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Question 1
ప్రశ్న 1
A circular pile carries axial compression in a soil profile where both positive shaft resistance and toe resistance can develop. Which expression correctly represents the idealized ultimate geotechnical resistance of the individual pile?
Explanation:
Ultimate axial resistance is commonly evaluated by combining end-bearing and positive shaft contributions. Toe resistance is developed beneath the pile base. Shaft resistance develops through interaction between the shaft and surrounding soil. The idealized expression is Qu = Qb + Qs when the contributions are consistently evaluated. Mobilization at different displacements, installation effects and structural resistance must also be considered in practical design.
వివరణ:
Question 2
ప్రశ్న 2
In the alpha-method for estimating the ultimate positive shaft resistance of a pile embedded in saturated clay under undrained loading, what does the adhesion factor alpha represent?
Explanation:
The alpha-method estimates positive unit shaft resistance in clay as fs = alpha cu. The parameter cu denotes the relevant undrained shear strength. The dimensionless adhesion factor alpha reflects soil-pile interaction and installation effects. Its value is not necessarily unity and should be selected from appropriate site information or applicable guidance. Ultimate shaft resistance is obtained by integrating this unit resistance over the contributing shaft area.
వివరణ:
Question 3
ప్రశ్న 3
A circular pile of diameter 0.60 m is embedded 10 m in uniform saturated clay. For this idealized undrained calculation, use cu = 50 kPa along the shaft and at the toe, alpha = 0.60, Nc = 9, and Qu = (pi d²/4)Nc cu + pi d L alpha cu. If factor of safety = 2.5 and pi = 3.1416, what is the allowable axial compression resistance?
Explanation:
The pile base area is pi(0.60)²/4 = approximately 0.28274 m². The ultimate toe resistance is 0.28274(9)(50) = approximately 127.23 kN. The ultimate shaft resistance is pi(0.60)(10)(0.60)(50) = approximately 565.49 kN. Therefore the combined ultimate resistance is approximately 692.72 kN. Dividing by the specified factor of safety of 2.5 gives an allowable resistance of approximately 277.1 kN.
వివరణ:
Question 4
ప్రశ్న 4
A circular pile of diameter 0.40 m passes through 4 m of clay having cu = 40 kPa and alpha = 0.80, followed by 6 m of clay having cu = 70 kPa and alpha = 0.50. The undrained toe strength is 70 kPa, and Nc = 9. Using Qu = (pi d²/4)Nc cu,toe + pi d sum(alpha_i cu,i Li), with pi = 3.1416, what is the ultimate axial resistance?
Explanation:
Each soil layer contributes shaft resistance using its own adhesion factor and undrained strength. The upper-layer contribution is pi(0.40)(4)(0.80)(40) = approximately 160.85 kN. The lower-layer contribution is pi(0.40)(6)(0.50)(70) = approximately 263.89 kN. The toe contribution is [pi(0.40)²/4](9)(70) = approximately 79.17 kN. Adding these three components gives approximately 503.9 kN ultimate axial resistance.
వివరణ:
Question 5
ప్రశ్న 5
An individual pile has a toe area of 0.20 m² in saturated clay with undrained toe strength cu = 90 kPa. If the specified undrained toe bearing factor Nc = 9, what is its idealized ultimate toe resistance Qb = Ap Nc cu?
Explanation:
The idealized undrained toe resistance is calculated from the toe area multiplied by Nc and cu. The given toe area is 0.20 m². Multiplying 0.20 by 9 and 90 kPa gives 162 kN. This value represents only the ultimate toe contribution. Positive shaft resistance, allowable load and settlement are separate matters requiring additional evaluation.
వివరణ:
Question 6
ప్రశ్న 6
An instrumented pile in uniform clay has an ultimate positive shaft resistance of 360 kN over a contributing shaft area of 12 m². The representative undrained strength is cu = 50 kPa. Under the uniform alpha-method relation Qs = alpha cu As, what is the inferred adhesion factor?
Explanation:
The unit shaft resistance equals the ultimate shaft load divided by the contributing shaft area. This gives 360/12 = 30 kPa. The alpha-method relation is fs = alpha cu. Therefore alpha = 30/50 = 0.60. This is an inferred value for the supplied conditions and must not automatically be assigned to different clays or pile-installation methods.
వివరణ:
Question 7
ప్రశ్న 7
A designer applies the alpha-method to piles in two clays with different undrained strengths. Which statement about predicting shaft resistance is technically correct?
Explanation:
The alpha-method links unit shaft adhesion to undrained strength through an empirical coefficient. That coefficient depends on the characteristics of the soil-pile interface and other relevant conditions. Consequently two clays with different strengths need not have the same adhesion factor. Using the same coefficient without justification can overestimate or underestimate shaft resistance. Appropriate correlations, site investigation and load-test information should inform the adopted values.
వివరణ:
Question 8
ప్రశ్న 8
A cylindrical pile with diameter d = 0.50 m mobilizes shaft friction along 10 m of sand. Using the prescribed effective-stress expression Qs = pi d L K sigma_v,avg tan(delta), take K = 1.20, average vertical effective stress = 100 kPa, and tan(delta) = 0.50. What is the ultimate positive shaft resistance? Use pi = 3.1416.
Explanation:
The assumed effective-stress unit shaft resistance is K sigma_v,avg tan(delta). Substituting gives 1.20(100)(0.50) = 60 kPa. The contributing shaft area is pi(0.50)(10) = approximately 15.708 m². Multiplication gives Qs = 60(15.708) = approximately 942.5 kN. The result is an ultimate shaft contribution under the specified simplified assumptions.
వివరణ:
Question 9
ప్రశ్న 9
A 0.50 m diameter pile has two 5 m shaft segments in sand. In both layers K = 1.0 and tan(delta) = 0.50, but average vertical effective stresses are 50 kPa and 150 kPa, respectively. Using Qs = pi d sum(Li Ki sigma_v,i tan(delta_i)) and pi = 3.1416, calculate total ultimate shaft resistance.
Explanation:
The average shaft friction in the first segment is 1(50)(0.50) = 25 kPa. Its 5 m segment area is pi(0.50)(5), giving approximately 196.35 kN. The second segment has unit friction 1(150)(0.50) = 75 kPa and contributes approximately 589.05 kN. Summing the two shaft contributions gives about 785.4 kN. It would be incorrect to apply the deeper layer stress to the entire embedded length.
వివరణ:
Question 10
ప్రశ్న 10
A circular pile with diameter D = 0.60 m is founded in sand. For the specified static toe-resistance expression Qb = Ap[0.5 D gamma_eff Ngamma + sigma_v,toe Nq], take gamma_eff = 10 kN/m³, Ngamma = 20, sigma_v,toe = 150 kPa and Nq = 25. Using pi = 3.1416, what is the ultimate toe resistance?
Explanation:
The toe area is Ap = pi(0.60)²/4 = approximately 0.28274 m². The soil-weight component of toe pressure is 0.5(0.60)(10)(20) = 60 kPa. The effective-overburden component is 150(25) = 3750 kPa. Their sum is an ultimate unit toe resistance of 3810 kPa. Multiplication by the base area gives approximately 1077.3 kN ultimate toe resistance.
వివరణ:
Question 11
ప్రశ్న 11
A 0.50 m diameter pile penetrates 8 m into sand. Use Qb = (pi d²/4)[0.5 d gamma_eff Ngamma + sigma_v,toe Nq] and Qs = pi d L K sigma_v,avg tan(delta). Take gamma_eff = 10 kN/m³, Ngamma = 15, sigma_v,toe = 120 kPa, Nq = 20, K = 1.0, sigma_v,avg = 70 kPa, tan(delta) = 0.50, and factor of safety = 2.5. What are the ultimate and allowable compression resistances, respectively?
Explanation:
The ultimate toe pressure is 0.5(0.50)(10)(15) + 120(20) = 2437.5 kPa. Multiplying by the toe area pi(0.50)²/4 gives approximately 478.6 kN. Shaft resistance is pi(0.50)(8)(1.0)(70)(0.50) = approximately 439.8 kN. The total ultimate compression resistance is therefore approximately 918.4 kN. Applying the specified factor of safety of 2.5 gives approximately 367.4 kN allowable resistance.
వివరణ:
Question 12
ప్రశ్న 12
At a pile site the water table is 3 m below ground level. The upper 3 m of sand has bulk unit weight 18 kN/m³, and the next 5 m has saturated unit weight 20 kN/m³; take gamma_w = 10 kN/m³ and hydrostatic conditions. What is the vertical effective overburden stress at 8 m depth?
Explanation:
The upper 3 m is above the water table and contributes 3(18) = 54 kPa of effective overburden. Below the water table, the submerged unit weight is 20 - 10 = 10 kN/m³. The lower 5 m contributes 5(10) = 50 kPa of effective overburden. The total effective stress at 8 m is therefore 54 + 50 = 104 kPa. Hydrostatic pore pressure must be considered when applying effective-stress pile-friction or toe formulas.
వివరణ:
Question 13
ప్రశ్న 13
The water table rises around a pile in sand while the relevant total overburden and interface parameters remain otherwise comparable. Which statement about the effective-stress method is most defensible?
Explanation:
Effective-stress pile formulas relate soil-pile friction to the effective normal stress at the interface. When pore-water pressure increases without a compensating increase in total stress, effective stress decreases. This can reduce the predicted positive shaft friction in an effective-stress analysis. Effective toe resistance may also change through the relevant surcharge and unit-weight terms. Actual changes require assessment of water-level position, soil condition, installation and the adopted analysis method.
వివరణ:
Question 14
ప్రశ్న 14
In a simplified sand-pile calculation, the adopted method explicitly caps the effective overburden pressure used in its unit shaft-friction formula once a specified critical depth is reached. Which procedure is correct below that depth?
Explanation:
Some simplified pile-capacity procedures impose a limiting effective overburden when estimating resistance in sand. The question explicitly adopts such a capped model. Accordingly the value used in the specified formula does not continue increasing beyond the prescribed limit. The model assumption should not be confused with a universal physical rule applicable to every soil and pile. More detailed effective-stress or site-calibrated analyses may adopt a different stress interpretation.
వివరణ:
Question 15
ప్రశ్న 15
A circular pile has a diameter of 0.80 m and a specified ultimate unit toe resistance of 1500 kPa. Assuming uniform toe pressure and pi = 3.1416, what ultimate end-bearing resistance does the pile develop?
Explanation:
The toe resistance is the ultimate unit toe pressure multiplied by the pile base area. The area of a circular base is pi d²/4. For d = 0.80 m, the area is approximately 0.50266 m². Multiplying this area by 1500 kPa gives approximately 754.0 kN. Shaft resistance is not included because only toe bearing has been specified.
వివరణ:
Question 16
ప్రశ్న 16
A cylindrical pile has diameter 0.60 m, a 12 m contributing shaft length and uniform ultimate positive unit shaft resistance of 45 kPa. Neglect toe resistance and use an explicit factor of safety of 3.0. What allowable axial compression resistance is obtained using Qs = pi d L fs?
Explanation:
The shaft surface area is pi(0.60)(12) = approximately 22.6195 m². The ultimate shaft resistance is 22.6195(45) = approximately 1017.9 kN. Toe resistance is neglected by instruction. The specified allowable value is obtained by dividing the ultimate load by 3.0. This gives approximately 339.3 kN and remains subject to structural and settlement limitations in actual design.
వివరణ:
Question 17
ప్రశ్న 17
A pile has calculated ultimate geotechnical compression resistance of 1400 kN, for which the project specifies a factor of safety of 2.5. The separately assessed allowable structural resistance is 500 kN, and the serviceability analysis limits working load to 450 kN. What is the governing allowable working compression load?
Explanation:
The geotechnical safe resistance is 1400/2.5 = 560 kN. Structural capacity separately limits the permitted working load to 500 kN. The specified settlement or serviceability limit is lower at 450 kN. A satisfactory design must respect all three governing checks. Therefore the allowable working compression load is 450 kN.
వివరణ:
Question 18
ప్రశ్న 18
For two geometrically similar circular piles in the same idealized soil, assume identical mobilized average unit shaft friction, identical embedded length and identical unit toe resistance. If pile diameter doubles, how do ultimate shaft and toe resistances change?
Explanation:
Shaft resistance for uniform unit friction is proportional to pile circumference times embedded length. With fixed length and unit shaft friction, it therefore varies directly with diameter. Toe resistance is proportional to the circular base area. With fixed ultimate unit toe pressure, that area varies with the square of diameter. Doubling diameter consequently doubles the shaft component and quadruples the toe component under the stated assumptions.
వివరణ:
Question 19
ప్రశ్న 19
At a point near the neutral plane of a pile affected by downward-moving fill and consolidating clay, the compressive axial force transmitted from the superstructure is 700 kN, and the accumulated downward dragload above that point is 160 kN. Neglect other forces. What axial compressive force must be carried at that location?
Explanation:
Negative skin friction acts downward along portions of a pile where the surrounding soil moves down relative to it. Its accumulated dragload adds to the compressive force being transmitted from the structure. The given superstructure contribution is 700 kN. The additional downward dragload is 160 kN at the specified section. Therefore the local compressive axial force is 700 + 160 = 860 kN, which must be considered in structural and geotechnical assessment.
వివరణ:
Question 20
ప్రశ్న 20
A 0.50 m diameter pile has 6 m of contributing shaft in sand. Use the beta-method fs = beta sigma_v,avg, where beta = K tan(delta). Given K = 0.80, tan(delta) = 0.50, and average vertical effective stress = 150 kPa, calculate ultimate shaft resistance for the segment, using pi = 3.1416.
Explanation:
The effective-stress shaft coefficient is beta = K tan(delta). Using the given values, beta = 0.80(0.50) = 0.40. The corresponding average unit shaft friction is 0.40(150) = 60 kPa. The contributing shaft area is pi(0.50)(6) = approximately 9.4248 m². Multiplication gives an ultimate shaft resistance of approximately 565.5 kN.
వివరణ:
Question 21
ప్రశ్న 21
In the effective-stress shaft-friction method for piles in sand, which interpretation of K and delta is correct?
Explanation:
The effective-stress friction expression is often written fs = K sigma_v' tan(delta). The coefficient K represents the relevant lateral effective-stress relation associated with the soil-pile interface. The angle delta represents interface friction rather than necessarily the full internal friction angle of the soil. Both quantities can depend on pile type, installation and the surrounding ground. Their values should be adopted from an appropriate method and evidence rather than assumed universal.
వివరణ:
Question 22
ప్రశ్న 22
A pile passes through thick clay and its toe rests in a dense sand layer. Which approach to evaluating its axial compression resistance is technically most appropriate?
Explanation:
A layered soil profile requires a compatible assessment of the relevant shaft segments and pile toe. Positive shaft resistance within clay can be estimated using appropriate undrained adhesion or another justified model. The toe resistance in sand requires parameters suitable for its drained or other governing condition. Additional shaft contributions can be evaluated separately wherever appropriate. The combined result should also account for pile installation, settlement and mobilization differences.
వివరణ:
Question 23
ప్రశ్న 23
For bored cast-in-situ concrete piles whose ultimate geotechnical capacity is estimated by a static formula under IS 2911 (Part 1/Sec 2):2010, what is the specified minimum factor of safety for arriving at the safe capacity?
Explanation:
IS 2911 (Part 1/Sec 2):2010 provides guidance for bored cast-in-situ concrete piles. It specifies a minimum factor of safety of 2.5 when safe capacity is derived from ultimate capacity using static formulae. The adopted factor may need to be higher depending on the reliability of input data and the structural situation. Settlement and structural strength remain independent checks even when the prescribed factor is met. The question concerns this particular static-formula provision and does not assert that every pile design situation uses the same factor.
వివరణ:
Question 24
ప్రశ్న 24
Static pile-capacity calculations predict that an individual pile has sufficient ultimate resistance, but a project requires confirmation of actual load-settlement response. Which investigation provides the most directly relevant performance evidence?
Explanation:
Static pile-capacity formulae rely on soil parameters and simplified load-transfer assumptions. An axial pile-load test records the pile response under controlled applied compression loads. The observed load-settlement relationship can be used to assess performance according to the specified interpretation criteria. A low-strain integrity test addresses potential continuity or defect concerns rather than directly measuring axial capacity. Load testing must still be interpreted with regard to the tested pile, subsurface variability and project requirements.
వివరణ:
Question 25
ప్రశ్న 25
A 0.50 m diameter pile has 5 m of shaft in clay with cu = 40 kPa and alpha = 0.80, followed by 5 m of shaft in sand with K = 1.0, tan(delta) = 0.50 and average vertical effective stress 110 kPa. Its toe is in sand with sigma_v,toe = 200 kPa, gamma_eff = 10 kN/m³, Nq = 20 and Ngamma = 20. Using Qs,clay = pi d L alpha cu, Qs,sand = pi d L K sigma_v,avg tan(delta), Qb = (pi d²/4)[0.5 d gamma_eff Ngamma + sigma_v,toe Nq], a factor of safety of 2.5, and pi = 3.1416, what is the allowable axial compression resistance?
Explanation:
The clay shaft contributes pi(0.50)(5)(0.80)(40) = approximately 251.3 kN. The sand shaft contributes pi(0.50)(5)(1.0)(110)(0.50) = approximately 432.0 kN. The sand toe pressure is 0.5(0.50)(10)(20) + 200(20) = 4050 kPa, producing approximately 795.2 kN toe resistance. The total ultimate resistance is approximately 251.3 + 432.0 + 795.2 = 1478.5 kN. Applying the factor of safety of 2.5 gives approximately 591.4 kN allowable axial compression resistance.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Qu = Qb + Qs, subject to the adopted mobilization assumptions. సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: D. A coefficient relating unit shaft adhesion to undrained shear strength, so that fs = alpha cu. సమాధానం: D.
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Question 3 ప్రశ్న 3Answer: C. 277.1 kN. సమాధానం: C.
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Question 4 ప్రశ్న 4Answer: A. 503.9 kN. సమాధానం: A.
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Question 5 ప్రశ్న 5Answer: C. 162 kN. సమాధానం: C.
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Question 6 ప్రశ్న 6Answer: B. 0.60. సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: A. The adhesion factor may vary with clay consistency and pile installation, so it should not automatically be held constant solely because cu is known. సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. 942.5 kN. సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. 785.4 kN. సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: A. 1077.3 kN. సమాధానం: A.
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Question 11 ప్రశ్న 11Answer: C. 918.4 kN and 367.4 kN. సమాధానం: C.
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Question 12 ప్రశ్న 12Answer: A. 104 kPa. సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: C. Rising pore pressure can reduce effective normal stress and hence the shaft and toe resistance predicted from effective-stress relationships. సమాధానం: C.
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Question 14 ప్రశ్న 14Answer: B. Use the stipulated limiting effective overburden in the capped calculation, while recognizing that the critical-depth assumption is model-specific. సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: D. 754.0 kN. సమాధానం: D.
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Question 16 ప్రశ్న 16Answer: B. 339.3 kN. సమాధానం: B.
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Question 17 ప్రశ్న 17Answer: A. 450 kN. సమాధానం: A.
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Question 18 ప్రశ్న 18Answer: D. Shaft resistance doubles and toe resistance quadruples. సమాధానం: D.
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Question 19 ప్రశ్న 19Answer: C. 860 kN. సమాధానం: C.
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Question 20 ప్రశ్న 20Answer: B. 565.5 kN. సమాధానం: B.
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Question 21 ప్రశ్న 21Answer: A. K reflects an applicable horizontal-to-vertical effective-stress relationship at the interface, while delta represents pile-soil interface friction and need not universally equal the soil friction angle phi. సమాధానం: A.
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Question 22 ప్రశ్న 22Answer: B. Evaluate the clay shaft contribution using appropriate clay parameters and the sand toe contribution using suitable sand bearing parameters, with other relevant strata assessed separately. సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: D. 2.5. సమాధానం: D.
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Question 24 ప్రశ్న 24Answer: C. A properly specified axial compression pile-load test with measured load and pile-head movement, interpreted under the applicable testing criteria. సమాధానం: C.
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Question 25 ప్రశ్న 25Answer: A. 591.4 kN. సమాధానం: A.
