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Question 1
ప్రశ్న 1
Which description most accurately states the treatment function of a conventional septic tank?
Explanation:
A septic tank is a watertight settling and partial anaerobic treatment unit. Heavier suspended solids accumulate as sludge near its bottom. Grease and other buoyant matter form a scum layer at the surface. Anaerobic processes progressively transform part of the retained organic material. The liquid leaving the tank still contains contaminants and needs an appropriate downstream treatment or disposal system.
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Question 2
ప్రశ్న 2
For a two-compartment septic tank with equal water depth and cross-sectional width, what partition arrangement accords with the capacity proportion described in IS 2470 (Part 1)?
Explanation:
IS 2470 (Part 1) describes a two-compartment arrangement in which the first chamber has twice the capacity of the second. With equal widths and liquid depths, capacity is proportional to plan length. The corresponding first- and second-compartment lengths are therefore two-thirds and one-third of the total. The first chamber provides the larger settling and sludge-retention zone. The partition requires appropriate submerged openings so that liquid can move between chambers without carrying excessive scum.
వివరణ:
Question 3
ప్రశ్న 3
Why are properly placed submerged inlet and outlet tees or baffles provided in a septic tank?
Explanation:
A septic tank needs relatively calm hydraulic conditions for settling and flotation. Inlet fittings reduce disturbance of accumulated solids and surface scum. Properly submerged outlet fittings prevent the floating layer from passing straight into the effluent pipe. The outlet should also avoid withdrawal from the bottom sludge zone. These details reduce solids carryover and protect the downstream effluent disposal system.
వివరణ:
Question 4
ప్రశ్న 4
Which nominal detention-time range is described for septic tanks designed on the stated average-flow basis in IS 2470 (Part 1)?
Explanation:
IS 2470 (Part 1) describes a detention period of 24 to 48 hours for tanks designed using its associated sewage-flow, sedimentation and sludge criteria. The stated range refers to average daily sewage flow. It is not a substitute for checking sludge and scum storage requirements. Actual design must consider the intended user population and operating conditions. The calculation basis should be clearly identified rather than applying an isolated textbook detention value universally.
వివరణ:
Question 5
ప్రశ్న 5
In calculating a septic tank's usable hydraulic detention volume, how should roof freeboard and reserved sludge-storage capacity be treated?
Explanation:
Freeboard is the vertical space between the design water level and the roof or cover. It is not available as normal liquid working volume. Accumulated sludge and scum occupy space and can reduce the effective flow-through volume. A sound design provides for both hydraulic treatment and storage between scheduled desludging events. Tank dimensions should therefore distinguish operating liquid depth, storage allowances and roof freeboard.
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Question 6
ప్రశ్న 6
A plot proposed for septic-tank effluent disposal has a seasonally high groundwater table and soil that infiltrates poorly. Which decision is most defensible?
Explanation:
Soil absorption depends on available unsaturated soil and adequate permeability. High groundwater levels can greatly reduce the safe separation between effluent infiltration and groundwater. Poorly permeable soil can cause backup or persistent ponding. IS 2470 (Part 2) addresses alternative secondary-treatment and disposal configurations according to site conditions. The selected arrangement must protect wells, groundwater and public health.
వివరణ:
Question 7
ప్రశ్న 7
Which operating practice best protects a septic tank's treatment performance over its service life?
Explanation:
The tank retains solids faster than anaerobic digestion can completely eliminate them. Sludge and scum therefore accumulate and require periodic removal. Excess storage reduces the volume available for settling and can lead to solids escaping through the outlet. Inspection-based scheduling is more reliable than assuming a universal interval without considering occupancy and tank size. Collected septage must be transported and treated or disposed of by an appropriate safe system.
వివరణ:
Question 8
ప్రశ్న 8
What is the main design concern if stormwater runoff and groundwater infiltration are allowed to enter a septic tank?
Explanation:
A septic tank is sized for its intended wastewater load rather than uncontrolled stormwater inflow. Additional hydraulic flow reduces nominal detention for a fixed working volume. Sudden surges can disturb the scum and settled solids. The resulting effluent may also exceed the infiltration capacity of the disposal system. Watertight construction and suitable drainage separation are therefore essential.
వివరణ:
Question 9
ప్రశ్న 9
Which set of geometrical recommendations is consistent with IS 2470 (Part 1) for a rectangular septic tank?
Explanation:
IS 2470 (Part 1) gives a minimum septic-tank width of 750 mm. It also specifies at least 1.0 m liquid depth and a minimum liquid capacity of 1,000 litres. Rectangular tanks are described with length between two and four times width. These geometric minima do not determine the final size on their own. Design flow, settling performance and stored sludge volume remain necessary checks.
వివరణ:
Question 10
ప్రశ్న 10
Before a worker enters a septic tank for an unusual repair, what is the most appropriate safety requirement?
Explanation:
Septic tanks can contain oxygen-deficient atmospheres and dangerous gases. Methane is flammable and hydrogen sulfide can be highly toxic. Lowering the liquid level does not establish that the enclosed atmosphere is safe. Confined-space work requires risk assessment, suitable atmospheric testing and trained personnel. Non-entry cleaning methods should be preferred wherever feasible.
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Question 11
ప్రశ్న 11
A small institution has 45 users, each contributing an explicitly assumed average of 100 L/day of wastewater to its septic tank. What is the average daily inflow?
Explanation:
The population served is 45 people. The assumed wastewater contribution is 100 litres per person per day. Daily flow is therefore 45 times 100 = 4,500 litres. Dividing by 1,000 converts it to 4.5 m3/day. The contribution rate is supplied as a project assumption rather than claimed as a universal septic design value.
వివరణ:
Question 12
ప్రశ్న 12
A septic tank retains 3.6 m3 of effective flow-through liquid volume after allowing for occupied sludge-storage space. If average wastewater inflow is 2.4 m3/day, what is the nominal hydraulic detention time?
Explanation:
Nominal detention time equals available working volume divided by daily flow. The specified flow-through volume is 3.6 m3. Dividing it by 2.4 m3/day gives 1.5 days. Converting to hours yields 1.5 times 24 = 36 hours. The stated volume already excludes space occupied by stored sludge and therefore should not be reduced a second time.
వివరణ:
Question 13
ప్రశ్న 13
A septic tank is to provide a project-selected nominal hydraulic detention of 36 hours at an average flow of 3.2 m3/day. What effective flow-through volume is required, excluding future sludge storage?
Explanation:
The chosen detention duration is 36/24 = 1.5 days. Required hydraulic volume equals average wastewater flow multiplied by detention time. The given flow is 3.2 m3/day. Multiplying 3.2 by 1.5 produces 4.8 m3. Any specified sludge and scum storage allowance must be considered separately in total tank capacity.
వివరణ:
Question 14
ప్రశ్న 14
For an illustrative design, allow 0.06 m3 of accumulated sludge-and-scum storage per person per year. How much storage is needed for 40 users between scheduled desludging events separated by two years?
Explanation:
The problem specifies a storage accumulation allowance rather than a universal code rate. Total storage is allowance multiplied by population and desludging interval. Multiplying 0.06 m3/person/year by 40 persons and two years gives 4.8 m3. This is the storage provision alone and not the whole septic-tank capacity. The final design also needs sufficient hydraulic liquid volume and freeboard.
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Question 15
ప్రశ్న 15
Under an explicitly simplified additive design model, a septic tank needs 5.4 m3 of effective flow-through liquid volume plus 2.1 m3 reserved for accumulated sludge and scum. What minimum combined capacity below the normal water level must be provided?
Explanation:
The problem expressly defines two nonoverlapping capacity allowances. Flow-through treatment requires 5.4 m3 of usable liquid space. Reserved sludge and scum storage adds 2.1 m3. Their sum is 5.4 + 2.1 = 7.5 m3 below normal water level. Roof freeboard is not counted in this combined operating capacity.
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Question 16
ప్రశ్న 16
A proposed two-compartment septic tank has total liquid capacity of 9.0 m3. The first chamber is designed for twice the volume of the second. What are the respective chamber capacities?
Explanation:
Let the second chamber have volume V. The first chamber must then have volume 2V. Since both sum to 9.0 m3, 3V = 9.0 m3. Thus the second compartment is 3.0 m3 and the first is 6.0 m3. This satisfies the stated two-to-one capacity arrangement.
వివరణ:
Question 17
ప్రశ్న 17
A rectangular septic tank requires 12 m3 of total liquid capacity at a uniform 1.5 m liquid depth. Its internal length is twice its width. Which internal length and width satisfy these requirements?
Explanation:
Required horizontal plan area is volume divided by liquid depth. This equals 12/1.5 = 8 m2. Let the width be B and length be 2B. The plan-area equation is 2B squared = 8, giving B = 2.0 m. The length is consequently 4.0 m, and both area and ratio requirements are met.
వివరణ:
Question 18
ప్రశ్న 18
What total liquid capacity is provided by a rectangular septic tank of internal length 3.0 m, width 1.5 m and normal liquid depth 1.4 m, ignoring any displacement by partitions?
Explanation:
Liquid capacity of a rectangular tank is internal length times width times operating liquid depth. The given dimensions are 3.0 m, 1.5 m and 1.4 m. Their product is 3.0 times 1.5 times 1.4 = 6.30 m3. The calculated volume excludes roof freeboard because only normal liquid depth is used. Real partitions and construction tolerances may require adjustments to the internal geometric volume.
వివరణ:
Question 19
ప్రశ్న 19
A septic tank has a designed normal liquid depth of 1.50 m and an explicitly specified freeboard of 0.30 m above water level. What minimum internal vertical depth from floor to underside of cover does this simplified geometry require?
Explanation:
Liquid depth and freeboard occupy consecutive vertical portions of the tank. The normal liquid level stands 1.50 m above the floor. A freeboard allowance of 0.30 m lies above that level. Adding them gives 1.80 m from floor to underside of cover. The freeboard must not be counted as ordinary working liquid capacity.
వివరణ:
Question 20
ప్రశ్న 20
Two identical septic tanks operating in parallel are to share a calculated total required liquid capacity of 14 m3 equally. What capacity must each tank provide under this equal-duty arrangement?
Explanation:
Total required capacity is specified as 14 m3. It is to be shared equally across two operating units. Dividing 14 by two gives 7 m3 for each tank. Both tanks together provide the full 14 m3 at normal operation. The calculation does not imply that either single tank has sufficient capacity to treat the entire flow during maintenance.
వివరణ:
Question 21
ప్రశ్న 21
A septic tank has a total below-water liquid capacity of 6.0 m3, of which accumulated sludge and scum presently occupy 1.5 m3. At an average wastewater inflow of 4.0 m3/day, what is the nominal detention time based on the remaining flow-through volume?
Explanation:
The gross volume below water level is 6.0 m3. Accumulated solids occupy 1.5 m3 and therefore reduce the flow-through volume to 4.5 m3. Nominal detention is 4.5/4.0 = 1.125 days. Multiplying by 24 gives 27 hours. This illustrates how progressive sludge accumulation can shorten detention even when the tank dimensions and incoming flow are unchanged.
వివరణ:
Question 22
ప్రశ్న 22
For a septic-tank sedimentation-area check at 25°C, IS 2470 (Part 1) states 0.92 m2 of plan area per 10 L/min of peak flow. At a design peak flow of 30 L/min, what plan area follows from this criterion alone?
Explanation:
The stated surface-area criterion is proportional to design peak flow. A peak rate of 30 L/min is three times the reference flow of 10 L/min. Required area is therefore 3 times 0.92 = 2.76 m2. The criterion is quoted for its stated temperature and sedimentation calculation. Final tank dimensions must also satisfy liquid capacity, geometry and sludge-storage requirements.
వివరణ:
Question 23
ప్రశ్న 23
A proposed subsurface effluent-disposal area is designed with an explicitly site-approved hydraulic application rate of 50 L/(m2 day). What effective absorption area is required to handle 1,500 L/day of septic-tank effluent?
Explanation:
The problem states a site-specific allowable application rate of 50 L/m2/day. The effluent quantity requiring disposal is 1,500 L/day. Dividing the flow by the allowable areal application gives 1,500/50 = 30 m2. This area must refer to the effective infiltrative surface relevant to the selected system. Soil percolation, groundwater separation and setbacks still need to be verified for the site.
వివరణ:
Question 24
ప్రశ్న 24
A site-approved effluent dispersion system has two trenches, each 15 m long and 0.60 m wide. If the allowable hydraulic loading on trench-bottom area is explicitly specified as 70 L/(m2 day), what combined daily effluent flow can the trenches accept?
Explanation:
The bottom area of one trench is 15 times 0.60 = 9.0 m2. Two identical trenches together provide 18.0 m2 of effective bottom area. At the specified rate of 70 L/m2/day, allowable flow is 18.0 times 70. The total is 1,260 L/day. The calculation assumes the stated site-approved loading remains valid for the proposed operating and groundwater conditions.
వివరణ:
Question 25
ప్రశ్న 25
A septic system serves 50 persons, each contributing an assumed 120 L/day. A simplified design specifies 36 hours of available hydraulic detention plus an additional sludge-and-scum storage allowance of 0.04 m3 per person per year for a two-year interval. Ignoring freeboard, what minimum combined capacity below normal water level is required?
Explanation:
Average wastewater flow is 50 times 120 = 6,000 L/day, or 6.0 m3/day. A 36-hour detention period is 1.5 days and requires 6.0 times 1.5 = 9.0 m3 of available flow-through volume. Two years of additional storage requires 0.04 times 50 times 2 = 4.0 m3. The stated additive model therefore needs 9.0 + 4.0 = 13.0 m3 below the normal water level. Freeboard, structural dimensions and effluent disposal are separate design provisions.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. It provides primary settling and flotation with anaerobic decomposition of retained solids, while its effluent requires suitable further treatment or disposal. సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: A. The first compartment occupies about two-thirds of the effective liquid length and the second about one-third. సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: C. To reduce inlet disturbance and draw the outgoing liquid from below the scum layer but above accumulated bottom sludge. సమాధానం: C.
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Question 4 ప్రశ్న 4Answer: D. 24–48 hours. సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: A. Freeboard above the normal liquid level is excluded, and adequate detention volume must remain available despite sludge and scum accumulation. సమాధానం: A.
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Question 6 ప్రశ్న 6Answer: C. Assess a suitably engineered secondary treatment or alternative disposal arrangement rather than assuming a conventional soak pit is viable. సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: B. Inspect sludge and scum accumulation and arrange safe desludging before excessive deposits interfere with settling and outlet performance. సమాధానం: B.
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Question 8 ప్రశ్న 8Answer: D. They can hydraulically overload the tank, shorten effective detention and impair the downstream absorption system. సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: C. Minimum width of 0.75 m, at least 1.0 m depth below water level, and a length-to-width ratio generally between 2 and 4. సమాధానం: C.
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Question 10 ప్రశ్న 10Answer: A. Treat it as a hazardous confined space and use trained personnel, atmospheric testing, isolation, ventilation and approved entry/rescue procedures. సమాధానం: A.
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Question 11 ప్రశ్న 11Answer: D. 4.5 m3/day. సమాధానం: D.
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Question 12 ప్రశ్న 12Answer: B. 36 hours. సమాధానం: B.
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Question 13 ప్రశ్న 13Answer: C. 4.8 m3. సమాధానం: C.
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Question 14 ప్రశ్న 14Answer: A. 4.8 m3. సమాధానం: A.
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Question 15 ప్రశ్న 15Answer: D. 7.5 m3. సమాధానం: D.
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Question 16 ప్రశ్న 16Answer: B. 6.0 m3 and 3.0 m3. సమాధానం: B.
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Question 17 ప్రశ్న 17Answer: C. 4.0 m and 2.0 m. సమాధానం: C.
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Question 18 ప్రశ్న 18Answer: A. 6.30 m3. సమాధానం: A.
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Question 19 ప్రశ్న 19Answer: D. 1.80 m. సమాధానం: D.
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Question 20 ప్రశ్న 20Answer: B. 7 m3. సమాధానం: B.
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Question 21 ప్రశ్న 21Answer: A. 27 hours. సమాధానం: A.
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Question 22 ప్రశ్న 22Answer: C. 2.76 m2. సమాధానం: C.
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Question 23 ప్రశ్న 23Answer: D. 30 m2. సమాధానం: D.
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Question 24 ప్రశ్న 24Answer: B. 1,260 L/day. సమాధానం: B.
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Question 25 ప్రశ్న 25Answer: A. 13.0 m3. సమాధానం: A.
