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Question 1
ప్రశ్న 1
Using the convention that a channel bed falling in the downstream direction has positive slope S0, which set correctly classifies the five standard bed-slope types used in GVF profile analysis?
Explanation:
The critical slope Sc is the bed slope that would produce uniform flow at the critical depth for the specified discharge and channel. A mild slope is positive but smaller than the critical slope. A steep slope is greater than the critical slope. A horizontal bed has S0 = 0, while an adverse bed rises downstream and therefore has S0 < 0 under the stated convention. Hence Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
For a given discharge in a prismatic channel, which relationship between normal depth yn and critical depth yc identifies a mild slope?
Explanation:
On a mild slope, the normal-flow condition occurs at a depth greater than critical depth. Thus yn > yc. Normal flow on a mild slope is therefore subcritical because its depth exceeds critical depth. This relationship is one of the most convenient ways of identifying a mild channel slope for a specified discharge. Therefore Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
For a given discharge in a prismatic channel, which relationship identifies a steep slope?
Explanation:
A steep slope produces a normal depth smaller than the critical depth. Thus yn < yc. Uniform flow at normal depth on such a channel is supercritical. The steep classification therefore depends on the hydraulic relationship between normal and critical depths rather than simply on the visual appearance of the bed. Hence Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
What condition defines a critical channel slope for the specified discharge, geometry and resistance?
Explanation:
Critical slope is the bed slope for which uniform flow would occur at critical depth. Therefore the normal and critical depths coincide. In symbols, yn = yc. This also means uniform flow on the critical slope would have a Froude number of one under the conventional formulation. Therefore Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
Which statement about normal depth on horizontal and adverse slopes is most appropriate for ordinary gravity-driven open-channel flow?
Explanation:
Uniform gravity flow requires the friction slope to be balanced by the positive downstream bed slope. A horizontal channel has zero bed slope, while an adverse channel rises in the downstream direction under the stated sign convention. Consequently an ordinary positive-discharge uniform-flow condition with a finite normal depth cannot be established on these slopes. Standard GVF classification therefore treats horizontal and adverse profiles without a finite normal-depth line. Hence Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
For mild and steep channels where both yn and yc are finite, how are the three GVF profile zones conventionally defined?
Explanation:
The actual flow depth y is compared with the two reference depths yn and yc. Zone 1 lies above both reference-depth lines. Zone 2 lies between normal and critical depth. Zone 3 lies below both reference depths. The order of yn and yc depends on whether the channel is mild or steep, but the zone definition itself remains consistent. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
What is the flow regime of any Zone 1 GVF profile in the standard classification?
Explanation:
Zone 1 is defined by an actual depth greater than both normal and critical depths. In particular, y > yc. A depth greater than critical depth corresponds to the subcritical branch for the specified discharge. Therefore Zone 1 profiles such as M1, S1 and C1 are subcritical. Hence Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
What is the flow regime of any Zone 3 profile?
Explanation:
Zone 3 lies below both relevant reference depths. Consequently the actual depth is below critical depth. For a given discharge, this places the flow on the supercritical branch. Examples include M3, S3, C3, H3 and A3. Therefore Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
Which statement correctly describes the hydraulic regime in Zone 2?
Explanation:
On a mild slope, yn > yc and Zone 2 satisfies yn > y > yc. Thus y remains above critical depth and the flow is subcritical. On a steep slope, yc > yn and Zone 2 satisfies yc > y > yn. The actual depth is then below critical depth and the flow is supercritical. Therefore Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
A prismatic channel has yn = 2.40 m and yc = 1.20 m. At a section the actual depth is y = 3.00 m. Which GVF profile designation applies?
Explanation:
Since yn = 2.40 m is greater than yc = 1.20 m, the channel slope is mild. The actual depth of 3.00 m is greater than both reference depths. It therefore lies in Zone 1. A Zone 1 profile on a mild slope is designated M1. Hence Option A is correct.
వివరణ:
Question 11
ప్రశ్న 11
For the same mild channel with yn = 2.40 m and yc = 1.20 m, the actual depth is y = 1.80 m. Which profile is present?
Explanation:
The relation yn > yc identifies a mild slope. The actual depth 1.80 m lies between 2.40 m and 1.20 m. Thus the flow is in Zone 2. A Zone 2 profile on a mild slope is M2 and is subcritical. Therefore Option C is correct.
వివరణ:
Question 12
ప్రశ్న 12
A mild channel has yn = 2.40 m and yc = 1.20 m. If the actual depth is y = 0.80 m, what is the profile designation?
Explanation:
The channel is mild because yn exceeds yc. The actual depth of 0.80 m is lower than both normal and critical depths. It therefore lies in Zone 3. A Zone 3 profile on a mild slope is M3, and the flow is supercritical. Hence Option B is correct.
వివరణ:
Question 13
ప్రశ్న 13
A channel has yn = 0.90 m and yc = 1.50 m. At a section the actual depth is y = 2.20 m. Which GVF profile is present?
Explanation:
Since yn is smaller than yc, the channel is steep. The actual depth of 2.20 m exceeds both critical and normal depths. The flow therefore lies in Zone 1. Zone 1 on a steep slope is designated S1 and is subcritical. Therefore Option C is correct.
వివరణ:
Question 14
ప్రశ్న 14
For the same steep channel with yn = 0.90 m and yc = 1.50 m, the actual depth is y = 1.20 m. Which profile applies?
Explanation:
The channel is steep because yn < yc. The actual depth 1.20 m lies between the critical depth of 1.50 m and the normal depth of 0.90 m. This is therefore Zone 2. The Zone 2 profile on a steep slope is S2, which is supercritical. Hence Option A is correct.
వివరణ:
Question 15
ప్రశ్న 15
For a steep channel with yn = 0.90 m and yc = 1.50 m, the actual depth is y = 0.60 m. Which profile is present?
Explanation:
The normal depth is below the critical depth, so the channel is steep. The actual depth 0.60 m is below both reference depths. It is therefore a Zone 3 condition. A Zone 3 profile on a steep slope is designated S3 and is supercritical. Therefore Option C is correct.
వివరణ:
Question 16
ప్రశ్న 16
For a critical-slope channel where yn = yc, which standard GVF profiles are physically applicable?
Explanation:
On a critical slope, the normal-depth and critical-depth lines coincide. Consequently there is no finite interval between them that could form a separate Zone 2. The standard realizable profiles are C1 above the common depth and C3 below it. C1 is subcritical and C3 is supercritical. Therefore Option C is correct.
వివరణ:
Question 17
ప్రశ్న 17
Why is a conventional C2 profile absent from the standard realizable GVF classification?
Explanation:
Zone 2 is defined as the region between normal depth and critical depth. On a critical slope these two reference depths are identical. There is therefore no finite range of depth that can constitute Zone 2. The meaningful nonuniform critical-slope profiles are consequently C1 and C3. Hence Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
Which profile designations apply on a horizontal channel bed?
Explanation:
A horizontal bed has S0 = 0 and does not possess a finite conventional normal depth for ordinary gravity-driven uniform flow. The applicable profiles are therefore classified relative primarily to critical depth. H2 has y > yc and is subcritical. H3 has y < yc and is supercritical. Thus Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
Which pair correctly describes the standard adverse-slope GVF profiles?
Explanation:
An adverse channel bed rises downstream and has S0 < 0 under the stated convention. An ordinary finite normal depth does not exist because gravity cannot balance positive friction in uniform flow. The A2 profile occurs above critical depth and is subcritical. The A3 profile occurs below critical depth and is supercritical. Therefore Option B is correct.
వివరణ:
Question 20
ప్రశ్న 20
Why are H1 and A1 absent from the standard set of realizable GVF profiles?
Explanation:
Zone 1 requires the actual depth to lie above both a finite normal-depth line and the critical-depth line. Horizontal and adverse channels do not possess a finite conventional normal depth for ordinary uniform gravity flow. Consequently the standard Zone 1 construction does not produce H1 or A1 profiles. Subcritical flow can still occur on these slopes as H2 or A2. Therefore Option A is correct.
వివరణ:
Question 21
ప్రశ్న 21
Using dy/dx = (S0 - Sf)/(1 - Fr²) with x positive downstream, which sequence correctly gives the signs of dy/dx for M1, M2 and M3 profiles?
Explanation:
For M1, y > yn and y > yc, so Sf < S0 and Fr < 1, giving a positive depth gradient. For M2, y < yn but y > yc, so Sf > S0 while Fr < 1, giving a negative gradient. For M3, y is below both depths, so Sf > S0 and Fr > 1; both numerator and denominator are negative, giving a positive gradient. Thus the sequence is positive, negative, positive. Therefore Option C is correct.
వివరణ:
Question 22
ప్రశ్న 22
Which sequence correctly gives the downstream signs of dy/dx for the S1, S2 and S3 profiles?
Explanation:
For S1, the actual depth exceeds both yc and yn, giving Sf < S0 and subcritical flow, so dy/dx is positive. For S2, y lies below yc but above yn, giving Sf < S0 and a negative denominator because the flow is supercritical. The resulting depth gradient is negative. For S3, y is below yn and yc, making both numerator and denominator negative and therefore giving a positive gradient. Hence Option A is correct.
వివరణ:
Question 23
ప్రశ్న 23
Which statement about approach to normal depth is correct for standard GVF profiles?
Explanation:
At normal depth the local friction slope equals the bed slope. In the standard GVF equation this causes the numerator S0 - Sf to approach zero. Provided the flow is not simultaneously at a singular critical condition, dy/dx therefore approaches zero. The normal-depth line consequently acts as an asymptote for profiles such as M1 and M2, and similarly for appropriate steep profiles. Therefore Option C is correct.
వివరణ:
Question 24
ప్రశ్న 24
For profiles that approach critical depth while S0 - Sf remains nonzero, what does the standard GVF equation predict?
Explanation:
At critical depth the Froude number approaches one. The denominator 1 - Fr² of the standard GVF equation therefore approaches zero. If the numerator remains finite and nonzero, the magnitude of dy/dx becomes very large. Geometrically, the profile approaches the critical-depth line with a very steep depth gradient within the simplified theory. Therefore Option B is correct.
వివరణ:
Question 25
ప్రశ్న 25
Which statement about hydraulic control is consistent with the GVF profile classification?
Explanation:
Subcritical flow permits gravity-wave information to propagate upstream as well as downstream. A downstream water-level control can therefore determine a subcritical GVF profile upstream of it. In supercritical flow, disturbances cannot travel upstream against the flow. Supercritical profiles are consequently governed primarily by upstream controls. Therefore Option A is correct.
వివరణ:
Question 26
ప్రశ్న 26
Consider the following statements about standard GVF profile classification: I. Mild slopes admit M1, M2 and M3 profiles. II. Steep slopes admit S1, S2 and S3 profiles. III. Critical slopes have C1 and C3 because Zone 2 disappears when yn = yc. IV. Horizontal and adverse slopes have only the 2- and 3-type profiles in the standard realizable classification. Which option is correct?
Explanation:
A mild channel has three possible zones and therefore M1, M2 and M3 profiles. A steep channel similarly admits S1, S2 and S3. On a critical slope, yn and yc coincide, eliminating a separate Zone 2 and leaving C1 and C3. Horizontal and adverse slopes lack a finite conventional normal-depth line and therefore have H2-H3 and A2-A3 respectively. Hence all four statements are correct and Option D is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Mild: 0 < S0 < Sc; Steep: S0 > Sc; Critical: S0 = Sc; Horizontal: S0 = 0; Adverse: S0 < 0 సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. yn > yc సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. yn < yc సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. yn = yc సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. A finite conventional normal depth is not available because the bed slope cannot balance positive friction loss in ordinary uniform flow సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. Zone 1: y above both yn and yc; Zone 2: y between yn and yc; Zone 3: y below both yn and yc సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. Subcritical, because y > yc సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. Supercritical, because y < yc సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. Zone 2 is subcritical on a mild slope but supercritical on a steep slope సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: A. M1 సమాధానం: A.
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Question 11 ప్రశ్న 11Answer: C. M2 సమాధానం: C.
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Question 12 ప్రశ్న 12Answer: B. M3 సమాధానం: B.
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Question 13 ప్రశ్న 13Answer: C. S1 సమాధానం: C.
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Question 14 ప్రశ్న 14Answer: A. S2 సమాధానం: A.
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Question 15 ప్రశ్న 15Answer: C. S3 సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: C. C1 and C3 సమాధానం: C.
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Question 17 ప్రశ్న 17Answer: B. Because yn = yc, so the Zone 2 interval between normal and critical depths collapses సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. H2 and H3 only సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: B. A2 for y > yc and A3 for y < yc సమాధానం: B.
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Question 20 ప్రశ్న 20Answer: A. Horizontal and adverse channels have no finite normal-depth line that can define a conventional Zone 1 above both yn and yc సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: C. M1 positive, M2 negative, M3 positive సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: A. S1 positive, S2 negative, S3 positive సమాధానం: A.
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Question 23 ప్రశ్న 23Answer: C. Profiles such as M1 and M2 approach the normal-depth line asymptotically rather than crossing it within the same prismatic reach సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: B. The magnitude of dy/dx becomes very large because 1 - Fr² approaches zero సమాధానం: B.
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Question 25 ప్రశ్న 25Answer: A. Subcritical profiles are generally controlled from downstream, whereas supercritical profiles are generally controlled from upstream సమాధానం: A.
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Question 26 ప్రశ్న 26Answer: D. I, II, III and IV సమాధానం: D.
