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Question 1
ప్రశ్న 1
Which combination of aggregate properties is principally covered by IS 2386 (Part 3)?
Explanation:
IS 2386 Part 3 deals with several mass-volume and moisture-related properties of aggregates. It includes procedures for specific gravity and water absorption. It also covers bulk density and calculation of void content. Field procedures for bulking and surface moisture of fine aggregate are included. Therefore Option A correctly identifies the scope relevant to this test.
వివరణ:
Question 2
ప్రశ్న 2
Which description correctly represents the saturated surface-dry (SSD) condition of an aggregate?
Explanation:
SSD is an important reference moisture condition in aggregate testing and concrete proportioning. In this state, the accessible or permeable pores have been filled with absorbed water. At the same time, free water has been removed from the external particle surfaces. Consequently SSD aggregate neither contributes surface water nor initially demands water to fill its absorptive capacity. Therefore Option A correctly describes the SSD condition.
వివరణ:
Question 3
ప్రశ్న 3
Which expression correctly gives aggregate water absorption as a percentage of oven-dry mass when WSSD is the saturated surface-dry mass and WOD is the oven-dry mass?
Explanation:
Water absorption represents the water held within permeable aggregate pores when the material changes from oven-dry to SSD condition. The absorbed-water mass is therefore WSSD minus WOD. Under the standard convention, this quantity is expressed as a percentage of the oven-dry aggregate mass. The denominator is consequently WOD rather than WSSD. Hence Option A gives the correct expression.
వివరణ:
Question 4
ప్రశ్న 4
An aggregate sample weighs 2000 g in the oven-dry condition and 2040 g in the saturated surface-dry condition. What is its water absorption?
Explanation:
The mass of water absorbed into the permeable pores is 2040 − 2000 = 40 g. Water absorption is expressed relative to the oven-dry mass. Therefore absorption equals 40 divided by 2000 multiplied by 100. The result is 2.0 percent. Hence Option B is correct.
వివరణ:
Question 5
ప్రశ్న 5
Which statement correctly distinguishes water absorption from surface moisture of aggregate?
Explanation:
Absorbed water occupies accessible pores within the aggregate particles. The SSD state represents the condition in which these pores are filled but the outside surface is dry. Water present in excess of SSD remains as free surface moisture. This free water contributes to the effective mixing water in concrete and therefore requires a batching correction. Hence Option A correctly distinguishes the two quantities.
వివరణ:
Question 6
ప్రశ్న 6
One kilogram of oven-dry sand has an absorption capacity of 2 percent. Its actual wet mass at batching is 1.050 kg. Assuming the pores are fully saturated, how much of the 50 g total water is free surface water?
Explanation:
An absorption capacity of 2 percent corresponds to 20 g of absorbed water for 1000 g of oven-dry sand. The actual wet mass exceeds the oven-dry mass by 50 g, so the total water associated with the sample is 50 g. Of this amount, 20 g is required to bring the aggregate to SSD condition. The remaining 30 g lies above SSD and is therefore free surface water. Hence Option B is correct.
వివరణ:
Question 7
ప్రశ్న 7
An aggregate has an absorption capacity of 2 percent but enters the concrete mixer with an actual moisture content of only 1 percent, both percentages being based on oven-dry mass. What is the most appropriate interpretation?
Explanation:
SSD would require moisture equal to the full absorption capacity of 2 percent. The actual moisture content is only 1 percent, so the aggregate remains below SSD condition. It therefore has an unfilled absorptive capacity equivalent to approximately 1 percent of its oven-dry mass. Unless allowance is made, the aggregate can take this water from the fresh concrete mixture. Therefore Option B is correct.
వివరణ:
Question 8
ప్రశ్న 8
A concrete mix requires 800 kg of fine aggregate in SSD condition. The available sand contains 3 percent free surface moisture by mass of SSD aggregate. What wet mass of sand should be batched, and by how much should the externally added mixing water be reduced?
Explanation:
Three percent surface moisture on 800 kg of SSD sand equals 24 kg of free water. The wet mass to be weighed is therefore 800 + 24 = 824 kg. That 24 kg of water enters the concrete with the aggregate itself. To maintain the intended effective water content, the separately added mixing water should be reduced by 24 kg. Therefore Option B is correct.
వివరణ:
Question 9
ప్రశ్న 9
Which statement correctly distinguishes bulk specific gravity based on oven-dry aggregate from apparent specific gravity?
Explanation:
Bulk specific gravity relates aggregate mass to the bulk volume of individual particles including their permeable pore space. Apparent specific gravity uses a smaller effective solid volume because permeable pores are excluded. Consequently apparent specific gravity is normally equal to or greater than bulk specific gravity for an absorptive aggregate. Neither quantity includes the large inter-particle voids of a loose aggregate stockpile. Therefore Option A correctly distinguishes the concepts.
వివరణ:
Question 10
ప్రశ్న 10
In a coarse-aggregate specific-gravity test, the saturated aggregate weighs 1250 g while suspended in water, 2000 g in SSD condition in air, and 1960 g after oven drying. Using Gdry = WOD/(WSSD − Wsubmerged), what is the approximate oven-dry bulk specific gravity?
Explanation:
The denominator is the SSD mass in air minus the saturated mass while submerged. This equals 2000 − 1250 = 750 g. The oven-dry mass is 1960 g. Therefore the dry bulk specific gravity is 1960 divided by 750, which is approximately 2.61. Hence Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
Using the same test data—1250 g submerged mass, 2000 g SSD mass and 1960 g oven-dry mass—which set of approximate values is correct for SSD specific gravity, apparent specific gravity and water absorption respectively?
Explanation:
SSD specific gravity is 2000 divided by 2000 − 1250, giving approximately 2.67. Apparent specific gravity is 1960 divided by 1960 − 1250, giving approximately 2.76. Water absorption is 100 multiplied by 2000 − 1960 divided by 1960. This gives approximately 2.04 percent. Therefore Option A contains the correct set of values.
వివరణ:
Question 12
ప్రశ్న 12
Why is apparent specific gravity generally greater than oven-dry bulk specific gravity for an absorptive aggregate?
Explanation:
Both quantities describe individual aggregate particles rather than the voids between separate particles. Bulk specific gravity includes the volume of permeable pores as part of the aggregate bulk particle volume. Apparent specific gravity excludes those permeable pores from the effective volume. The denominator used for apparent specific gravity is therefore smaller. Consequently the apparent specific gravity is normally the larger value and Option A is correct.
వివరణ:
Question 13
ప్రశ్న 13
Which statement correctly describes aggregate bulk density?
Explanation:
Bulk density is determined from the mass of aggregate contained within a measure of known volume. That measured volume includes both aggregate particles and the void spaces between them. Consequently bulk density depends strongly on how the particles are packed in the container. Moisture condition and grading can also influence the measured result. Therefore Option A correctly defines bulk density.
వివరణ:
Question 14
ప్రశ్న 14
A 15-litre cylindrical measure contains 24.0 kg of aggregate after the specified filling procedure. What is its bulk density?
Explanation:
Bulk density is obtained by dividing the net aggregate mass by the calibrated measure volume. The calculation is 24.0 kg divided by 15 L. This gives 1.60 kg/L. Since 1 kg/L equals 1000 kg/m³, the same result is 1600 kg/m³. Therefore Option B is correct.
వివరణ:
Question 15
ప్రశ్న 15
For the same aggregate and moisture condition, why is rodded bulk density normally greater than loose bulk density?
Explanation:
Loose filling leaves the aggregate in a relatively open packing arrangement. Rodding supplies compactive effort that allows particles to rearrange more efficiently. A greater mass can therefore occupy the same calibrated container volume. The mineral specific gravity of the particles themselves does not change during this process. Hence Option A correctly explains the higher rodded bulk density.
వివరణ:
Question 16
ప్రశ్న 16
An oven-dry aggregate has a specific gravity of 2.65 and a bulk density of 1.59 kg/L. Using Voids (%) = (1 − Bulk density/Specific gravity) × 100, what is the approximate void content?
Explanation:
With water density represented by 1 kg/L, the particle material density corresponding to a specific gravity of 2.65 is numerically 2.65 kg/L. The ratio of bulk density to particle density is therefore 1.59 divided by 2.65, which equals 0.60. The unoccupied fraction is 1 − 0.60 = 0.40. Expressed as a percentage, the void content is 40 percent. Therefore Option C is correct.
వివరణ:
Question 17
ప్రశ్న 17
An aggregate of specific gravity 2.65 has a loose bulk density of 1.45 kg/L and a rodded bulk density of 1.65 kg/L. Which statement is correct?
Explanation:
Loose void content is approximately 100 times 1 − 1.45/2.65, which is about 45 percent. Rodded void content is approximately 100 times 1 − 1.65/2.65, which is about 38 percent. The reduction occurs because compaction improves particle packing. The specific gravity of the aggregate material itself remains unchanged. Therefore Option A is correct.
వివరణ:
Question 18
ప్రశ్న 18
What is the fundamental cause of bulking of moist fine aggregate?
Explanation:
A small amount of moisture forms films around fine aggregate particles. Surface-tension effects associated with these films tend to hold neighbouring particles slightly apart. The resulting loose particle arrangement occupies a greater bulk volume than the corresponding dry or inundated material. This increase in apparent volume is called bulking. Therefore Option A correctly explains its physical origin.
వివరణ:
Question 19
ప్రశ్న 19
Which statement about the relationship between moisture content and bulking of sand is generally correct?
Explanation:
Dry sand has no moisture-film bulking effect. When a small quantity of water is introduced, surface films separate the particles and the apparent volume increases. Bulking normally reaches a maximum at an intermediate moisture content. With further addition of water, the films merge and the particles can pack more closely again. Thus bulking largely disappears on complete inundation, making Option A correct.
వివరణ:
Question 20
ప్రశ్న 20
Why does fine sand generally show greater bulking than coarse sand for comparable moisture conditions?
Explanation:
Finer particles provide a larger total surface area for a given mass of material. Moisture films therefore act over a larger area and can influence the particle spacing more strongly. This tends to produce a greater increase in loose apparent volume than for relatively coarse sand. The effect is not caused by a necessarily different mineral specific gravity. Therefore Option A is correct.
వివరణ:
Question 21
ప్రశ్న 21
In a field bulking test, damp sand occupies a depth of 30 cm in a uniform container. After the sand is completely inundated and consolidated, its depth is 24 cm. What is the percentage bulking?
Explanation:
For a container of constant cross-sectional area, volume is proportional to the measured sand depth. Percentage bulking is therefore calculated as (30/24 − 1) multiplied by 100. The ratio 30/24 equals 1.25. The increase over the inundated reference volume is consequently 25 percent. Hence Option B is correct.
వివరణ:
Question 22
ప్రశ్న 22
In a measuring-cylinder field test, damp sand initially occupies 200 mL. After sufficient water is added and the sand is stirred and inundated, it occupies 160 mL. What is the percentage bulking of the damp sand?
Explanation:
The damp loose volume is 200 mL while the corresponding inundated reference volume is 160 mL. Percentage bulking is calculated as (200/160 − 1) multiplied by 100. The ratio is 1.25, so the increase is 0.25 or 25 percent. The reduction after inundation occurs because the moisture-film bulking effect disappears. Therefore Option B is correct.
వివరణ:
Question 23
ప్రశ్న 23
A nominal volumetric concrete proportion requires 0.50 m³ of dry-equivalent sand. Field testing shows that the damp sand has 25 percent bulking. What loose volume of the damp sand should be measured to supply approximately the intended quantity?
Explanation:
A bulking value of 25 percent means that the damp sand occupies 1.25 times its dry-equivalent loose volume. The required corrected measured volume is therefore 0.50 multiplied by 1.25. This equals 0.625 m³. Without this correction, a volumetric batch would contain less sand than intended. Hence Option C is correct.
వివరణ:
Question 24
ప్రశ్న 24
If strongly bulked damp sand is measured by volume but no bulking correction is applied, what is the principal consequence for a nominal volumetric concrete mix?
Explanation:
Bulking causes a given mass of damp sand to occupy a greater loose volume. A fixed gauge box filled with bulked sand therefore contains less actual sand than the same nominal volume of unbulked material. If no correction is made, the fine-aggregate quantity is under-batched. The nominal proportion consequently becomes richer in cementitious material relative to sand than intended. Therefore Option A is correct.
వివరణ:
Question 25
ప్రశ్న 25
Why is bulking primarily a practical concern with fine aggregate rather than normal coarse aggregate?
Explanation:
Bulking results from moisture films acting around the surfaces of particles. Fine aggregate has a much greater total surface area for a given bulk quantity than coarse aggregate. Surface-tension effects can therefore separate fine particles sufficiently to cause a substantial apparent-volume increase. Coarse aggregate can certainly absorb and retain moisture, but comparable bulking is normally insignificant. Hence Option A is correct.
వివరణ:
Question 26
ప్రశ్న 26
A manufactured aggregate covered by the normal IS 383:2016 manufactured-aggregate requirement has a measured water absorption of 6 percent and does not qualify for the recycled-aggregate relaxation. If the normal maximum is 5 percent, what is the correct conclusion?
Explanation:
IS 383 includes additional requirements for manufactured aggregates, including a normal maximum water absorption value of 5 percent. The stated aggregate gives a measured value of 6 percent. Because the question explicitly excludes the special recycled-aggregate provision, the higher allowance cannot be invoked. The measured result therefore exceeds the applicable normal requirement. Hence Option B is correct.
వివరణ:
Question 27
ప్రశ్న 27
Consider the following statements about aggregate moisture and volume properties:
1. SSD aggregate has its permeable pores filled but has no free surface water.
2. Aggregate wetter than SSD can contribute free water to the concrete mixture.
3. Aggregate drier than SSD may absorb part of the added mixing water.
4. Bulk density and particle specific gravity are necessarily numerically identical because both involve mass and volume.
Which statements are correct?
1. SSD aggregate has its permeable pores filled but has no free surface water.
2. Aggregate wetter than SSD can contribute free water to the concrete mixture.
3. Aggregate drier than SSD may absorb part of the added mixing water.
4. Bulk density and particle specific gravity are necessarily numerically identical because both involve mass and volume.
Which statements are correct?
Explanation:
Statement 1 is correct because SSD means saturated internal permeable pores with a dry external surface. Statement 2 is correct because water above SSD exists as free surface moisture and contributes to the effective concrete water. Statement 3 is correct because aggregate below SSD still has available absorptive capacity. Statement 4 is incorrect because bulk density includes inter-particle voids and depends on packing, whereas specific gravity describes the aggregate particle material relative to water. Therefore Statements 1, 2 and 3 are correct and Option B is the unique answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: A. Specific gravity, density, voids, water absorption and bulking సమాధానం: A.
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Question 2 ప్రశ్న 2Answer: A. Permeable pores are filled with water, but no free water film remains on the particle surface. సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: A. 100(WSSD − WOD)/WOD సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: B. 2.0 percent సమాధానం: B.
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Question 5 ప్రశ్న 5Answer: A. Absorption is water held in permeable particle pores up to SSD condition, while surface moisture is free water present outside the particles above SSD condition. సమాధానం: A.
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Question 6 ప్రశ్న 6Answer: B. 30 g సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: B. It is below SSD and may absorb approximately 1 percent of its oven-dry mass from the mixing water. సమాధానం: B.
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Question 8 ప్రశ్న 8Answer: B. 824 kg sand and 24 kg less added water సమాధానం: B.
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Question 9 ప్రశ్న 9Answer: A. Bulk specific gravity accounts for the aggregate bulk particle volume including permeable pores, whereas apparent specific gravity excludes the volume of permeable pores. సమాధానం: A.
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Question 10 ప్రశ్న 10Answer: C. 2.61 సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. 2.67, 2.76 and 2.04 percent సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: A. Apparent specific gravity excludes permeable pore volume from the effective aggregate volume used in its calculation. సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: A. It is the mass of aggregate occupying a given bulk volume, including the inter-particle voids present under the specified packing condition. సమాధానం: A.
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Question 14 ప్రశ్న 14Answer: B. 1.60 kg/L సమాధానం: B.
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Question 15 ప్రశ్న 15Answer: A. Rodding improves particle packing and reduces inter-particle void volume within the measure. సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: C. 40 percent సమాధానం: C.
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Question 17 ప్రశ్న 17Answer: A. The loose condition has about 45 percent voids and the rodded condition about 38 percent voids. సమాధానం: A.
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Question 18 ప్రశ్న 18Answer: A. Thin moisture films and surface-tension effects separate sand particles, increasing their apparent loose volume. సమాధానం: A.
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Question 19 ప్రశ్న 19Answer: A. Bulking develops at relatively low moisture contents, may reach a maximum at an intermediate moisture content, and largely disappears when the sand becomes fully inundated. సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: A. Finer sand has greater surface area per unit mass, so moisture-film effects influence a larger particle surface. సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: B. 25 percent సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: B. 25 percent సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. 0.625 m³ సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: A. Less actual sand is batched than intended, so the resulting mixture becomes richer in cement paste relative to fine aggregate. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: A. Fine aggregate has much greater surface area per unit volume, making moisture-film separation effects substantially more important. సమాధానం: A.
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Question 26 ప్రశ్న 26Answer: B. It does not satisfy the stated normal 5 percent water-absorption limit. సమాధానం: B.
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Question 27 ప్రశ్న 27Answer: B. 1, 2 and 3 only సమాధానం: B.
