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Question 1
ప్రశ్న 1
Which statement correctly describes the current IS 800:2007 design approach for a simple rolled steel beam?
Explanation:
IS 800:2007 is principally a Limit State design code for structural steel. A beam must possess adequate strength against relevant bending, shear and stability limit states. Serviceability requirements such as deflection must also be satisfied under the appropriate service-load combinations. Laterally unsupported beams require consideration of lateral-torsional buckling rather than only cross-sectional bending resistance. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
Which Indian Standard is primarily used to obtain standard dimensions and sectional properties of hot-rolled steel beam, column, channel and angle sections?
Explanation:
IS 808:2021 covers the standard dimensions and sectional properties of hot-rolled beam, column, channel and angle sections. Its tables provide information such as dimensions, mass, area, moments of inertia and radii of gyration for standardized sections. These geometrical properties are then used with the structural design provisions of IS 800. IS 800 is a design code rather than the primary dimensional table for rolled sections. Therefore Option A is correct.
వివరణ:
Question 3
ప్రశ్న 3
A conventional rolled I-beam is placed with its web vertical and carries downward gravity loads. About which axis does it normally resist its principal bending?
Explanation:
With the web vertical, downward transverse loading produces bending in the vertical plane of the web. The corresponding bending axis through the section is the strong or major centroidal axis. Rolled I-sections have a much larger second moment of area about this axis because their flanges are located far from it. This makes them efficient for carrying vertical bending moments. Therefore Option C is correct.
వివరణ:
Question 4
ప్రశ్న 4
Which expression defines the elastic section modulus Ze of a beam cross-section about a specified bending axis?
Explanation:
The elastic flexure relation is sigma = My/I. At the extreme fibre, y becomes ymax. The expression can then be written as sigma_max = M/Ze when Ze is defined as I/ymax. Elastic section modulus therefore measures the ability of the section to resist elastic bending stress about the selected axis. Therefore Option B is correct.
వివరణ:
Question 5
ప్రశ్న 5
A rolled beam has second moment of area I = 120 × 10^6 mm^4 about its major axis. Its extreme fibre is 200 mm from the neutral axis. What is its elastic section modulus about that axis?
Explanation:
The elastic section modulus is Ze = I/ymax. Substituting the supplied values gives 120 × 10^6 divided by 200. The result is 600000 mm^3. This is equal to 600 × 10^3 mm^3. Therefore Option D is correct.
వివరణ:
Question 6
ప్రశ్న 6
How does IS 800 section classification affect the bending resistance expression of a laterally supported rolled beam under low shear?
Explanation:
Plastic and compact sections have sufficiently stocky compression elements to develop the plastic stress distribution assumed in plastic bending resistance. IS 800 therefore uses beta_b = 1.0 for these classes in the basic bending-strength expression. For a semi-compact section, beta_b is taken as Ze/Zp, which reduces the expression effectively to an elastic-section-modulus basis. Slender sections require further treatment because local buckling prevents full utilization of the gross section. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
A laterally supported compact simply supported rolled beam has Zp = 850 × 10^3 mm^3, Ze = 760 × 10^3 mm^3, fy = 250 MPa and gamma_m0 = 1.10. The design shear is below 0.6Vd. Using Md = Zp fy/gamma_m0 subject to the simply supported beam limit Md not exceeding 1.2Ze fy/gamma_m0, what design bending strength governs?
Explanation:
For a compact section beta_b is 1.0, so the basic plastic bending strength is Zp fy/gamma_m0. This gives 850000 × 250/1.10 = approximately 193.2 kN·m. For the stated simply supported beam, the serviceability-related upper limit is 1.2 × 760000 × 250/1.10 = approximately 207.3 kN·m. The lower of these two values is 193.2 kN·m. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
A laterally supported semi-compact beam has Zp = 900 × 10^3 mm^3, Ze = 800 × 10^3 mm^3, fy = 250 MPa and gamma_m0 = 1.10. Neglect high-shear effects. What design bending strength follows from beta_b = Ze/Zp?
Explanation:
For a semi-compact section, beta_b is Ze/Zp. Hence beta_b Zp reduces directly to Ze in the bending-strength expression. The design strength is therefore 800000 × 250/1.10 = 181.82 × 10^6 N·mm. This equals approximately 181.8 kN·m. Therefore Option B is correct.
వివరణ:
Question 9
ప్రశ్న 9
A rolled beam has an effective shear area Av = 3000 mm^2, web yield stress fyw = 250 MPa and gamma_m0 = 1.10. Assuming shear yielding governs and shear buckling does not, what is Vd = Av fyw/(sqrt(3) gamma_m0)?
Explanation:
The nominal plastic shear resistance is based on Av fyw divided by the square root of three. The design value is further divided by gamma_m0. Substitution gives 3000 × 250/[sqrt(3) × 1.10]. This evaluates to approximately 393.6 kN. Therefore Option C is correct.
వివరణ:
Question 10
ప్రశ్న 10
For the beam in the previous question with Vd = 393.6 kN, above what factored shear force does the IS 800 high-shear interaction provision begin to affect the ordinary bending-strength calculation?
Explanation:
IS 800 distinguishes low shear from high shear using 0.6Vd. Here Vd is 393.6 kN. Multiplying by 0.6 gives approximately 236.2 kN. When the factored shear exceeds this level, the ordinary low-shear bending strength cannot simply be used without the prescribed interaction reduction. Therefore Option D is correct.
వివరణ:
Question 11
ప్రశ్న 11
What is the principal consequence when the factored shear in a steel beam exceeds 0.6Vd?
Explanation:
A large shear force consumes part of the yielding capacity of the web. When the design shear exceeds 0.6Vd, IS 800 therefore requires interaction between shear and bending to be considered. The bending resistance may be reduced according to the applicable high-shear provisions. This does not mean that the beam automatically fails as soon as the 0.6Vd threshold is crossed. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
A simply supported steel beam of span 6 m carries a factored uniformly distributed load of 30 kN/m over its entire span. What are the maximum factored bending moment and support shear respectively?
Explanation:
For a simply supported beam under full-span UDL, the maximum bending moment is wL^2/8. Substitution gives 30 × 6^2/8 = 135 kN·m. Each support reaction and the maximum end shear equal wL/2. That value is 30 × 6/2 = 90 kN. Therefore Option C is correct.
వివరణ:
Question 13
ప్రశ్న 13
A laterally supported compact beam must resist a factored bending moment of 180 kN·m. Take fy = 250 MPa and gamma_m0 = 1.10, and assume the applicable section-modulus upper limit does not govern. What minimum plastic section modulus Zp is required from Md = Zp fy/gamma_m0?
Explanation:
Rearranging the bending-strength equation gives Zp = Md gamma_m0/fy. The applied moment of 180 kN·m is 180 × 10^6 N·mm. Hence Zp = 180 × 10^6 × 1.10/250. The result is 792000 mm^3, or 792 × 10^3 mm^3. Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
A simply supported steel beam of span 8 m carries a factored concentrated load of 120 kN at midspan. What are the maximum bending moment and maximum support shear?
Explanation:
For a central point load on a simply supported beam, each support reaction is P/2. The maximum support shear is therefore 120/2 = 60 kN. The maximum bending moment occurs at midspan and equals PL/4. This gives 120 × 8/4 = 240 kN·m. Therefore Option D is correct.
వివరణ:
Question 15
ప్రశ్న 15
A simply supported steel beam has span 6 m, service UDL 12 kN/m, E = 2.0 × 10^5 N/mm^2 and I = 180 × 10^6 mm^4. Using delta_max = 5wL^4/(384EI), what is the maximum elastic deflection?
Explanation:
The distributed load of 12 kN/m is numerically 12 N/mm. The span is 6000 mm. Substituting the supplied data into 5wL^4/(384EI) gives approximately 5.625 mm. Rounded suitably, the maximum elastic deflection is 5.63 mm. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
Which statement correctly reflects the amended IS 800:2007 serviceability procedure for beam deflection?
Explanation:
Beam deflection is a serviceability rather than a collapse check. IS 800 requires the most adverse but realistic arrangement of service loads to be considered using elastic analysis. Amendment No. 1 changed Clause 5.6.1 so that the load factors are taken from Table 4 rather than using a universal statement that every load factor is simply 1.0. Many ordinary serviceability combinations contain factors of 1.0, while accompanying actions in some combinations can have different Table 4 factors. Therefore Option C is correct.
వివరణ:
Question 17
ప్రశ్న 17
What is lateral-torsional buckling of a steel beam?
Explanation:
A beam bending about its major axis develops a compression flange. If that compression flange lacks adequate lateral restraint over a sufficient length, it can move sideways. Because the two flanges and web are connected, this lateral displacement is accompanied by twisting of the section. The resulting instability is termed lateral-torsional buckling and can reduce member bending strength below its cross-sectional resistance. Therefore Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
A simply supported laterally unsupported compact rolled beam has Zp = 900 × 10^3 mm^3, Ze = 800 × 10^3 mm^3, fy = 250 MPa and gamma_m0 = 1.10. If its lateral-torsional buckling reduction factor is chi_LT = 0.75, use fbd = chi_LT fy/gamma_m0 and Md = Zp fbd. What design bending strength is obtained?
Explanation:
The design bending compressive stress is fbd = 0.75 × 250/1.10 = approximately 170.45 MPa. For a compact section, beta_b is 1.0. The lateral-torsional-buckling design moment is therefore 900000 × 170.45 = approximately 153.4 × 10^6 N·mm. This is 153.4 kN·m and is lower than the corresponding cross-sectional bending resistance for the supplied data. Therefore Option D is correct.
వివరణ:
Question 19
ప్రశ్న 19
Which condition most directly improves the lateral-torsional buckling resistance of a rolled steel beam?
Explanation:
Lateral-torsional buckling depends strongly on the ability of the compression flange to move sideways and on the beam's ability to twist. Effective lateral restraints suppress this movement at restraint points. Reducing the unrestrained length therefore generally increases the member's lateral stability and its usable bending resistance. Simply increasing unrestrained length would have the opposite effect. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
An unstiffened beam web has clear depth d = 600 mm, thickness tw = 8 mm and web yield stress fyw = 250 MPa. Taking epsilon_w = sqrt(250/fyw) = 1.0, what does the IS 800 criterion d/tw > 67epsilon_w indicate?
Explanation:
The web slenderness is d/tw = 600/8 = 75. With web yield stress fyw = 250 MPa, epsilon_w = sqrt(250/250) = 1.0. The unstiffened-web shear-buckling trigger is therefore 67epsilon_w = 67. Since 75 exceeds 67, the web shear-buckling resistance has to be verified instead of assuming that simple plastic shear yielding alone governs. Therefore Option C is correct.
వివరణ:
Question 21
ప్రశ్న 21
What is the purpose of the shear area Av used in the IS 800 shear-strength calculation of an I-beam?
Explanation:
Vertical shear in an I-section is carried predominantly by its web. IS 800 therefore defines an appropriate shear area rather than simply using the entire gross cross-sectional area in the plastic shear expression. For rolled I-sections under major-axis shear, the code provides the corresponding web-based shear-area rule. This area is used with the web yield stress in evaluating shear resistance. Therefore Option B is correct.
వివరణ:
Question 22
ప్రశ్న 22
A large concentrated reaction acts on a rolled steel beam near a support. Which additional web behaviour may require checking apart from the overall beam shear capacity?
Explanation:
A concentrated reaction introduces a high localized compressive force into the beam web near the loaded flange. Even if the beam possesses sufficient overall shear strength, the web can experience local bearing or yielding. Slender webs may also buckle or cripple locally in the load-introduction region. Bearing stiffeners or other detailing may be required where the unstiffened web is inadequate. Therefore Option D is correct.
వివరణ:
Question 23
ప్రశ్న 23
Which sequence represents a sound preliminary procedure for selecting a simple rolled steel beam?
Explanation:
Beam selection begins with determining the relevant design bending moments, shears and service actions. A trial rolled section can then be chosen using section-modulus and other preliminary requirements. Its cross-section classification, bending strength, shear strength and lateral stability must be verified. Serviceability requirements such as deflection are then checked together with web, connection and detailing considerations. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
A laterally supported compact simply supported beam has Md = 193.2 kN·m and Vd = 393.6 kN. It is subjected to factored moment M = 175 kN·m and factored shear V = 180 kN. Its service deflection is 18 mm against a specified limit of 20 mm. Which conclusion is correct, assuming no other limit state governs?
Explanation:
The applied factored moment of 175 kN·m is below the design bending strength of 193.2 kN·m. The applied shear of 180 kN is below Vd = 393.6 kN. It is also below 0.6Vd, which is approximately 236.2 kN, so the high-shear bending reduction is not triggered by the stated shear. The service deflection of 18 mm is less than the specified 20 mm limit. Therefore Option C is correct under the assumptions stated.
వివరణ:
Question 25
ప్రశ్న 25
Under the IS 800 lateral-restraint guidance for a gravity-loaded beam, when may a floor connection to the compression flange be considered capable of providing full lateral restraint, subject to the stated code conditions?
Explanation:
IS 800 gives a practical criterion for recognizing full lateral restraint from a floor connection under the conditions stated in the code. The frictional or other positive restraint should be capable of resisting a lateral force not less than 2.5 percent of the maximum force in the compression flange. The floor construction itself must also be capable of resisting the resulting lateral force. The provision applies where gravity loads constitute the dominant loading and should not be detached from those qualifications. Therefore Option B is correct.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Strength and serviceability limit states are checked using the Limit State framework, with member stability also considered where relevant సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: A. IS 808:2021 సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: C. About its major centroidal axis సమాధానం: C.
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Question 4 ప్రశ్న 4Answer: B. Ze = I/ymax సమాధానం: B.
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Question 5 ప్రశ్న 5Answer: D. 600 × 10^3 mm^3 సమాధానం: D.
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Question 6 ప్రశ్న 6Answer: C. Plastic and compact sections may use the plastic section modulus subject to code limits, while semi-compact sections are limited essentially by the elastic section modulus సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. 193.2 kN·m సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: B. 181.8 kN·m సమాధానం: B.
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Question 9 ప్రశ్న 9Answer: C. 393.6 kN సమాధానం: C.
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Question 10 ప్రశ్న 10Answer: D. Approximately 236.2 kN సమాధానం: D.
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Question 11 ప్రశ్న 11Answer: A. The bending strength may have to be reduced to account for interaction between high shear and bending సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: C. 135 kN·m and 90 kN సమాధానం: C.
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Question 13 ప్రశ్న 13Answer: B. 792 × 10^3 mm^3 సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: D. 240 kN·m and 60 kN సమాధానం: D.
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Question 15 ప్రశ్న 15Answer: A. 5.63 mm సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: C. Deflection is checked by elastic analysis for the most adverse but realistic service-load combinations, using the applicable serviceability load factors given in Table 4 సమాధానం: C.
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Question 17 ప్రశ్న 17Answer: B. An instability in which the compression region moves laterally and the beam twists as bending resistance is lost సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: D. 153.4 kN·m సమాధానం: D.
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Question 19 ప్రశ్న 19Answer: A. Providing effective lateral restraint to the compression flange and reducing its unrestrained length సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: C. d/tw = 75, which exceeds 67, so shear-buckling resistance of the web requires verification సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: B. It represents the effective portion of the cross-section principally participating in resistance to vertical shear సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: D. Local web bearing, yielding or buckling/crippling beneath the concentrated force సమాధానం: D.
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Question 23 ప్రశ్న 23Answer: A. Determine design actions, choose a trial rolled section, classify it, check bending and shear including stability, then verify serviceability and detailing సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: C. It satisfies the stated bending, shear and deflection checks, and the shear is below the high-shear threshold సమాధానం: C.
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Question 25 ప్రశ్న 25Answer: B. When positive restraint can resist a lateral force of at least 2.5 percent of the maximum compression-flange force, with the floor system capable of carrying that restraint force సమాధానం: B.
