 1000 kg/m³ has an external boundary-layer-edge velocity Ue = 4.0 m/s that is increasing at dUe/dx = +0.50 s^-1. What is dp/dx approximately?
Explanation:
For steady incompressible external flow, dp/dx = -rho Ue(dUe/dx). Substitution gives dp/dx = -(1000)(4.0)(0.50). This equals -2000 Pa/m. The negative sign indicates a favourable pressure gradient because pressure decreases downstream while velocity increases. Therefore Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
Air of density 1.2 kg/m³ has an external velocity Ue = 5.0 m/s that decreases at dUe/dx = -0.40 s^-1. What is the streamwise pressure gradient?
Explanation:
The external-flow relation is dp/dx = -rho Ue(dUe/dx). Substitution gives dp/dx = -(1.2)(5.0)(-0.40). The result is +2.4 Pa/m. Since pressure increases in the downstream direction, this is an adverse pressure gradient. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
Oil has dynamic viscosity mu = 1.0 × 10^-3 Pa·s. If the streamwise velocity gradient at a wall is (du/dy)_wall = 200 s^-1, what is the wall shear stress?
Explanation:
For a Newtonian fluid, tau_w = mu(du/dy)_wall. Substitution gives tau_w = (1.0 × 10^-3)(200). This equals 0.200 Pa. Since the gradient is positive, the wall shear is positive under the stated streamwise convention. Therefore Option D is correct.
వివరణ:
Question 21
ప్రశ్న 21
In water of density 1000 kg/m³, the external velocity at a location is Ue = 2.0 m/s and the measured pressure gradient is dp/dx = +500 Pa/m. Using the incompressible external-flow relation, what is dUe/dx?
Explanation:
The relation dp/dx = -rho Ue(dUe/dx) can be rearranged for dUe/dx. Thus dUe/dx = -(dp/dx)/(rho Ue). Substitution gives -500/(1000 × 2.0). The result is -0.25 s^-1, confirming that the positive pressure gradient produces external-flow deceleration. Therefore Option B is correct.
వివరణ:
Question 22
ప్రశ్న 22
Along a surface, the static pressure rises from 100 kPa to 103 kPa over a downstream distance of 2.0 m. If the variation is approximated as linear, what is the average pressure gradient and its classification?
Explanation:
The pressure increase is 3 kPa, or 3000 Pa. Dividing by the downstream distance of 2.0 m gives an average dp/dx of +1500 Pa/m. A positive pressure gradient means pressure increases in the direction of flow. This is therefore an adverse pressure gradient. Hence Option C is correct.
వివరణ:
Question 23
ప్రశ్న 23
For flow over a smoothly curved body, why is boundary-layer separation often associated with the downstream region after the external velocity has passed a maximum?
Explanation:
As the external stream accelerates toward a velocity maximum, the pressure normally decreases and the gradient is favourable. Beyond the velocity maximum, the outer flow commonly decelerates. Bernoulli or Euler reasoning then implies a downstream pressure rise. This adverse pressure gradient acts strongly on the low-momentum fluid close to the wall and can eventually cause separation. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
Which statement correctly distinguishes the no-slip condition from the separation criterion at a stationary solid wall?
Explanation:
The no-slip condition states that fluid directly in contact with a stationary solid has zero tangential velocity. This remains true for attached flow, at incipient separation, and within a separated region. What changes at separation is the wall-normal gradient of streamwise velocity. At incipient separation that gradient, and therefore the wall shear stress, becomes zero. Therefore Option D is correct.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about boundary-layer separation: I. A favourable pressure gradient corresponds to external-flow acceleration. II. An adverse pressure gradient tends to decelerate the external flow and can promote separation. III. At classical incipient separation, wall shear stress becomes zero. IV. Separation can produce a wake and substantially increase pressure drag. Which option is correct?
Explanation:
Statement I is correct because falling pressure corresponds to acceleration of the external incompressible flow. Statement II correctly describes the adverse-gradient condition associated with deceleration and possible separation. Statement III gives the standard wall-shear criterion for classical incipient separation. Statement IV correctly identifies wake formation and increased form or pressure drag as major engineering consequences. Therefore all four statements are correct and Option D is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Detachment of the boundary-layer flow from the surface after the near-wall fluid loses sufficient streamwise momentum సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. dp/dx < 0 and dUe/dx > 0 సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. dp/dx > 0 and dUe/dx < 0 సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. dp/dx = -rho Ue(dUe/dx) సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. tau_w = mu(du/dy)_wall సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. tau_w = 0, equivalently (du/dy)_wall = 0 for a Newtonian fluid సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. Near-wall flow reversal has developed సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. (d²u/dy²)_wall is positive because mu(d²u/dy²)_wall = dp/dx సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. It accelerates the external flow and generally makes separation less likely సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: C. It tends to promote separation, but a sufficiently weak adverse gradient can still permit attached flow సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. Turbulent mixing transports higher-momentum fluid toward the wall, producing a fuller mean velocity profile సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. Formation of a separated wake containing recirculation and strong velocity deficits సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: B. It commonly increases pressure or form drag by producing a low-pressure wake సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: C. It can make the downstream pressure recovery more gradual and reduce the severity of the adverse pressure gradient సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: A. It removes low-momentum fluid from the near-wall region and produces a thinner, more energetic attached layer సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: D. To mix higher-momentum outer fluid into the near-wall region and thereby energize the boundary layer సమాధానం: D.
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Question 17 ప్రశ్న 17Answer: B. It can delay separation because a turbulent boundary layer is more resistant to adverse pressure gradients, but it may increase skin-friction drag సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. -2000 Pa/m సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: A. +2.4 Pa/m సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: D. 0.200 Pa సమాధానం: D.
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Question 21 ప్రశ్న 21Answer: B. -0.25 s^-1 సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: C. +1500 Pa/m, adverse సమాధానం: C.
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Question 23 ప్రశ్న 23Answer: A. The external stream then usually decelerates and experiences pressure recovery, producing an adverse pressure gradient సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: D. The wall velocity remains u = 0, while incipient separation is identified by (du/dy)_wall = 0 సమాధానం: D.
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Question 25 ప్రశ్న 25Answer: D. I, II, III and IV సమాధానం: D.
