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Question 1
ప్రశ్న 1
A municipal plant must remove coarse debris, abrasive grit, settleable solids and biodegradable organics, and must disinfect clarified effluent before discharge. Which liquid-treatment sequence is most appropriate for a conventional activated-sludge scheme?
Explanation:
Screening protects downstream equipment from large floating and suspended debris. Grit removal prevents abrasive mineral particles from accumulating in subsequent units. Primary settling reduces settleable solids and part of the organic load before biological treatment. Aeration then treats biodegradable constituents, and secondary clarification separates the resulting biological flocs. Disinfection follows adequate solids removal when required by the approved effluent-discharge objective.
వివరణ:
Question 2
ప్రశ్న 2
A wastewater plant has repeated pump impeller damage from rags and sand, although its biological reactor removes soluble BOD satisfactorily. Which process-train improvement should receive first priority?
Explanation:
Rags can obstruct or damage pumping and mechanical equipment. Dense mineral grit causes abrasion and deposition that biological treatment cannot reliably prevent. Screens and grit-removal facilities are specifically intended to intercept these materials. Changes to sludge wasting or aeration conditions address different operating problems. Equipment layout must also ensure that the vulnerable pumps receive appropriate upstream protection.
వివరణ:
Question 3
ప్రశ్న 3
A screened and degritted municipal wastewater stream has relatively low settleable TSS but high soluble biodegradable BOD. If the objective is substantial soluble-BOD removal, which selection is technically justified?
Explanation:
Primary settling mainly removes settleable particulate material. High soluble biodegradable BOD cannot be removed adequately through gravity clarification alone. An aerobic biological unit such as activated sludge or a suitable attached-growth process can oxidize the soluble substrate. Biomass generated or detached during treatment must be separated before final effluent release. The selected configuration also needs to satisfy the site's effluent and operational requirements.
వివరణ:
Question 4
ప్రశ్న 4
At an activated-sludge plant, soluble BOD leaving aeration is low, but final-effluent TSS rises and the secondary-clarifier sludge blanket is increasing. What should the engineer investigate first?
Explanation:
Low soluble BOD after aeration indicates that substrate oxidation may be satisfactory. High final suspended solids can nevertheless result from failure of downstream biomass separation. A rising sludge blanket may indicate inadequate withdrawal, poor settleability or excessive solids loading. Return and waste sludge flows should be assessed alongside clarifier hydraulic conditions. Increasing upstream treatment capacity without diagnosing secondary clarification would not directly resolve the observed problem.
వివరణ:
Question 5
ప్రశ్న 5
A small municipality has biodegradable sewage, adequate site area, limited capacity for continuous aerator maintenance, and a requirement for conventional secondary BOD removal. Which treatment concept merits serious consideration in a comparative feasibility study?
Explanation:
A trickling filter uses biofilm attached to media for biological oxidation. It can be a candidate where its energy and operational characteristics fit local conditions. The process still needs media distribution, ventilation, drainage and maintenance. Detached biofilm must be removed in a downstream clarifier. A feasibility comparison must also examine achievable effluent quality, site area, cost and staffing rather than assuming that one technology is universally superior.
వివరణ:
Question 6
ప్రశ్న 6
A conventional plant generates primary sludge and excess waste activated sludge while its final liquid effluent passes through disinfection. Which solids-handling arrangement is most defensible where anaerobic digestion has been selected?
Explanation:
Primary sludge and WAS originate at different points in the wastewater-treatment train. Both streams require an appropriate solids-management route rather than discharge with clarified effluent. Thickening can reduce the volume that the digester must handle. Anaerobic digestion stabilizes a portion of the biodegradable solids and produces biogas. Digested sludge generally still requires dewatering and a compliant final use or disposal pathway.
వివరణ:
Question 7
ప్రశ్న 7
A conventional carbon-removal activated-sludge plant must now meet a stringent ammonia-nitrogen limit, while no total-nitrogen limit is specified. Which integrated design review is most relevant?
Explanation:
Nitrification is a biological conversion of ammonia to oxidized nitrogen under aerobic conditions. It requires adequate oxygen and a suitable solids retention time for nitrifying organisms. The secondary solids-separation and return systems must retain the required biomass. Primary sedimentation and grit removal do not accomplish the required ammonia oxidation. A separate denitrification requirement would arise if the receiving-water objective also specified sufficient total-nitrogen removal.
వివరణ:
Question 8
ప్రశ్న 8
A remote institutional site is considering a septic tank, but soil tests indicate low infiltration capacity and the groundwater table is seasonally close to ground level. Which integrated treatment and effluent-disposal decision is preferable?
Explanation:
A septic tank provides settling and partial anaerobic stabilization rather than complete effluent treatment. Subsurface disposal depends on soil permeability and suitable unsaturated separation from groundwater. A high groundwater table increases the risk of contamination and hydraulic failure. Where soil absorption is unsuitable, engineered secondary treatment or a different approved effluent route should be evaluated. The selected solution must address both treatment quality and long-term disposal performance.
వివరణ:
Question 9
ప్రశ్న 9
A municipal works receives an unusually large load of sand and road grit following sewer cleaning, and its primary sludge hoppers are filling with heavy inert solids. Which process change most directly addresses the source of the problem?
Explanation:
Sand and road grit are relatively dense inorganic solids. Excessive accumulation in primary units suggests insufficient upstream grit interception or removal. A functioning grit chamber limits abrasion and unwanted inorganic deposits throughout the plant. Sludge removal facilities still need inspection when unusual loads occur. Altering biological recycle or disinfection would not target the main cause of the observed inert-solids buildup.
వివరణ:
Question 10
ప్రశ్న 10
Digester supernatant is returned intermittently to the head of an activated-sludge plant, and each return coincides with an ammonia spike at the biological inlet. What integrated response should be evaluated?
Explanation:
Anaerobic sludge digestion can release soluble ammonium into separated liquors. Returning this liquid adds nitrogen and potentially other pollutant loads to the sewage-treatment train. An intermittent return can create a transient demand that exceeds biological treatment capacity. Equalization, controlled return or separate sidestream treatment may be appropriate. A plant-wide mass balance is needed to compare alternatives and avoid simply shifting the problem to the outfall.
వివరణ:
Question 11
ప్రశ్న 11
Which interpretation of internal recycle streams is correct when comparing conventional activated sludge and a conventional trickling-filter process?
Explanation:
Activated sludge relies on suspended microbial flocs maintained by secondary clarification and return sludge. The RAS line returns concentrated biological solids to the aeration stage. Trickling-filter microorganisms mainly grow attached to stationary media. Its liquid recirculation may improve wetting, hydraulic application and process stability. Recirculating liquid over a trickling filter is not equivalent to maintaining MLSS through an activated-sludge return line.
వివరణ:
Question 12
ప్రశ్న 12
A plant already meets its approved BOD and TSS discharge targets after secondary clarification but fails a specified microbial-quality target for a planned reuse application. Which modification should be considered first?
Explanation:
Meeting organic and suspended-solids targets does not by itself establish microbiological suitability for reuse. Disinfection is selected to achieve an independently specified microbial-quality objective. Filtration or other polishing may be needed depending on effluent characteristics and the disinfection technology. The appropriate barrier must be evaluated for effectiveness, contact conditions and reliability. Reuse requirements vary with the intended application and applicable regulatory approval.
వివరణ:
Question 13
ప్రశ్న 13
Raw sewage contains 250 mg/L BOD5 at 12 MLD. Primary clarification removes 30% of incoming BOD5, and the subsequent biological stage plus its secondary clarifier removes 85% of the BOD5 remaining after primary clarification. Assuming unchanged net liquid flow, what are the final BOD5 concentration and overall removal?
Explanation:
The primary clarifier leaves 250 times 0.70 = 175 mg/L of BOD5. The subsequent stage leaves 15% of this concentration. Therefore final BOD5 equals 175 times 0.15 = 26.25 mg/L. Overall removal from raw sewage is (250 - 26.25)/250 times 100 = 89.5%. Stage efficiencies act on the loads entering their respective stages and cannot simply be added.
వివరణ:
Question 14
ప్రశ్న 14
A hypothetical plant treats 8 MLD containing 300 mg/L influent TSS. Primary settling captures 60% of this TSS, and a downstream polishing/settling stage captures 80% of the remaining TSS; assume no additional solids generation and unchanged net flow. What are final TSS and the solids mass captured in the downstream stage?
Explanation:
Primary settling leaves 40% of 300 mg/L, or 120 mg/L. The downstream stage captures 80% of that remaining concentration, leaving 24 mg/L. Its solids capture is 8 times (120 - 24) = 768 kg/day. The primary unit separately removes 8 times (300 - 120) = 1,440 kg/day. This simplified solids balance excludes new biomass production, which must be considered in a real biological-treatment design.
వివరణ:
Question 15
ప్రశ్న 15
An ASP receives 6.0 MLD of fresh primary effluent and operates at RAS ratio Qr/Q = 0.50. Its secondary clarifier removes 0.12 MLD as WAS in addition to RAS. Neglect all other liquid losses and additions. What are clarifier inlet flow and net clarified effluent flow?
Explanation:
Return sludge flow is 0.50 times 6.0 = 3.0 MLD. Aeration-tank discharge entering the secondary clarifier is the sum of fresh and recycled flows, or 9.0 MLD. Clarifier underflow is split into 3.0 MLD RAS and 0.12 MLD WAS. The clarified outflow is 9.0 - 3.0 - 0.12 = 5.88 MLD. RAS is internal recirculation and is not an additional external wastewater discharge.
వివరణ:
Question 16
ప్రశ్న 16
A primary clarifier ahead of biological treatment receives 10 MLD average flow and 24 MLD peak flow. For this design exercise, the specified maximum average and peak overflow rates are 40 and 80 m3/(m2 day), respectively. Which minimum effective plan area satisfies both limits?
Explanation:
At average flow, the required area is 10,000/40 = 250 m2. At peak flow, the required area is 24,000/80 = 300 m2. The tank must satisfy both conditions using the same effective plan area. The larger value of 300 m2 governs and the two areas must not be added. The design must also check detention, hydraulic distribution, weir loading and sludge removal.
వివరణ:
Question 17
ప్రశ్న 17
A conventional ASP receives 5 MLD of sewage at 240 mg/L BOD5, after primary settling removes 25% of the raw BOD5 load. If the selected aeration F/M is 0.25 kg BOD5/(kg MLVSS day) with MLVSS = 3.0 kg/m3, what aeration volume and fresh-flow nominal HRT result?
Explanation:
The raw BOD5 load is 5 times 240 = 1,200 kg/day. Primary clarification leaves 75% of the load, or 900 kg/day, for the aeration stage. Required MLVSS inventory is 900/0.25 = 3,600 kg. At 3.0 kg/m3 MLVSS, required aeration volume is 1,200 m3. The corresponding fresh-flow nominal HRT is 1,200/5,000 times 24 = 5.76 hours.
వివరణ:
Question 18
ప్రశ్న 18
A plant sends 1,200 kg/day of primary sludge dry solids at 65% volatile content and 600 kg/day of WAS dry solids at 75% volatile content to a digester. The blended thickened feed is 45 m3/day, the maximum specified VS loading is 1.5 kg/(m3 day), and minimum specified HRT is 20 days. What minimum effective digester volume meets both requirements?
Explanation:
Primary sludge provides 1,200 times 0.65 = 780 kg VS/day. WAS provides 600 times 0.75 = 450 kg VS/day, for a combined 1,230 kg VS/day. The loading limit requires 1,230/1.5 = 820 m3 of working volume. The detention requirement separately gives 45 times 20 = 900 m3. Selecting 900 m3 meets both constraints because the larger required volume governs.
వివరణ:
Question 19
ప్రశ్న 19
Raw sewage BOD5 is 280 mg/L. Primary settling removes 25% of it and the final effluent from subsequent biological treatment and clarification is 42 mg/L at unchanged net flow. What are removal across the biological/secondary stage and overall removal from raw sewage, respectively?
Explanation:
Primary settling leaves 280 times 0.75 = 210 mg/L of BOD5. The subsequent stage reduces this to 42 mg/L. Its removal relative to its own inlet is (210 - 42)/210 = 80%. Overall removal relative to the raw influent is (280 - 42)/280 = 85%. These different denominator choices must be identified when comparing unit-process and total-plant efficiency.
వివరణ:
Question 20
ప్రశ్న 20
A sludge train blends 60 m3/day of WAS at 0.8% total solids by mass with 20 m3/day of primary sludge at 3.0% total solids by mass. A thickener captures 90% of the combined dry solids in an underflow at 4.0% total solids by mass. Assuming all wet-sludge densities are 1,000 kg/m3, what is the underflow volume?
Explanation:
WAS contributes 60 times 1,000 times 0.008 = 480 kg dry solids/day. Primary sludge contributes 20 times 1,000 times 0.03 = 600 kg/day. Total incoming dry solids are 1,080 kg/day and the thickener captures 972 kg/day. An underflow at 4.0% solids and 1,000 kg/m3 carries 40 kg solids per cubic metre. Required underflow volume is therefore 972/40 = 24.3 m3/day.
వివరణ:
Question 21
ప్రశ్న 21
A combined-sewer catchment sends short-duration wet-weather surges to an STP that performs well in dry weather but experiences primary and secondary clarifier solids washout during peaks. Which integrated design response is most appropriate?
Explanation:
Wet-weather inflow can sharply increase hydraulic load without increasing biodegradable strength proportionally. High flow can overload primary and secondary settling units and cause solids washout. Equalization or other approved wet-weather management can moderate the surges if appropriately designed. Screens, grit removal, clarifiers and biological reactors must be checked against their relevant peak capacities. Simply modifying biomass wasting cannot substitute for an integrated hydraulic assessment.
వివరణ:
Question 22
ప్రశ్న 22
A trickling filter receives 3.0 MLD of primary effluent at 180 mg/L BOD5 and recirculates clarified liquid at a ratio of 1.0 to fresh flow. Its media area is 1,000 m2 and depth is 2.0 m. What are total applied hydraulic loading and external organic loading based only on fresh BOD5 mass?
Explanation:
Recirculation at a ratio of one adds another 3.0 MLD to the fresh 3.0 MLD. Total liquid applied is therefore 6,000 m3/day, giving hydraulic loading of 6,000/1,000 = 6.0 m3/(m2 day). Fresh external BOD5 load is 3.0 times 180 = 540 kg/day. Media volume is 1,000 times 2.0 = 2,000 m3. The specified external organic loading is 540/2,000 = 0.27 kg BOD5/(m3 day).
వివరణ:
Question 23
ప్రశ్న 23
A proposed nitrifying ASP needs 600 kg O2/day for its specified carbonaceous treatment duty and must additionally oxidize 50 kg/day of ammonia nitrogen. Using a theoretical nitrification requirement of 4.56 kg O2 per kg ammonia nitrogen oxidized, what combined theoretical oxygen demand should be considered before field transfer corrections?
Explanation:
The stated carbonaceous oxygen duty is 600 kg/day. Nitrification requires an additional 50 times 4.56 = 228 kg O2/day. The combined theoretical demand is 600 + 228 = 828 kg O2/day. Aeration equipment cannot be sized merely by adding this mass directly to an air-flow rate without checking oxygen-transfer performance. Field transfer efficiency, temperature and operational allowances require separate evaluation.
వివరణ:
Question 24
ప్రశ్న 24
An industrial cleaning stream periodically enters a municipal sewer, causing abrupt soluble-BOD loading and oxygen depletion in an activated-sludge reactor despite normal preliminary solids removal. Which intervention addresses the treatment train most effectively?
Explanation:
A soluble organic shock can pass through screening, grit removal and much of primary sedimentation. It can increase the oxygen demand placed on the biological treatment system. Industrial source control and equalization can reduce the size and frequency of such peaks. Plant operators should evaluate dissolved oxygen, organic loading and biomass health before changing process settings. Effective correction addresses the influent disturbance as well as the reactor's ability to withstand it.
వివరణ:
Question 25
ప్రశ్న 25
A land-constrained municipality has reliable skilled operation and must meet stringent carbon, ammonia and total-nitrogen targets together with an approved disinfection target. Which preliminary process-selection concept is most defensible?
Explanation:
A strict ammonia limit ordinarily requires a treatment arrangement capable of nitrification. Meeting an additional total-nitrogen limit can require nitrogen removal beyond simple ammonia oxidation. A suitable biological nutrient-removal configuration can incorporate the necessary aerobic and anoxic functions. Effluent solids control and any required disinfection or polishing remain part of the full treatment train. Process choice must also assess hydraulic variability, sludge handling, land, costs and achievable site-specific effluent limits.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: C. Screening, grit removal, primary settling, aeration, secondary clarification and disinfection. సమాధానం: C.
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Question 2 ప్రశ్న 2Answer: A. Restore effective screening and grit removal upstream of vulnerable pumps and downstream treatment units. సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: D. Provide an appropriately designed biological treatment stage followed by suitable biomass separation. సమాధానం: D.
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Question 4 ప్రశ్న 4Answer: B. Examine secondary-clarifier solids loading and settling, together with RAS and WAS operation. సమాధానం: B.
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Question 5 ప్రశ్న 5Answer: C. A properly loaded trickling filter with suitable distribution, ventilation and downstream secondary clarification. సమాధానం: C.
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Question 6 ప్రశ్న 6Answer: D. Provide appropriate collection and thickening of primary sludge and WAS, then controlled digestion and subsequent dewatering or further handling. సమాధానం: D.
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Question 7 ప్రశ్న 7Answer: A. Check nitrification-capable aeration, oxygen supply, suitable biomass retention and secondary-solids handling. సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: B. Evaluate site-appropriate further treatment and an approved disposal or conveyance route instead of assuming ordinary subsurface soakage is feasible. సమాధానం: B.
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Question 9 ప్రశ్న 9Answer: A. Improve upstream grit removal and grit handling while verifying preliminary hydraulic performance. సమాధానం: A.
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Question 10 ప్రశ్న 10Answer: C. Measure the sidestream nitrogen and organic loads, control or equalize the returns, and assess biological-treatment or sidestream-treatment capacity. సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: D. Activated sludge returns concentrated settled biomass to aeration, whereas trickling-filter recirculation generally reapplies liquid to the attached-growth bed. సమాధానం: D.
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Question 12 ప్రశ్న 12Answer: B. Provide an appropriate validated disinfection barrier, with any required upstream polishing, and verify the actual reuse-quality requirements. సమాధానం: B.
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Question 13 ప్రశ్న 13Answer: A. 26.25 mg/L and 89.5% overall removal. సమాధానం: A.
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Question 14 ప్రశ్న 14Answer: D. 24 mg/L and 768 kg/day captured in the downstream stage. సమాధానం: D.
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Question 15 ప్రశ్న 15Answer: B. 9.0 MLD and 5.88 MLD, respectively. సమాధానం: B.
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Question 16 ప్రశ్న 16Answer: C. 300 m2, controlled by peak-flow overflow rate. సమాధానం: C.
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Question 17 ప్రశ్న 17Answer: A. 1,200 m3 and 5.76 hours. సమాధానం: A.
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Question 18 ప్రశ్న 18Answer: D. 900 m3, controlled by the minimum detention time. సమాధానం: D.
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Question 19 ప్రశ్న 19Answer: B. 80% and 85%. సమాధానం: B.
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Question 20 ప్రశ్న 20Answer: C. 24.3 m3/day. సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: D. Assess wet-weather flow management or equalization and verify peak hydraulic capacity and solids retention across the entire treatment train. సమాధానం: D.
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Question 22 ప్రశ్న 22Answer: A. 6.0 m3/(m2 day) and 0.27 kg BOD5/(m3 day). సమాధానం: A.
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Question 23 ప్రశ్న 23Answer: B. 828 kg O2/day. సమాధానం: B.
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Question 24 ప్రశ్న 24Answer: C. Investigate source pretreatment and equalization, characterize the shock load, and reassess aeration and biological operating capacity. సమాధానం: C.
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Question 25 ప్రశ్న 25Answer: A. Evaluate compact biological nutrient-removal configurations with appropriate clarification or solids separation, polishing/disinfection where needed, and a complete sludge-handling line. సమాధానం: A.
