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Question 1
ప్రశ్న 1
Which procedure correctly represents the mean sectional area method of computing earthwork volume between two consecutive cross sections?
Explanation:
The mean sectional area method is also known as the average-end-area method. It uses the cross-sectional areas measured or calculated at the two ends of an interval. The mean area is obtained by adding these two areas and dividing the sum by two. Multiplying the mean area by the longitudinal interval length gives the estimated earthwork volume. The mathematical expression is V = L(A1 + A2)/2. The method differs from the mid-sectional area method, which uses the representative area at the middle of the interval.
వివరణ:
Question 2
ప్రశ్న 2
Two consecutive road-cutting sections have cross-sectional areas of 14 m2 and 26 m2. If the distance between the sections is 35 m, what is the estimated cutting volume by the mean sectional area method?
Explanation:
The mean sectional area method uses the arithmetic average of the two end areas. The first sectional area is 14 m2 and the second is 26 m2. Their mean is (14 + 26)/2 = 20 m2. The longitudinal interval is 35 m. The estimated cutting volume is therefore 20 x 35 = 700 m3. The calculation assumes that the average-end-area method is the specified basis for estimating the earthwork quantity.
వివరణ:
Question 3
ప్రశ్న 3
A road embankment on level transverse ground has a constant formation width of 7 m and symmetrical side slopes of 1.5 horizontal to 1 vertical. The filling heights at two consecutive sections are 1 m and 2 m, and their spacing is 24 m. What volume is obtained by the MEAN SECTIONAL AREA method, using the complete area of each end section?
Explanation:
For an embankment with symmetrical side slopes on level transverse ground, sectional area is A = Bd + md^2. At the first section, the area is 7 x 1 + 1.5 x 1^2 = 8.5 m2. At the second section, the area is 7 x 2 + 1.5 x 2^2 = 20 m2. The arithmetic mean of the two complete areas is (8.5 + 20)/2 = 14.25 m2. The earthwork volume is therefore 14.25 x 24 = 342 m3. Using the mean depth to calculate one midpoint area would represent a different computation method and would not give this result.
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Question 4
ప్రశ్న 4
Cross-sectional areas at three consecutive chainages are 10 m2, 16 m2 and 22 m2. The spacing between successive sections is uniformly 25 m. What is the total earthwork volume by the mean sectional area method?
Explanation:
The three cross sections define two longitudinal intervals of 25 m each. For the first interval, the mean area is (10 + 16)/2 = 13 m2. Its estimated volume is 13 x 25 = 325 m3. For the second interval, the mean area is (16 + 22)/2 = 19 m2. Its estimated volume is 19 x 25 = 475 m3. Adding the two volumes gives 325 + 475 = 800 m3. The intermediate section is used as the ending area of one interval and the starting area of the next.
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Question 5
ప్రశ్న 5
The cross-sectional areas of an earthwork alignment at chainages 0+000, 0+020, 0+055 and 0+075 are 12 m2, 20 m2, 14 m2 and 18 m2 respectively. Using the mean sectional area method with ACTUAL chainage intervals, what is the total volume?
Explanation:
The successive chainage intervals are 20 m, 35 m and 20 m. The first interval volume is (12 + 20)/2 x 20 = 320 m3. The second interval volume is (20 + 14)/2 x 35 = 595 m3. The third interval volume is (14 + 18)/2 x 20 = 320 m3. The total earthwork volume is therefore 320 + 595 + 320 = 1,235 m3. Using a common interval length for all three reaches would be incorrect because the sections are not equally spaced.
వివరణ:
Question 6
ప్రశ్న 6
A railway embankment has end-sectional areas of 18 m2 and 30 m2 over a longitudinal length of 40 m. What volume is estimated by the mean sectional area method?
Explanation:
The two end-sectional areas are 18 m2 and 30 m2. Their arithmetic mean is (18 + 30)/2 = 24 m2. The longitudinal length between the sections is 40 m. The estimated earthwork volume is 24 x 40 = 960 m3. This is equivalent to using the formula V = L(A1 + A2)/2. The result is an average-end-area estimate and does not require a separately surveyed midpoint section.
వివరణ:
Question 7
ప్రశ్న 7
An earthwork reach has end-sectional areas of 16 m2 and 24 m2. If its volume calculated by the mean sectional area method is 1,200 m3, what is the distance between the sections?
Explanation:
The volume formula for the mean sectional area method is V = L(A1 + A2)/2. Rearranging the expression gives L = 2V/(A1 + A2). The sum of the end-sectional areas is 16 + 24 = 40 m2. Substituting the given volume gives L = 2 x 1,200/40 = 60 m. The required longitudinal interval is therefore 60 m. Dividing volume by the mean sectional area gives the same result because 1,200/20 = 60 m.
వివరణ:
Question 8
ప్రశ్న 8
Five consecutive earthwork cross sections have areas of 8 m2, 14 m2, 20 m2, 12 m2 and 16 m2. The four intervals between them are each 30 m long. What is the total volume by the mean sectional area method?
Explanation:
Five cross sections form four longitudinal intervals. For equal spacing, the total volume can be written as V = L[A1/2 + A2 + A3 + A4 + A5/2]. The weighted area sum is 8/2 + 14 + 20 + 12 + 16/2. This becomes 4 + 14 + 20 + 12 + 8 = 58 m2. Multiplying by the common spacing of 30 m gives 58 x 30 = 1,740 m3. The first and last sections receive half-weighting, while the three intermediate sections receive full weighting.
వివరణ:
Question 9
ప్రశ్న 9
Three successive cross sections have areas of 8 m2, 12 m2 and 24 m2 at chainages 0+000, 0+020 and 0+050 respectively. What is the total earthwork volume by the mean sectional area method?
Explanation:
The first interval extends from chainage 0+000 to 0+020 and has a length of 20 m. Its mean sectional area is (8 + 12)/2 = 10 m2, giving 200 m3. The second interval extends from 0+020 to 0+050 and has a length of 30 m. Its mean area is (12 + 24)/2 = 18 m2, giving 540 m3. The combined volume is 200 + 540 = 740 m3. Using only the first and last cross sections over the full 50 m would ignore the surveyed intermediate sectional area.
వివరణ:
Question 10
ప్రశ్న 10
A canal excavation has a uniform cross-sectional area of 21 m2 throughout a straight 75 m reach. What volume is obtained by the mean sectional area method?
Explanation:
The cross-sectional area is constant at 21 m2 throughout the specified reach. Therefore both end-sectional areas are equal to 21 m2. Their arithmetic mean is also 21 m2. The longitudinal length is 75 m. The computed volume is 21 x 75 = 1,575 m3. Because the section is uniform throughout, the mean sectional area method gives the exact geometric volume under the stated assumptions.
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Question 11
ప్రశ్న 11
A road embankment has a constant formation width of 6 m and symmetrical side slopes of 1 horizontal to 1 vertical on level transverse ground. The filling heights at two consecutive sections are 1 m and 2 m, and the section spacing is 30 m. What volume is obtained by the mean sectional area method?
Explanation:
The sectional area of the embankment is calculated using A = Bd + md^2. At the first section, A1 = 6 x 1 + 1 x 1^2 = 7 m2. At the second section, A2 = 6 x 2 + 1 x 2^2 = 16 m2. Their mean is (7 + 16)/2 = 11.5 m2. Multiplying by the section spacing gives V = 11.5 x 30 = 345 m3. The method averages the two complete sectional areas rather than using the average filling height to calculate a single section.
వివరణ:
Question 12
ప్రశ్న 12
A symmetrical road cutting on level transverse ground has a formation width of 10 m and side slopes of 1.5 horizontal to 1 vertical. Its cutting depths at two successive cross sections are 1.2 m and 2.4 m, with an interval length of 25 m. What is the estimated cutting volume by the mean sectional area method?
Explanation:
The cross-sectional area formula is A = Bd + md^2 for the stated symmetrical cutting. At the first section, A1 = 10 x 1.2 + 1.5 x 1.2^2 = 12 + 2.16 = 14.16 m2. At the second section, A2 = 10 x 2.4 + 1.5 x 2.4^2 = 24 + 8.64 = 32.64 m2. Their average is (14.16 + 32.64)/2 = 23.40 m2. The estimated cutting volume is 23.40 x 25 = 585 m3. The computation includes the rectangular portion and the side-slope contributions at both end sections.
వివరణ:
Question 13
ప్రశ్న 13
A road cutting has a formation width of 8 m and unequal side slopes of 1 horizontal to 1 vertical on the left and 2 horizontal to 1 vertical on the right. The cutting depths at two sections are 1 m and 2 m on level transverse ground. If the sections are 20 m apart, what is the volume by the mean sectional area method?
Explanation:
For unequal side slopes on level transverse ground, sectional area is A = Bd + [(m1 + m2)/2]d^2. The effective combined side-slope coefficient is (1 + 2)/2 = 1.5. At the first section, A1 = 8 x 1 + 1.5 x 1^2 = 9.5 m2. At the second section, A2 = 8 x 2 + 1.5 x 2^2 = 22 m2. The mean sectional area is (9.5 + 22)/2 = 15.75 m2. Therefore the estimated volume is 15.75 x 20 = 315 m3.
వివరణ:
Question 14
ప్రశ్న 14
Two consecutive excavation sections have trapezoidal geometries. The first has a bottom width of 6 m, top width of 10 m and depth of 2 m; the second has a bottom width of 6 m, top width of 14 m and depth of 3 m. If their longitudinal spacing is 40 m, what is the mean-sectional-area volume?
Explanation:
The area of a trapezoidal section is half the sum of its parallel widths multiplied by its depth. The first sectional area is (6 + 10)/2 x 2 = 16 m2. The second sectional area is (6 + 14)/2 x 3 = 30 m2. The mean sectional area is (16 + 30)/2 = 23 m2. Multiplying by the longitudinal spacing gives 23 x 40 = 920 m3. The two individual sectional areas must be calculated before averaging because the sectional dimensions differ.
వివరణ:
Question 15
ప్రశ్న 15
The sectional areas at two consecutive stations are 14.5 m2 and 21.5 m2. Their spacing is 24 m. What earthwork volume is obtained by the mean sectional area method?
Explanation:
The two sectional areas are 14.5 m2 and 21.5 m2. Their sum is 36.0 m2. Dividing by two gives a mean sectional area of 18.0 m2. The interval length is 24 m. The earthwork volume is therefore 18.0 x 24 = 432 m3. The units are consistent because square metres multiplied by metres produce cubic metres.
వివరణ:
Question 16
ప్రశ్న 16
At the beginning of a 20 m earthwork interval, the cross-sectional area is zero, while the area at the end is 22 m2. If the mean sectional area method is expressly specified, what volume does that method estimate?
Explanation:
The question specifically requires the mean sectional area method. Its formula is V = L(A1 + A2)/2. The end-sectional areas are zero and 22 m2. Their arithmetic mean is (0 + 22)/2 = 11 m2. Multiplying by the 20 m interval gives an estimated volume of 220 m3. For a sharply tapering three-dimensional earthwork shape, this average-end-area estimate may differ from the true geometric volume, so the prescribed method must be distinguished from an exact-volume calculation.
వివరణ:
Question 17
ప్రశ్న 17
A 50 m earthwork interval begins with a cutting area of 12 m2 and ends with a filling area of 18 m2. Assume the SIGNED sectional area varies linearly from +12 m2 for cutting to -18 m2 for filling. Using the mean sectional area method separately on either side of the zero-area transition, what are the respective cutting and filling volumes?
Explanation:
The signed sectional area changes from +12 m2 to -18 m2 over a distance of 50 m. Under the stated linear-area assumption, the zero-area transition lies 50 x 12/(12 + 18) = 20 m from the starting station. The cutting reach is therefore 20 m long, and the filling reach is 30 m long. The cutting volume is (12 + 0)/2 x 20 = 120 m3. The filling volume is (0 + 18)/2 x 30 = 270 m3. These quantities must be reported separately rather than combined algebraically. The calculation is based on linear variation of signed sectional area, not merely linear variation of centre-line depth.
వివరణ:
Question 18
ప్రశ్న 18
Two cross sections, 30 m apart, each contain BOTH cutting and filling areas. At the first section, cutting area is 8 m2 and filling area is 3 m2. At the second section, cutting area is 12 m2 and filling area is 5 m2. Assuming the areas of each type vary linearly between sections, what are the respective volumes by the mean sectional area method?
Explanation:
The cross sections contain separate cutting and filling portions. The mean cutting area is (8 + 12)/2 = 10 m2. Its estimated volume over 30 m is 10 x 30 = 300 m3. The mean filling area is (3 + 5)/2 = 4 m2. Its estimated volume is 4 x 30 = 120 m3. Cutting and filling are distinct earthwork operations, so their volumes should not be reduced to a single net quantity. The stated linear-area assumption permits the average-end-area calculation to be applied separately to each type.
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Question 19
ప్రశ్న 19
At the ends of a 25 m excavation interval, the measured soil-cutting areas are 12 m2 and 20 m2, while rock-cutting areas are 4 m2 and 6 m2 respectively. Using the mean sectional area method separately for each excavation class, what are the SOIL and ROCK quantities?
Explanation:
The excavation is classified into soil and rock quantities that must be measured separately. The mean soil-cutting area is (12 + 20)/2 = 16 m2. Its estimated quantity is 16 x 25 = 400 m3. The mean rock-cutting area is (4 + 6)/2 = 5 m2. Its estimated quantity is 5 x 25 = 125 m3. The combined physical excavation volume is 525 m3, but the classified quantities should remain separate for estimation and payment. This avoids applying one excavation rate indiscriminately to different material classes.
వివరణ:
Question 20
ప్రశ్న 20
Three successive sections at chainages 0+000, 0+020 and 0+050 have areas of 10 m2, A m2 and 18 m2 respectively. The total volume calculated by the mean sectional area method is 770 m3. What is the UNKNOWN intermediate sectional area A?
Explanation:
The first interval is 20 m long, and the second interval is 30 m long. The total volume equation is 770 = 20(10 + A)/2 + 30(A + 18)/2. Expanding the terms gives 770 = 100 + 10A + 15A + 270. Combining constants and coefficients produces 770 = 370 + 25A. Therefore 25A = 400, giving A = 16 m2. Substitution confirms that the interval volumes are 260 m3 and 510 m3, whose sum is 770 m3.
వివరణ:
Question 21
ప్రశ్న 21
Four consecutive earthwork cross sections have areas of 10 m2, 14 m2, 18 m2 and 30 m2, with a uniform spacing of 20 m between successive sections. Which total volume is correct under the mean sectional area method?
Explanation:
Four sections define three intervals of 20 m each. The mean areas of successive pairs are (10 + 14)/2 = 12 m2, (14 + 18)/2 = 16 m2 and (18 + 30)/2 = 24 m2. The interval volumes are therefore 240 m3, 320 m3 and 480 m3. Their sum is 240 + 320 + 480 = 1,040 m3. Simply averaging all four sectional areas and multiplying by the full 60 m length would give 1,080 m3, which is incorrect for this method. The first and last sectional areas receive half-weighting in the correct equal-interval expression.
వివరణ:
Question 22
ప్రశ్న 22
For a 30 m earthwork interval, the end-sectional areas are 9 m2 and 25 m2, while the measured midpoint sectional area is 15 m2. By how much does the mean sectional area method result EXCEED the volume obtained using the prismoidal formula?
Explanation:
The mean sectional area volume is V = 30(9 + 25)/2 = 510 m3. The prismoidal formula is Vp = L(A1 + 4Am + A2)/6. Substituting the given areas gives Vp = 30(9 + 4 x 15 + 25)/6. The bracketed sum is 9 + 60 + 25 = 94. The prismoidal result is therefore 30 x 94/6 = 470 m3. The mean sectional area estimate exceeds the prismoidal estimate by 510 - 470 = 40 m3. The difference occurs because the two formulas use different information about the variation of sectional area.
వివరణ:
Question 23
ప్రశ్న 23
An earthwork interval is 40 m long and has end-sectional areas of 10 m2 and 30 m2. A new cross section measured at its midpoint has an area of 12 m2. What is the REVISED total volume if the mean sectional area method is applied separately to the two 20 m subintervals?
Explanation:
The original 40 m interval is divided into two 20 m subintervals. For the first subinterval, the end areas are 10 m2 and 12 m2. Its estimated volume is (10 + 12)/2 x 20 = 220 m3. For the second subinterval, the end areas are 12 m2 and 30 m2. Its volume is (12 + 30)/2 x 20 = 420 m3. The revised total is therefore 220 + 420 = 640 m3. The original two-section estimate would be 800 m3, illustrating how additional measured sections can change the calculated quantity.
వివరణ:
Question 24
ప్రశ్న 24
Consider the following statements about the mean sectional area method: Statement I: If cross-sectional area varies linearly with longitudinal distance, the method gives the exact geometric volume for that interval. Statement II: For symmetrical trapezoidal earthwork sections with fixed formation width and side slopes, averaging the end depths before calculating one sectional area always gives the same volume as averaging the two complete end-sectional areas. Which option is correct?
Explanation:
The mean sectional area method is mathematically exact when sectional area varies linearly along the interval. Under that condition, the integral of sectional area equals the interval length multiplied by the arithmetic mean of the end areas. Statement I is therefore correct. For symmetrical earthwork with side slopes, the sectional area is A = Bd + md^2. Because this relationship contains the square of depth, averaging depths before calculating the area generally differs from averaging the complete end areas. Statement II is consequently incorrect, except in special cases where the relevant difference vanishes.
వివరణ:
Question 25
ప్రశ్న 25
Five consecutive earthwork cross sections at chainages 0+000, 0+020, 0+050, 0+070 and 0+100 have areas of 6 m2, 14 m2, 10 m2, 18 m2 and 22 m2 respectively. Using the mean sectional area method with the ACTUAL interval lengths, what is the TOTAL earthwork volume?
Explanation:
The four successive interval lengths are 20 m, 30 m, 20 m and 30 m. The first interval volume is (6 + 14)/2 x 20 = 200 m3. The second interval volume is (14 + 10)/2 x 30 = 360 m3. The third interval volume is (10 + 18)/2 x 20 = 280 m3. The fourth interval volume is (18 + 22)/2 x 30 = 600 m3. Adding all four interval volumes gives 200 + 360 + 280 + 600 = 1,440 m3. The calculation correctly uses each sectional area with its associated intervals rather than assuming uniform spacing.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Find the arithmetic mean of the two end-sectional areas and multiply it by the distance between the sections. సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. 700 m3. సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. 342 m3. సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. 800 m3. సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. 1,235 m3. సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: A. 960 m3. సమాధానం: A.
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Question 7 ప్రశ్న 7Answer: C. 60 m. సమాధానం: C.
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Question 8 ప్రశ్న 8Answer: D. 1,740 m3. సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. 740 m3. సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: C. 1,575 m3. సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. 345 m3. సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. 585 m3. సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: B. 315 m3. సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: C. 920 m3. సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: A. 432 m3. సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: D. 220 m3. సమాధానం: D.
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Question 17 ప్రశ్న 17Answer: C. 120 m3 cutting and 270 m3 filling. సమాధానం: C.
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Question 18 ప్రశ్న 18Answer: D. 300 m3 cutting and 120 m3 filling. సమాధానం: D.
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Question 19 ప్రశ్న 19Answer: A. 400 m3 soil and 125 m3 rock. సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: A. 16 m2. సమాధానం: A.
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Question 21 ప్రశ్న 21Answer: C. 1,040 m3. సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: B. 40 m3. సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: D. 640 m3. సమాధానం: D.
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Question 24 ప్రశ్న 24Answer: A. Statement I is correct, but Statement II is incorrect. సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: B. 1,440 m3. సమాధానం: B.
