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Question 1
ప్రశ్న 1
Which group most appropriately represents the standard actions that may have to be considered in the stability analysis of a solid gravity dam?
Explanation:
A gravity dam may be subjected to several permanent, variable and environmental actions. IS 6512 includes dead load, reservoir and tail-water pressures, uplift, earthquake forces, earth and silt pressures, ice pressure, wind pressure, wave pressure and thermal loads as applicable. Not every action necessarily governs every dam or every loading combination. Self-weight and hydrostatic water pressure can generally be calculated relatively directly, whereas actions such as uplift, earthquake and sediment effects require additional assumptions and investigation. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
For a vertical upstream face retaining water to a depth H, which statement correctly describes the static hydrostatic pressure resultant?
Explanation:
Hydrostatic pressure is proportional to depth below the free water surface. Consequently, the pressure diagram on a vertical face is triangular, with zero intensity at the water surface and maximum intensity at the base. The resultant horizontal force equals the area of this triangular pressure diagram. The centroid of a triangle lies one-third of its height from the side having the maximum intensity. Hence the hydrostatic resultant acts at H/3 above the base and Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
A gravity dam has a vertical upstream face retaining water to a depth of 30 m. Taking the unit weight of water as 9.81 kN/m³, what is the horizontal hydrostatic force per metre length of dam?
Explanation:
For a vertical face, the hydrostatic resultant per metre length is P = 0.5 × gamma_w × H². Substitution gives P = 0.5 × 9.81 × 30². This equals 4414.5 kN/m. The force acts horizontally in the downstream direction on the upstream face. Its line of action is 30/3 = 10 m above the base, so Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
For the 30 m water depth in the preceding type of situation, the hydrostatic force is 4414.5 kN/m and acts 10 m above the base. What is its overturning moment about the base level per metre length of dam?
Explanation:
The moment of a force about a point equals the force multiplied by its perpendicular lever arm. The hydrostatic resultant is 4414.5 kN/m. Its line of action is 10 m above the base. Therefore the overturning moment is 4414.5 × 10 = 44,145 kN·m per metre length. Hence Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
A vertical downstream face of a gravity dam is subjected to 6 m of tail-water. Taking gamma_w = 9.81 kN/m³, which result correctly gives the tail-water force and its line of action?
Explanation:
Tail-water pressure also varies hydrostatically with depth. Its resultant is 0.5 × 9.81 × 6² = 176.58 kN/m. Because the pressure distribution is triangular, the force acts at one-third of the 6 m depth from the base. The line of action is therefore 2 m above the base. The tail-water force acts upstream on the downstream face, so Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
A gravity dam has 30 m headwater and 6 m tail-water acting on vertical faces. Ignoring all other horizontal forces and taking gamma_w = 9.81 kN/m³, what is the net horizontal hydrostatic force?
Explanation:
The upstream hydrostatic force is 0.5 × 9.81 × 30² = 4414.50 kN/m acting downstream. The tail-water force is 0.5 × 9.81 × 6² = 176.58 kN/m acting upstream. Because the forces oppose one another, their magnitudes must be subtracted. The net horizontal force is 4414.50 - 176.58 = 4237.92 kN/m downstream. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
A triangular gravity-dam section is 30 m high and 24 m wide at the base, with a vertical upstream face. If the unit weight of concrete is 24 kN/m³, what are the self-weight and its horizontal line of action from the upstream heel per metre length?
Explanation:
The triangular cross-sectional area is 0.5 × 24 × 30 = 360 m². For one metre length of dam, the volume is therefore 360 m³. The weight is 360 × 24 = 8640 kN/m. The centroid of this right triangle is located B/3 from the vertical upstream side, which is 24/3 = 8 m from the heel. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
A gravity-dam section has a vertical upstream face, a top width of 6 m, a base width of 24 m and a height of 30 m. If concrete weighs 24 kN/m³, at what horizontal distance from the upstream heel does the self-weight resultant act?
Explanation:
The trapezoid can be divided into a 6 m × 30 m rectangle and a right triangle having base 18 m and height 30 m. Their areas are 180 m² and 270 m² respectively. Their centroids lie 3 m and 6 + 18/3 = 12 m from the heel. The combined centroid is (180 × 3 + 270 × 12)/(180 + 270) = 8.4 m from the heel. The total weight would be 450 × 24 = 10,800 kN/m, but its line of action is the quantity requested, so Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
What is the principal effect of uplift pressure beneath a gravity dam on its static stability?
Explanation:
Uplift is water pressure acting within joints, cracks, pores and the dam-foundation contact. Its resultant acts upward beneath the dam. It therefore reduces the effective downward normal force provided principally by the self-weight of the structure. This can decrease frictional or shear resistance available against sliding and can also produce a destabilizing moment about the downstream toe. Consequently Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
A gravity dam has a base width of 20 m and an upstream water depth of 25 m, with no tail-water. If the undrained uplift pressure is assumed to decrease linearly from full reservoir pressure at the heel to zero at the toe, what is the uplift resultant per metre length?
Explanation:
With no tail-water, the assumed undrained uplift diagram is triangular. The maximum uplift intensity at the heel is gamma_w H = 9.81 × 25 kPa. The resultant equals the triangular area, U = 0.5 × gamma_w × H × B. Thus U = 0.5 × 9.81 × 25 × 20 = 2452.5 kN/m. The resultant acts B/3 from the high-pressure heel, and therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
At the base of a dam, the uplift pressure corresponds to 24 m water head at the heel and 4 m head at the toe over a base width of 18 m. Assuming a linear pressure variation and gamma_w = 9.81 kN/m³, where does the uplift resultant act from the heel?
Explanation:
The uplift diagram is a trapezoid and can be separated into a rectangle corresponding to 4 m head and a triangle corresponding to the additional 20 m head at the heel. In head-area terms, the rectangular area is 4 × 18 = 72 and acts at 9 m from the heel. The triangular area is 0.5 × 20 × 18 = 180 and acts at 18/3 = 6 m from the heel. Hence the resultant location is (72 × 9 + 180 × 6)/(72 + 180) = 6.86 m approximately. The total uplift is 2472.12 kN/m, and Option A gives the correct line of action.
వివరణ:
Question 12
ప్రశ్న 12
What is the correct conceptual effect of a properly functioning foundation-drainage system beneath a gravity dam?
Explanation:
Foundation drains provide a path through which seepage pressure can be relieved. They can therefore reduce uplift compared with an otherwise undrained condition. The reduction is not normally assumed to make uplift vanish over the complete base. Design uplift depends on reservoir level, tail-water, drain location, effectiveness and foundation conditions. Hence the appropriate reduced pressure distribution must still be included and Option D is correct.
వివరణ:
Question 13
ప్రశ్న 13
Under the simplified silt-pressure criterion given in IS 6512:2019, the horizontal combined 'silt and water pressure' may be represented by an equivalent fluid having approximately what density?
Explanation:
Deposited silt against the upstream face can impose additional pressure on a gravity dam. The submerged sediment and water effects are considered together in the simplified criterion. IS 6512:2019 gives an equivalent-fluid density of 1360 kg/m³ for calculating the horizontal silt-and-water pressure. The code separately uses 1925 kg/m³ for the corresponding vertical silt-and-water loading, so the two values should not be confused. Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
For a wave height hw = 2.0 m, IS 6512:2019 gives the approximate total wave force as Pw = 20hw² kN per metre length. If the reservoir still-water depth at the dam is 30 m, what is the approximate overturning moment of the wave force about the base, using the specified line of action 0.375hw above still-water level?
Explanation:
For hw = 2 m, the wave force is Pw = 20 × 2² = 80 kN/m. Its line of action is 0.375 × 2 = 0.75 m above the still-water level. Since the still-water depth is 30 m, the force acts 30.75 m above the base. The overturning moment is therefore 80 × 30.75 = 2460 kN·m/m. Hence Option C is correct.
వివరణ:
Question 15
ప్రశ్న 15
According to the approximate wave-pressure representation used for solid gravity dams, where does the resultant wave force act relative to the still-water level?
Explanation:
Wave impact is concentrated near the reservoir water surface rather than over the full reservoir depth. IS 6512 provides an approximate pressure diagram for evaluating this additional action. The resultant of that diagram is taken at a height of 0.375 times the wave height above the still-water level. This location is important when calculating the wave-induced overturning moment because the lever arm can be large even when the total wave force is modest. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
Which statement about ice pressure on a gravity dam is most appropriate?
Explanation:
Ice pressure is an environmental action relevant mainly where significant reservoir ice formation occurs. Expansion, temperature changes and wind effects on ice sheets can transmit horizontal pressure to the dam near the water surface. The magnitude is therefore dependent on climatic and site conditions rather than being equally important at every project. It does not replace the hydrostatic water loading produced by the reservoir. Hence Option D is correct.
వివరణ:
Question 17
ప్రశ్న 17
Which statement best represents the treatment of direct wind pressure in IS 6512:2019 for a massive gravity dam?
Explanation:
Wind can exert pressure directly on exposed portions of a dam. For a massive gravity dam, this direct structural action is generally small compared with major actions such as self-weight and reservoir pressure. IS 6512 consequently notes that direct wind pressure is seldom significant and may be ignored in the dam stability calculation. Wind remains important indirectly because wind acting over the reservoir surface generates waves. Therefore Option B is correct.
వివరణ:
Question 18
ప్రశ్న 18
In a simplified pseudo-static earthquake analysis, a dam monolith has a weight of 9000 kN per metre and a horizontal seismic coefficient of 0.10. If its centroid is 12 m above the base, what are the horizontal inertia force and its corresponding moment about the base?
Explanation:
In a simple pseudo-static representation, the horizontal inertia force on the dam is the seismic coefficient multiplied by the weight. Thus Fh = 0.10 × 9000 = 900 kN per metre. The inertia force is taken through the centroid of the relevant dam mass for this simplified calculation. Its moment about the base is therefore 900 × 12 = 10,800 kN·m per metre. Consequently Option C is correct.
వివరణ:
Question 19
ప్రశ్న 19
During earthquake analysis of a gravity dam with a reservoir, which statement correctly distinguishes dam inertia from hydrodynamic water effects?
Explanation:
Ground acceleration produces inertia effects in the mass of the concrete dam. Reservoir water also responds dynamically to the motion of the dam and foundation. This response can produce hydrodynamic pressure in addition to the static reservoir pressure considered in the earthquake loading condition. The magnitude and distribution depend on the adopted seismic-analysis method and reservoir-structure interaction assumptions. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
For a simplified force system, headwater thrust is 4000 kN/m downstream, tail-water thrust is 300 kN/m upstream, dam weight is 9000 kN/m downward and uplift is 1800 kN/m upward. Neglecting all other forces, what is the magnitude of the resultant applied force?
Explanation:
The net horizontal component is 4000 - 300 = 3700 kN/m downstream. The net vertical component is 9000 - 1800 = 7200 kN/m downward. The magnitude of the resultant is the square root of 3700² + 7200². This gives approximately 8095 kN/m. The resultant is inclined about 27.2 degrees downstream from the vertical, so Option D is correct.
వివరణ:
Question 21
ప్రశ్న 21
For a conventional gravity-dam section, take moments about the downstream toe and define clockwise moments as positive. Which sign assignment is generally correct for the four stated forces?
Explanation:
The upstream hydrostatic force acts downstream at a height above the base and therefore tends to rotate the dam clockwise about the downstream toe. An upward uplift resultant acting to the left of the toe also produces a clockwise moment about that toe. The downward self-weight acting to the left of the toe produces a counter-clockwise resisting moment. Tail-water acts upstream on the downstream face and likewise generally produces a counter-clockwise stabilizing moment. With clockwise defined as positive, Option B gives the correct signs.
వివరణ:
Question 22
ప్రశ్న 22
Why should the beneficial effect of tail-water not be assessed only by subtracting its horizontal thrust from the upstream reservoir thrust?
Explanation:
Tail-water pressure on the downstream face acts upstream and therefore opposes the main headwater thrust. This horizontal component can have a stabilizing effect. However, the downstream water level also influences pore-water and uplift pressure at or near the downstream toe. Increased uplift reduces the effective downward force and can adversely affect stability. A consistent analysis must therefore consider both effects, making Option C correct.
వివరణ:
Question 23
ప్రశ్న 23
Which loading description most appropriately represents the normal operating condition for a solid gravity dam?
Explanation:
A loading combination should represent actions having a reasonable probability of occurring together. Under IS 6512 Load Combination B, the dam carries its dead load with the reservoir at full reservoir elevation, normal dry-weather tail-water and normal uplift. Silt and ice are included where applicable. These actions collectively represent the specified normal-operation condition. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
Which combination correctly represents the flood-discharge loading condition specified for a solid gravity dam?
Explanation:
IS 6512 Load Combination C represents the flood-discharge condition. It specifies the reservoir at maximum flood pool elevation with all gates open and tail-water at the corresponding flood elevation. Normal uplift is included rather than being neglected, and silt is included where applicable. These hydraulic actions must be considered together because they represent the prescribed flood operating condition. Therefore Option D is correct.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about forces acting on a gravity dam: I. Self-weight normally provides an important stabilizing downward action. II. Hydrostatic pressure on a vertical upstream face varies linearly with depth. III. Uplift generally reduces the effective downward force available for stability. IV. Tail-water thrust generally acts opposite to upstream reservoir thrust. Which option is correct?
Explanation:
Statement I is correct because a gravity dam relies strongly on its own weight for stability. Statement II is correct because static water pressure is proportional to depth. Statement III is correct because uplift acts upward and reduces the effective downward force on the foundation. Statement IV is correct because tail-water on the downstream face exerts an upstream-directed hydrostatic thrust. Therefore all four statements are correct and Option C is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Dead load, reservoir and tail-water loads, uplift, earthquake forces, earth and silt pressures, ice, wind, wave and thermal loads as applicable సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. Pressure increases linearly with depth, and the resultant acts at H/3 above the base సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. 4414.5 kN/m సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. 44,145 kN·m/m సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. 176.58 kN/m acting 2 m above the base సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. 4237.92 kN/m downstream సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. 8640 kN/m acting 8 m from the heel సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. 8.4 m సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. It acts upward, reducing the effective downward force and generally reducing resistance to sliding and overturning సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: C. 2452.5 kN/m సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. Approximately 6.86 m from the heel సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. It can reduce uplift near the drainage line, but uplift must still be included using the specified pressure distribution సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: B. 1360 kg/m³ సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: C. 2460 kN·m/m సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: A. At a height of 0.375hw above the still-water level సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: D. Where relevant, ice can exert a predominantly horizontal action near the reservoir surface and should be evaluated for applicable climatic conditions సమాధానం: D.
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Question 17 ప్రశ్న 17Answer: B. Direct wind pressure exists but is seldom significant for the dam body and may generally be ignored, although wind is important in generating waves సమాధానం: B.
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Question 18 ప్రశ్న 18Answer: C. 900 kN and 10,800 kN·m సమాధానం: C.
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Question 19 ప్రశ్న 19Answer: A. Earthquake shaking can produce inertia force in the dam body and an additional hydrodynamic pressure response of the reservoir water సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: D. Approximately 8095 kN/m సమాధానం: D.
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Question 21 ప్రశ్న 21Answer: B. Headwater positive, uplift positive, self-weight negative and tail-water negative సమాధానం: B.
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Question 22 ప్రశ్న 22Answer: C. Because tail-water can provide an upstream stabilizing thrust while also contributing to uplift pressure toward the downstream toe సమాధానం: C.
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Question 23 ప్రశ్న 23Answer: A. Dead load with full reservoir elevation, normal dry-weather tail-water, normal uplift, and applicable silt and ice effects సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: D. Reservoir at maximum flood pool elevation, all spillway gates open, tail-water at flood elevation, normal uplift and applicable silt effects సమాధానం: D.
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Question 25 ప్రశ్న 25Answer: C. I, II, III and IV సమాధానం: C.
