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Question 1
ప్రశ్న 1
What is the principal purpose of an energy dissipator downstream of a spillway carrying high-velocity flow?
Explanation:
Water descending a spillway can convert a large part of its available head into kinetic energy. If that high-velocity flow reaches an erodible downstream bed without adequate treatment, severe scour and undermining can occur. Energy dissipators reduce, redistribute, or safely relocate this excess energy before the flow can threaten the structure or downstream channel. Hydraulic-jump stilling basins and bucket-type arrangements achieve this objective by different hydraulic mechanisms. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
For an uncontrolled overflow spillway, use Q = C L H^(3/2). If C = 2.10, effective crest length L = 18 m and total head H = 2.5 m, what is the discharge?
Explanation:
The supplied discharge relation is Q = C L H^(3/2). For H = 2.5 m, H^(3/2) is approximately 3.953. Substituting gives Q = 2.10 × 18 × 3.953. The resulting discharge is approximately 149.4 m³/s. No external coefficient table is required because the value of C is supplied in the question. Therefore Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
At the spillway head-measurement section, the static water head above the crest is 3.0 m and the average approach velocity is 4.0 m/s. Taking g = 9.81 m/s² and using total head H = h + V²/(2g), what total head should be used in the stated idealized discharge relation?
Explanation:
The approach-velocity head is V²/(2g). With V = 4.0 m/s, it equals 16/(2 × 9.81), or approximately 0.815 m. Adding this to the 3.0 m static head gives a total head of approximately 3.815 m. Rounded suitably, the value is about 3.82 m. This illustrates why appreciable approach velocity should not automatically be ignored in a total-head formulation. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
Why can poor or highly nonuniform approach conditions upstream of an ogee spillway affect its hydraulic performance?
Explanation:
Spillway discharge depends on more than the static water depth above the crest. Appreciable approach velocity contributes to the total energy head available to the flow. Poor alignment or nonuniform approach flow can also produce uneven velocity distribution, separation, and localized contractions. These effects can alter the effective discharge coefficient and the distribution of flow over the crest. Consequently approach geometry and velocity conditions are important parts of spillway hydraulic design. Therefore Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
For the same effective crest length and discharge coefficient, an uncontrolled spillway follows Q proportional to H^(3/2). If the head increases from 2.0 m to 2.5 m, by approximately what factor does the discharge increase?
Explanation:
The ratio of the two discharges is (H2/H1)^(3/2). Substituting the stated heads gives (2.5/2.0)^(3/2). This is 1.25^(3/2), which is approximately 1.398. The discharge therefore becomes about 1.40 times its original value. The result demonstrates the nonlinear sensitivity of overflow discharge to crest head. Therefore Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
Why does spillway flow commonly require substantial downstream protection after descending through a large elevation difference?
Explanation:
As water descends from the reservoir to a much lower downstream elevation, gravitational potential energy is converted into kinetic energy. The resulting velocities can be very high at the toe of a steep spillway or chute. High-velocity jets can scour riverbed material, erode banks, and undermine spillway or dam foundations. Energy dissipation and appropriate downstream protection are therefore needed to reduce or safely relocate these erosive effects. The required treatment depends on discharge, velocity, tail-water, geology, and downstream channel conditions. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
At a section of spillway flow, the depth is 1.2 m and the average velocity is 12 m/s. Neglecting elevation datum effects at that section, what is the specific energy E = y + V²/(2g), taking g = 9.81 m/s²?
Explanation:
Specific energy is the flow depth plus the velocity head when measured relative to the channel bed. The velocity head is 12²/(2 × 9.81), which is approximately 7.34 m. Adding the 1.2 m flow depth gives approximately 8.54 m. The large velocity-head component illustrates the high kinetic energy that can exist in spillway flow. Such energy must be considered when designing downstream dissipation and protection works. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
A rectangular spillway channel carries water 1.0 m deep at a velocity of 10 m/s. Using Fr = V/sqrt(g y) with g = 9.81 m/s², what is the Froude number and flow regime?
Explanation:
For the stated rectangular flow, Fr = 10/sqrt(9.81 × 1.0). The denominator is approximately 3.132, giving Fr ≈ 3.19. A Froude number greater than one identifies supercritical flow. Such rapid shallow flow is typical of many spillway chutes approaching an energy dissipator. A hydraulic jump can convert this supercritical flow into a deeper subcritical state when suitable downstream conditions are available. Therefore Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
Which description best characterizes a hydraulic jump used for spillway energy dissipation?
Explanation:
A hydraulic jump forms when rapid supercritical flow changes to a deeper subcritical state. The transition contains intense turbulence, surface rollers, air entrainment, and mixing. A substantial amount of excess mechanical energy is dissipated during this process. Stilling basins are designed to form and contain this jump where its turbulence can be safely accommodated. The hydraulic jump therefore converts dangerous high-velocity flow into a more manageable downstream condition. Therefore Option A is correct.
వివరణ:
Question 10
ప్రశ్న 10
For a hydraulic jump in a horizontal rectangular channel, use y2/y1 = 0.5[sqrt(1 + 8Fr1²) - 1]. If y1 = 1.0 m and Fr1 = 4.0, what is the sequent depth y2?
Explanation:
The supplied sequent-depth relation gives y2/y1 = 0.5[sqrt(1 + 8 × 4²) - 1]. The term under the square root is 129, whose square root is approximately 11.358. The depth ratio is therefore approximately 0.5(11.358 - 1) = 5.179. Since y1 is 1.0 m, y2 is approximately 5.18 m. This is the conjugate depth required by the ideal momentum relation for the stated incoming flow. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
For an ideal hydraulic jump in a horizontal rectangular channel, use ΔE = (y2 - y1)^3/(4 y1 y2). If y1 = 1.0 m and y2 = 4.0 m, what is the specific-energy loss?
Explanation:
The difference in conjugate depths is 4.0 - 1.0 = 3.0 m. Cubing this value gives 27 m³. The denominator is 4 × 1.0 × 4.0 = 16 m². Therefore ΔE = 27/16 = 1.6875 m, or approximately 1.69 m. This lost specific energy is converted mainly into turbulence, mixing, heat, and air entrainment within the jump. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
For a conventional hydraulic-jump stilling basin, which tail-water condition is generally most favorable for forming the intended jump near the basin location?
Explanation:
The downstream depth needed after a hydraulic jump is related to the incoming supercritical flow through the momentum relation. If the actual tail-water depth is close to this sequent depth, the jump can form near its intended basin position. This helps the basin contain the turbulent region and protects the downstream bed. Significant mismatch between tail-water and required conjugate depth can shift or alter the jump. Therefore tail-water characteristics over the operating range are a major criterion in stilling-basin selection and design. Therefore Option D is correct.
వివరణ:
Question 13
ప్రశ్న 13
What is a likely consequence if the available tail-water depth is substantially lower than the conjugate depth required for a hydraulic jump at the spillway toe?
Explanation:
A hydraulic jump requires adequate downstream depth to support its deeper subcritical state. If the tail-water level is too low, the required conjugate depth is not available at the intended basin location. The jump may therefore move or sweep downstream from the protected apron. High velocities and severe turbulence can then reach unprotected bed material. Such a condition can cause scour, undermining, and damage to downstream structures. Therefore Option A is correct.
వివరణ:
Question 14
ప్రశ్న 14
What is the most appropriate interpretation when tail-water is substantially greater than the depth required for a free hydraulic jump?
Explanation:
Excessive tail-water can submerge the normal surface roller of a free hydraulic jump. The jump is then commonly described as submerged or drowned. Energy is still dissipated, but the location, turbulence pattern, pressures, and efficiency can differ from the intended free-jump condition. Basin geometry and operating performance should therefore be checked over the expected tail-water range. High tail-water is not automatically unsafe, but it cannot be ignored in energy-dissipator design. Therefore Option B is correct.
వివరణ:
Question 15
ప్రశ్న 15
What is the purpose of chute blocks, baffle blocks and end sills when they are appropriately incorporated into a hydraulic-jump stilling basin?
Explanation:
Stilling-basin appurtenances modify the momentum and turbulence of the incoming high-velocity flow. Chute blocks can split and disturb the entering jet, while baffle blocks can provide additional resistance within suitable basin designs. End sills can help control the downstream flow pattern and retain the jump within the basin. These devices can improve performance or reduce the required basin dimensions when they are used within an appropriate proven design range. Their dimensions and use must still account for structural loads, cavitation potential, and hydraulic performance. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
Which site condition most strongly favors consideration of a hydraulic-jump stilling basin rather than projecting the spillway jet far downstream?
Explanation:
A hydraulic-jump basin works efficiently when downstream water depth can support a stable jump at the designed location. A protected concrete apron can contain the intense turbulence and keep it away from erodible natural bed material. This arrangement is particularly attractive where it is preferable to dissipate the energy close to the spillway toe under controlled conditions. If tail-water is much too low, maintaining the jump within a conventional basin may become difficult or uneconomical. Therefore the stated combination of adequate tail-water and downstream scour vulnerability favors the stilling-basin alternative. Therefore Option C is correct.
వివరణ:
Question 17
ప్రశ్న 17
Under IS 7365 terminology, which two broad classes of bucket-type energy dissipators are recognized?
Explanation:
Bucket-type energy dissipators use a curved terminal arrangement at the downstream end of a spillway or chute. IS 7365 broadly distinguishes roller-bucket arrangements from trajectory or flip-bucket arrangements. Roller buckets rely substantially on roller action involving the bucket and tail-water region. Trajectory buckets instead project the high-velocity jet into the air and move the major downstream impact away from the structure. These two concepts respond to different tail-water and downstream geological conditions. Therefore Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
Which hydraulic condition is particularly associated with a solid roller bucket?
Explanation:
A solid roller bucket is an upturned bucket arrangement intended to operate with substantial downstream water depth. The interaction of the issuing flow with the high tail-water produces characteristic roller circulation. Energy is dissipated through intense turbulence and the complementary roller system in and downstream of the bucket. IS 7365 associates the solid roller-bucket concept particularly with tail-water depths well above the ordinary sequent-depth condition. Its hydraulic behavior is therefore fundamentally different from that of a free trajectory bucket. Therefore Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
Which combination of conditions most strongly favors a trajectory or flip-bucket dissipator?
Explanation:
A trajectory bucket is especially useful when available tail-water is too low to sustain a hydraulic jump at the spillway toe. The bucket turns the high-velocity flow upward and projects it downstream as a free jet. Sound rock and adequate downstream space are desirable because the plunging jet can generate a significant scour hole or plunge pool. The impact zone must be sufficiently far from the dam and other structures so that such scour does not threaten their safety. This arrangement can reduce the need for a long excavated stilling basin in favorable rocky terrain. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
Which statement most accurately describes the energy-dissipation mechanism of a flip or ski-jump bucket?
Explanation:
A flip bucket should not be interpreted as a device that consumes most of the spillway energy within its own short curved surface. Its principal hydraulic role is to change the trajectory of the high-velocity jet. Some energy is lost through air interaction and jet breakup during flight, but substantial energy usually remains at impact. Major dissipation then occurs in the tail-water, plunge pool, and scour region downstream. The purpose is therefore to relocate the most severe energy effects to a site where they will not endanger the dam or spillway. Therefore Option D is correct.
వివరణ:
Question 21
ప్రశ్న 21
A spillway discharges 360 m³/s through a 24 m wide rectangular chute. What is the discharge intensity, or unit discharge q = Q/b?
Explanation:
Unit discharge is the total discharge divided by the effective flow width. Here q = 360/24. This gives 15 m³/s per metre of chute width, conventionally written as 15 m²/s. Unit discharge is useful because it relates total spillway flow to the hydraulic loading carried by each unit width. It is an important quantity in estimating flow depth, velocity, energy-dissipator loading, and scour potential. Therefore Option B is correct.
వివరణ:
Question 22
ప్రశ్న 22
The unit discharge entering a stilling basin is 15 m²/s and the incoming flow depth is 1.5 m. Assuming a rectangular section and uniform velocity, what is the average velocity?
Explanation:
For a rectangular channel of unit width, unit discharge equals velocity multiplied by flow depth. Thus V = q/y. Substituting q = 15 m²/s and y = 1.5 m gives V = 10 m/s. Such a velocity represents substantial kinetic energy entering the stilling basin. The corresponding Froude number and conjugate depth would then be relevant to hydraulic-jump design. Therefore Option C is correct.
వివరణ:
Question 23
ప్రశ్న 23
A high-velocity spillway flow enters an energy dissipator at 10 m/s. Taking g = 9.81 m/s², what is its velocity head V²/(2g)?
Explanation:
The velocity head is V²/(2g). For V = 10 m/s, the numerator is 100 m²/s². Dividing by 19.62 m/s² gives approximately 5.10 m. This value represents the kinetic-energy head associated with the mean flow velocity. A large velocity head helps explain why spillway toe flows can be highly erosive if they are not adequately dissipated or redirected. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
A hydraulic jump carries Q = 100 m³/s and dissipates 4.0 m of specific energy. Using water density 1000 kg/m³ and g = 9.81 m/s², what is the approximate rate of mechanical-energy dissipation, P = rho g Q ΔE?
Explanation:
The rate of energy dissipation is P = rho g Q ΔE. Substitution gives P = 1000 × 9.81 × 100 × 4.0 watts. The result is 3,924,000 W. Converting to megawatts gives 3.924 MW. This large power loss occurs through intense turbulent motion, air entrainment, eddies, and mixing within the jump. Therefore Option D is correct.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about spillway energy dissipation: I. A hydraulic-jump basin is strongly influenced by the relation between available tail-water and required sequent depth. II. A flip bucket principally projects the jet away from the structure rather than dissipating all energy within the bucket. III. High residual velocities downstream can require bed or bank protection even after an energy dissipator. IV. Geology, tail-water, discharge intensity and scour risk are important when selecting an energy-dissipation arrangement. Which option is correct?
Explanation:
Statement I is correct because a stable hydraulic jump depends strongly on the available downstream depth relative to the required conjugate depth. Statement II is correct because a flip bucket mainly redirects the high-velocity jet and shifts the principal impact and dissipation zone downstream. Statement III is correct because no dissipator should be assumed to reduce every downstream velocity or local erosive action to zero. Statement IV is correct because energy-dissipator selection must consider hydraulic loading together with tail-water and the resistance of the downstream foundation and channel. Therefore all four statements are correct and Option B is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. To reduce the excessive kinetic energy of the released water so that downstream scour and structural damage are controlled సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. Approximately 149.4 m³/s సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. Approximately 3.82 m సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. Because approach velocity, flow distribution, separation and contractions can influence the effective head and discharge coefficient సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. 1.40 సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. Because a large part of the available head can appear as high flow velocity capable of causing severe bed and bank erosion సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. Approximately 8.54 m సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. Fr ≈ 3.19, supercritical సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: A. An abrupt transition from supercritical to subcritical flow accompanied by strong turbulence and substantial loss of mechanical energy సమాధానం: A.
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Question 10 ప్రశ్న 10Answer: C. Approximately 5.18 m సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. Approximately 1.69 m సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. Available tail-water should approximately match the required conjugate or sequent depth for the design condition సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: A. The jump may sweep downstream beyond the intended basin, leaving high-velocity flow capable of causing scour సమాధానం: A.
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Question 14 ప్రశ్న 14Answer: B. The jump can become submerged or drowned, and basin performance should be checked for the resulting flow condition సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: A. To assist jump formation and stabilization, increase turbulence or resistance, and help reduce the basin length or downstream velocity where the adopted design permits సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: C. Adequate tail-water close to the required sequent depth and a need to dissipate energy on a protected apron before flow reaches an erodible channel సమాధానం: C.
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Question 17 ప్రశ్న 17Answer: B. Roller-bucket type and trajectory or flip-bucket type సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. Tail-water sufficiently high, commonly substantially above the sequent-depth condition, so that strong roller action develops around the bucket సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: A. Tail-water too low to form the desired hydraulic jump, sound downstream rock, and sufficient distance for the projected jet to land safely away from the structure సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: D. The bucket mainly redirects and projects the jet so that much of the remaining energy is dissipated during jet breakup and in the downstream plunge or impact region సమాధానం: D.
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Question 21 ప్రశ్న 21Answer: B. 15 m²/s సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: C. 10 m/s సమాధానం: C.
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Question 23 ప్రశ్న 23Answer: A. Approximately 5.10 m సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: D. 3.924 MW సమాధానం: D.
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Question 25 ప్రశ్న 25Answer: B. I, II, III and IV సమాధానం: B.
