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Question 1
ప్రశ్న 1
Which statement best describes yield-line analysis of reinforced concrete slabs?
Explanation:
Yield-line theory is concerned with the ultimate flexural collapse of slabs. At collapse, plastic rotations are idealized as being concentrated along yield lines while the regions between them act as rigid slab segments for the mechanism calculation. A kinematically admissible assumed mechanism is analysed using plastic moment capacities. Such a mechanism gives an upper-bound estimate of the true collapse load, so alternative plausible mechanisms must be investigated. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
What is meant by a positive yield line in a conventionally reinforced RCC slab subjected to downward gravity loading?
Explanation:
A positive bending moment produces sagging curvature in the slab. Under the usual downward loading convention, this places the bottom face in flexural tension. A positive yield line therefore forms when the positive moment resistance associated principally with the bottom reinforcement is mobilized. Plastic rotation can then occur along that line at approximately the positive plastic moment capacity. Therefore Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
Which description correctly identifies a negative yield line in an RCC slab?
Explanation:
Negative bending produces hogging curvature. For the usual slab orientation, this places the top face in flexural tension. Negative yield lines can consequently develop near restrained or continuous supports where adequate top reinforcement and rotational restraint exist. Their plastic moment resistance contributes to the internal work of the collapse mechanism. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
When is a set of yield lines considered to form a collapse mechanism?
Explanation:
Formation of one isolated yielded section does not necessarily create structural collapse. A mechanism requires sufficient plastic lines to permit the slab pieces to move relative to one another without violating the displacement restraints at the supports. In the idealized mechanism, the regions bounded by yield lines are treated as rigid segments. Relative rotation occurs along the yield lines while the moment resistance remains at its plastic value. Therefore Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
Which two methods are commonly used to determine collapse loads in classical yield-line analysis?
Explanation:
Classical yield-line analysis can be carried out using the virtual-work method. It can also be performed by considering equilibrium of the individual rigid slab segments. These approaches are commonly called the virtual-work and segmental-equilibrium methods. For the same correctly defined collapse mechanism, the two approaches should lead to the same collapse result. Therefore Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
What equation expresses the virtual-work principle at collapse in yield-line analysis?
Explanation:
A compatible small virtual displacement is imposed on the assumed collapse mechanism. The applied loads perform external work during this displacement. Plastic rotations along the yield lines dissipate internal work. At collapse, the virtual-work equation equates the total external work to the total internal work for the assumed mechanism. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
A straight yield line has constant plastic moment resistance m per unit length, length L and relative rotation theta across it. What is its contribution to internal work?
Explanation:
The plastic moment resistance m is specified per unit length of yield line. Multiplication by the yield-line length L gives the total resisting moment acting along that line. Plastic work is moment multiplied by the compatible relative rotation across the line. The internal-work contribution is therefore mLtheta when m and theta are uniform along the line. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
For a uniformly distributed load w acting over a slab area A, how is the external virtual work generally obtained in yield-line analysis?
Explanation:
Different points of a collapsing slab generally undergo different virtual displacements. A distributed load therefore does not perform work equal simply to total load multiplied by the maximum displacement. Instead, the local load intensity is multiplied by the local compatible displacement and integrated over the loaded area. For simple rigid triangular or polygonal slab segments, this integration can often be evaluated using the displacement of the segment centroid. Therefore Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
An isotropically reinforced square slab of side L is simply supported along all four edges and carries a uniformly distributed collapse load w. For the standard symmetric X-shaped yield-line mechanism with positive plastic moment resistance m per unit length, which relation is obtained?
Explanation:
For the symmetric X mechanism, four triangular rigid slab segments meet at the slab centre. Taking a central virtual displacement delta, the total internal work along the four positive yield lines is 8m delta. The external work of the uniformly distributed load is wL squared delta divided by 3. Equating internal and external work gives wL squared/3 = 8m. Hence w = 24m/L squared and Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
A 5 m by 5 m isotropically reinforced slab is simply supported on all four edges. Assuming the standard symmetric X-shaped mechanism and positive plastic moment resistance m = 30 kN·m/m, what uniformly distributed collapse load is obtained?
Explanation:
For the stated simply supported square mechanism, the collapse-load relation is w = 24m/L squared. Substituting m = 30 kN·m/m and L = 5 m gives w = 24 × 30/25. This equals 28.8 kN/m². The result is an upper-bound collapse load corresponding to the explicitly assumed X-shaped mechanism. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
A square slab is fixed along all four edges and is assumed to collapse in the symmetric mechanism consisting of positive diagonal yield lines and negative yield lines along all four fixed edges. If the positive and negative plastic moment capacities are m+ and m- respectively, which collapse-load relation follows for a uniformly distributed load?
Explanation:
The positive diagonal yield lines dissipate internal work equal to 8m+ delta for a central virtual displacement delta. The four fixed boundaries act as negative yield lines and contribute a further 8m- delta. Thus the total internal work is 8(m+ + m-)delta. The external work remains wL squared delta divided by 3 for the symmetric mechanism. Equating the two gives w = 24(m+ + m-)/L squared, so Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
A 5 m square slab fixed on all four edges has positive plastic moment capacity m+ = 25 kN·m/m and negative plastic moment capacity m- = 15 kN·m/m. Assuming the standard symmetric fixed-edge mechanism under UDL, what collapse load is obtained?
Explanation:
For the specified fixed square mechanism, w = 24(m+ + m-)/L squared. The combined plastic resistance is 25 + 15 = 40 kN·m/m. Hence w = 24 × 40/25 = 38.4 kN/m². Both positive and negative yield lines contribute positive energy dissipation even though their bending signs are opposite. Therefore Option D is correct.
వివరణ:
Question 13
ప్రశ్న 13
An isotropically reinforced square slab is simply supported along all four edges and is subjected to a single concentrated load at its centre. For the symmetric X-shaped yield-line mechanism, the positive plastic moment resistance is 22 kN·m/m. What collapse point load is predicted?
Explanation:
For a unit central virtual displacement delta, the four diagonal positive yield lines dissipate internal work equal to 8m delta. The concentrated load at the centre moves through the full displacement delta, so its external work is P delta. Equating the works gives P = 8m. With m = 22 kN·m/m, P = 8 × 22 = 176 kN. Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
Consider a one-way slab strip of span L, simply supported at both ends and carrying a uniformly distributed collapse load w. If a positive yield line forms across the full strip width at midspan with plastic moment resistance m per unit width, what collapse-load relation is obtained?
Explanation:
At collapse the two halves of the strip rotate about the simple supports. If the midspan displacement is delta, each half has a rotation of approximately 2delta/L and the relative rotation across the central yield line is 4delta/L. For a strip width B, the internal work is 4mBdelta/L. The UDL external work is wBLdelta/2 because the deflected shape is triangular along the span. Equating the works gives w = 8m/L squared, so Option C is correct.
వివరణ:
Question 15
ప్రశ్న 15
A one-way simply supported slab strip has span 4 m and positive plastic moment resistance m = 24 kN·m/m. Assuming the standard midspan yield-line mechanism under uniform loading, what collapse load is obtained?
Explanation:
For the stated one-way simply supported mechanism, w = 8m/L squared. Substitution gives w = 8 × 24/4 squared. Since 4 squared is 16, the result is 192/16 = 12 kN/m². The strip width cancels from the virtual-work equation because both external and internal work are proportional to it. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
A one-way slab strip is fixed at both ends and collapses with one positive yield line at midspan and negative yield lines at both supports. If the positive and negative plastic moment capacities are m+ and m- respectively, which collapse-load relation applies under uniform loading?
Explanation:
The positive midspan yield line undergoes the relative rotation between the two slab halves. Each fixed support also develops a negative plastic rotation relative to the stationary support. Adding the work of the positive and two negative yield lines gives internal work proportional to m+ + m-. Equating this work to that of the uniformly distributed load gives w = 8(m+ + m-)/L squared. Therefore Option D is correct.
వివరణ:
Question 17
ప్రశ్న 17
A one-way slab strip fixed at both ends has span 4 m, positive plastic moment resistance m+ = 20 kN·m/m and negative plastic moment resistance m- = 15 kN·m/m. What uniformly distributed collapse load follows from the standard three-yield-line mechanism?
Explanation:
For a fixed-ended one-way strip, w = 8(m+ + m-)/L squared for the stated mechanism. The combined moment resistance is 20 + 15 = 35 kN·m/m. Therefore w = 8 × 35/16 = 280/16. This equals 17.5 kN/m². Hence Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
Which statement correctly distinguishes isotropically and orthotropically reinforced slabs in yield-line analysis?
Explanation:
An isotropic yield-moment idealization has the same plastic moment resistance in the two orthogonal principal directions. Consequently the effective moment resistance of a yield line is independent of its orientation in the slab plane. In an orthotropically reinforced slab, the principal moment capacities differ because the reinforcement or section properties differ by direction. The orientation of a yield line then affects the moment resistance mobilized along it. Therefore Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
For an orthotropically reinforced slab, use the supplied relation m(alpha) = mx cos²(alpha) + my sin²(alpha). If mx = 30 kN·m/m, my = 15 kN·m/m and the yield line makes alpha = 60 degrees with the x-axis, what value of m(alpha) is obtained?
Explanation:
For 60 degrees, cos²60 degrees = 0.25 and sin²60 degrees = 0.75. The first contribution is therefore 30 × 0.25 = 7.5 kN·m/m. The second contribution is 15 × 0.75 = 11.25 kN·m/m. Their sum is 18.75 kN·m/m. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
Three different kinematically admissible yield-line mechanisms for the same slab predict collapse loads of 42 kN/m², 37 kN/m² and 40 kN/m². According to the upper-bound character of yield-line analysis, which value should govern among these mechanisms?
Explanation:
Each kinematically admissible mechanism provides an upper bound to the true collapse load under the idealized plastic theory. A poor assumed mechanism can therefore predict a load that is too high. Several plausible patterns should be investigated rather than accepting the first mechanism examined. Among the three stated mechanisms, 37 kN/m² is the lowest predicted collapse load and is consequently the critical upper-bound solution of those considered. Therefore Option D is correct.
వివరణ:
Question 21
ప్రశ్న 21
Which statement most accurately distinguishes yield-line analysis from ordinary elastic slab analysis?
Explanation:
Elastic plate analysis considers the stiffness of the slab and the distribution of moments before substantial yielding occurs. Yield-line analysis instead idealizes the slab at an ultimate flexural mechanism after sufficient plastic moment capacities have been mobilized. It therefore does not reproduce the elastic moment distribution that exists at normal service loads. Crack control, deflection and other serviceability requirements cannot be established merely from a yield-line collapse calculation. Therefore Option B is correct.
వివరణ:
Question 22
ప్రశ్న 22
How does changing an edge from simply supported to fully rotationally restrained affect a typical yield-line collapse mechanism, assuming adequate top reinforcement is present?
Explanation:
A simply supported boundary is idealized as having no significant negative moment resistance. A rotationally restrained edge with adequate top reinforcement can develop hogging moment up to its negative plastic capacity. A negative yield line may therefore occur along or near that restrained boundary as part of the collapse mechanism. Its plastic rotation dissipates additional internal work and can increase the predicted collapse load relative to the comparable simply supported mechanism. Therefore Option A is correct.
వివరణ:
Question 23
ప్రశ్న 23
Which requirement is essential for an assumed yield-line pattern to be kinematically admissible?
Explanation:
An upper-bound collapse mechanism must be geometrically possible. The rigid slab segments have to rotate and translate in a manner that fits together along their common yield lines. They must also satisfy displacement restrictions at supports and other constrained boundaries. A mechanism that requires an impossible separation, overlap or prohibited support displacement is not kinematically admissible. Therefore Option C is correct.
వివరణ:
Question 24
ప్రశ్న 24
A yield line has plastic moment resistance m = 30 kN·m/m, length 4.0 m and compatible relative rotation 0.020 rad. What internal work is dissipated along this yield line?
Explanation:
Internal work along a straight yield line is mLtheta when the moment resistance and rotation are uniform. The total plastic resisting moment along the line is 30 × 4 = 120 kN·m. Multiplying by the relative rotation 0.020 gives 120 × 0.020 = 2.40 kN·m. The rotation must be the relative rotation between the adjoining slab segments, not an unrelated absolute rotation. Therefore Option D is correct.
వివరణ:
Question 25
ప్రశ్న 25
An isotropically reinforced 6 m by 6 m square slab is simply supported on all four edges and is assumed to collapse in the standard symmetric X-shaped mechanism. If its positive plastic moment resistance is 18 kN·m/m, what uniformly distributed collapse load follows from virtual work?
Explanation:
For the stated symmetric simply supported square mechanism, the internal work is 8m delta. The external work is wL squared delta divided by 3. Equating these quantities gives w = 24m/L squared. Substituting m = 18 kN·m/m and L = 6 m gives w = 24 × 18/36 = 12 kN/m². Therefore Option C is correct.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. It is a plastic-collapse method in which an assumed kinematically admissible yield-line mechanism gives an upper-bound estimate of collapse load సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. A line associated with positive or sagging bending, with principal flexural tension at the bottom face సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. It is associated with hogging bending and yielding of reinforcement near the top face సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. When enough yield lines have formed to divide the slab into segments that can undergo compatible rigid-body rotations consistent with the supports సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. Virtual-work method and segmental-equilibrium method సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. External work done by the collapse loads equals internal work dissipated along the yield lines సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. mLtheta సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. By integrating the load multiplied by the compatible virtual displacement over the loaded slab area సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. w = 24m/L squared సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: C. 28.8 kN/m² సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. w = 24(m+ + m-)/L squared సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. 38.4 kN/m² సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: B. 176 kN సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: C. w = 8m/L squared సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: A. 12 kN/m² సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: D. w = 8(m+ + m-)/L squared సమాధానం: D.
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Question 17 ప్రశ్న 17Answer: B. 17.5 kN/m² సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. In an isotropically reinforced slab the relevant plastic moment capacity is direction-independent, whereas an orthotropic slab has different capacities associated with its principal reinforcement directions సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: A. 18.75 kN·m/m సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: D. 37 kN/m² because the lowest admissible upper-bound collapse load is the critical one among those examined సమాధానం: D.
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Question 21 ప్రశ్న 21Answer: B. Yield-line analysis investigates an ultimate plastic collapse mechanism, whereas elastic analysis evaluates pre-yield force and deformation distributions based on elastic stiffness assumptions సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: A. The restrained edge can develop a negative yield line and contribute additional internal plastic work సమాధానం: A.
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Question 23 ప్రశ్న 23Answer: C. The slab segments must undergo compatible motions while satisfying the displacement restraints imposed by the supports సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: D. 2.40 kN·m సమాధానం: D.
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Question 25 ప్రశ్న 25Answer: C. 12 kN/m² సమాధానం: C.
