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Question 1
ప్రశ్న 1
Which feature fundamentally distinguishes open-channel flow from ordinary pressure flow in a pipe running full?
Explanation:
Open-channel flow is characterized by the presence of a free surface between the flowing liquid and the gas above it. The pressure at that free surface is ordinarily atmospheric when the channel is open to the atmosphere. Open-channel flow may occur in natural channels such as rivers or in artificial channels such as canals and flumes. The liquid below the surface can have nonzero pressure because of its depth. Therefore Option A is correct.
వివరణ:
Question 2
ప్రశ్న 2
What is the principal driving mechanism for ordinary gravity flow in an open channel?
Explanation:
Open-channel flow is primarily driven by gravity acting on the liquid mass. When the channel bed has a longitudinal slope, a component of the fluid weight acts in the direction of flow. Boundary resistance opposes this motion and influences the resulting velocity and depth. A completely enclosed pressure difference is not required as it is in many full-pipe systems. Therefore Option A is correct.
వివరణ:
Question 3
ప్రశ్న 3
Which statement best defines a prismatic open channel?
Explanation:
A prismatic channel has constant geometric characteristics along the reach under consideration. Its cross-sectional shape and dimensions do not change with longitudinal distance. Its bed slope is also taken as constant for the usual definition. These geometric conditions do not by themselves guarantee uniform or steady flow. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
For an open-channel cross-section, which set of definitions is correct?
Explanation:
The hydraulic radius is defined as the flow area A divided by the wetted perimeter P. The hydraulic depth is defined as the flow area A divided by the top width T. Both quantities have dimensions of length. Hydraulic radius is widely used in resistance equations, whereas hydraulic depth is particularly important in open-channel Froude-number calculations. Therefore Option A is correct.
వివరణ:
Question 5
ప్రశ్న 5
A rectangular channel is 4.0 m wide and carries water to a depth of 1.5 m. What is its hydraulic radius?
Explanation:
The flow area is A = by = 4.0 × 1.5 = 6.0 m². The wetted perimeter of a rectangular open channel is P = b + 2y = 4.0 + 3.0 = 7.0 m. The free surface is not included in the wetted perimeter. Therefore R = A/P = 6/7 = approximately 0.857 m. Hence Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
A trapezoidal channel has bottom width b = 3 m, flow depth y = 2 m and side slope 1 horizontal to 1 vertical on each side. What are its flow area and hydraulic radius approximately?
Explanation:
For side slope z = 1, the trapezoidal area is A = y(b + zy). Thus A = 2(3 + 1 × 2) = 10 m². The wetted perimeter is P = b + 2y√(1 + z²) = 3 + 4√2 = approximately 8.657 m. Hence R = A/P = 10/8.657 = approximately 1.155 m. Therefore Option B is correct.
వివరణ:
Question 7
ప్రశ్న 7
A symmetric triangular channel has side slope 1.5 horizontal to 1 vertical and carries water to a depth of 2.0 m. What are its hydraulic radius and hydraulic depth approximately?
Explanation:
For a symmetric triangular section, A = zy² = 1.5 × 2² = 6.0 m². Its top width is T = 2zy = 2 × 1.5 × 2 = 6.0 m, so hydraulic depth is A/T = 1.0 m. The wetted perimeter is P = 2y√(1 + z²) = 4√3.25 = approximately 7.211 m. Therefore the hydraulic radius is 6/7.211 = approximately 0.832 m. Hence Option B is correct.
వివరణ:
Question 8
ప్రశ్న 8
For a very wide rectangular open channel in which the width is much greater than the flow depth, which approximation is appropriate for the hydraulic radius?
Explanation:
For a rectangular channel, R = by/(b + 2y). If the width b is much larger than the depth y, the wetted perimeter b + 2y is approximately b. The hydraulic radius then becomes approximately by/b. This simplifies to R approximately equal to y. Therefore Option A is correct.
వివరణ:
Question 9
ప్రశ్న 9
Which boundary is excluded when calculating the wetted perimeter of an ordinary open-channel section?
Explanation:
Wetted perimeter is the length of the solid channel boundary that is in contact with the flowing liquid. The bed and submerged sides are therefore included. The free surface is in contact with the gas above the water rather than the solid channel boundary. It is represented separately by the top width when required. Therefore Option A is correct.
వివరణ:
Question 10
ప్రశ్న 10
What is the hydraulic depth of a rectangular channel carrying water to depth y?
Explanation:
Hydraulic depth is defined as D = A/T. For a rectangular channel, the area is A = by and the top width is T = b. Therefore D = by/b = y. This identity is especially useful when applying the Froude-number formula to rectangular channels. Hence Option B is correct.
వివరణ:
Question 11
ప్రశ్న 11
Which statement correctly distinguishes steady from unsteady open-channel flow?
Explanation:
Steadiness concerns variation with time at a fixed spatial location. If depth, discharge and other flow variables at a specified section remain unchanged with time, the flow is steady. If such quantities change with time, the flow is unsteady. Spatial variation along the channel is a separate issue described by uniform or varied-flow classification. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
Which statement correctly distinguishes uniform from non-uniform open-channel flow?
Explanation:
Uniformity is a spatial classification rather than a time classification. In uniform open-channel flow, quantities such as depth and mean velocity remain constant along the channel reach. In non-uniform or varied flow, one or more such properties change with longitudinal position. A prismatic channel can still carry non-uniform flow if hydraulic conditions force the depth to vary. Therefore Option A is correct.
వివరణ:
Question 13
ప్రశ్న 13
A canal carries a constant discharge with a depth that gradually increases in the downstream direction but does not change with time at any fixed section. How should the flow be classified?
Explanation:
The depth at each fixed section does not change with time, so the flow is steady. The depth nevertheless changes from one section to another in the downstream direction. Therefore the flow is spatially non-uniform. Because the change is described as gradual, it would more specifically be a gradually varied steady flow. Hence Option A is correct.
వివరణ:
Question 14
ప్రశ్న 14
Which statement about a prismatic channel is correct?
Explanation:
Prismatic describes the channel geometry, not the resulting flow regime. A prismatic channel has constant cross-sectional geometry and bed slope along the reach. Uniform flow may occur when the hydraulic conditions permit the depth and velocity to remain constant. Obstructions, downstream controls or changing boundary conditions can produce varied flow even in the same prismatic channel. Therefore Option A is correct.
వివరణ:
Question 15
ప్రశ్న 15
Which statement correctly distinguishes gradually varied flow from rapidly varied flow?
Explanation:
Both gradually and rapidly varied flows are forms of non-uniform open-channel flow. In gradually varied flow, the depth changes slowly over a comparatively long channel distance. In rapidly varied flow, the depth changes significantly over a relatively short distance. Hydraulic jumps are important examples of rapidly varied flow. Therefore Option A is correct.
వివరణ:
Question 16
ప్రశ్న 16
For steady uniform flow in a prismatic open channel, which statement is normally correct along the uniform reach?
Explanation:
Uniform flow requires the flow depth and cross-sectional flow properties to remain constant with distance. In a prismatic channel this also means the mean velocity remains constant when discharge is constant. The component of gravity driving the flow is balanced by boundary resistance. Under the standard uniform-flow description, the bed, water-surface and energy slopes are parallel, with the friction slope equal to the bed slope. Therefore Option A is correct.
వివరణ:
Question 17
ప్రశ్న 17
For an open-channel section of arbitrary shape, which expression gives the Froude number when V is mean velocity and D = A/T is hydraulic depth?
Explanation:
The Froude number compares the mean flow velocity with the characteristic gravity-wave speed. For a general open-channel section, the characteristic depth used in the introductory one-dimensional expression is hydraulic depth D = A/T. The Froude number is therefore Fr = V/√(gD). It is dimensionless because both numerator and denominator have dimensions of velocity. Hence Option A is correct.
వివరణ:
Question 18
ప్రశ్న 18
Which basic open-channel classification based on Froude number is correct?
Explanation:
Froude number provides an important dynamic classification of open-channel flow. A value less than one corresponds to subcritical flow. A value equal to one identifies the critical condition. A value greater than one corresponds to supercritical flow. This classification is distinct from the steady/unsteady and uniform/non-uniform classifications. Therefore Option A is correct.
వివరణ:
Question 19
ప్రశ్న 19
Water flows in a rectangular channel at depth 1.0 m with mean velocity 2.0 m/s. What is the Froude number and basic flow regime? Take g = 9.81 m/s².
Explanation:
For a rectangular channel, hydraulic depth equals the actual flow depth. Thus Fr = V/√(gy) = 2/√(9.81 × 1.0). The denominator is approximately 3.132 m/s. Therefore Fr is approximately 0.639. Since this is below one, the flow is subcritical and Option B is correct.
వివరణ:
Question 20
ప్రశ్న 20
A rectangular channel carries water at depth 0.50 m with mean velocity 3.0 m/s. What is the Froude number and basic regime? Take g = 9.81 m/s².
Explanation:
For the rectangular section, hydraulic depth is 0.50 m. The characteristic gravity-wave speed is √(9.81 × 0.50), which is approximately 2.215 m/s. Dividing the mean velocity 3.0 m/s by this value gives Fr approximately 1.355. Since Fr is greater than one, the flow is supercritical. Therefore Option C is correct.
వివరణ:
Question 21
ప్రశ్న 21
At a channel section the hydraulic depth is 1.20 m. What mean velocity corresponds to the critical condition Fr = 1? Take g = 9.81 m/s².
Explanation:
Critical flow corresponds to Fr = 1. From Fr = V/√(gD), the critical mean velocity is V = √(gD). Substituting D = 1.20 m gives V = √(9.81 × 1.20). This is approximately 3.431 m/s. Therefore Option C is correct.
వివరణ:
Question 22
ప్రశ్న 22
A trapezoidal channel has bottom width 3 m, side slope 1 horizontal to 1 vertical, depth 2 m and mean velocity 2.5 m/s. What is its Froude number approximately? Take g = 9.81 m/s².
Explanation:
The area is A = y(b + zy) = 2(3 + 2) = 10 m². The top width is T = b + 2zy = 3 + 4 = 7 m. Therefore the hydraulic depth is D = A/T = 10/7 = approximately 1.429 m. The Froude number is 2.5/√(9.81 × 1.429) = approximately 0.668. Hence Option B is correct.
వివరణ:
Question 23
ప్రశ్న 23
A rectangular channel 3.0 m wide carries water 0.80 m deep at a mean velocity of 1.5 m/s. What is the discharge?
Explanation:
The flow area of the rectangular channel is A = by. Substitution gives A = 3.0 × 0.80 = 2.40 m². Discharge is Q = AV. Thus Q = 2.40 × 1.5 = 3.60 m³/s. Therefore Option C is correct.
వివరణ:
Question 24
ప్రశ్న 24
A rectangular channel 2.0 m wide carries a discharge of 5.0 m³/s at a depth of 1.0 m. What are the mean velocity and Froude number approximately? Take g = 9.81 m/s².
Explanation:
The rectangular flow area is A = 2.0 × 1.0 = 2.0 m². Therefore the mean velocity is V = Q/A = 5.0/2.0 = 2.50 m/s. Hydraulic depth equals the actual depth of 1.0 m. Hence Fr = 2.50/√9.81 = approximately 0.798. Therefore Option B is correct.
వివరణ:
Question 25
ప్రశ్న 25
Consider the following statements about open-channel flow: I. Hydraulic radius is A/P, where P excludes the free surface. II. Hydraulic depth is A/T. III. Steady flow may still be non-uniform. IV. A prismatic channel does not necessarily carry uniform flow. Which option is correct?
Explanation:
Statement I is correct because wetted perimeter contains only the solid boundary in contact with the liquid. Statement II is the definition of hydraulic depth using flow area and top width. Statement III is correct because steadiness concerns time variation while uniformity concerns spatial variation. Statement IV is correct because a prismatic geometry can carry varied flow under suitable upstream or downstream controls. Therefore all four statements are correct and Option D is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: A. The flowing liquid possesses a free surface exposed to a gas, usually the atmosphere సమాధానం: A.
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Question 2 ప్రశ్న 2Answer: A. The component of the liquid weight acting along the channel సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: A. Its cross-sectional shape, size and bed slope remain unchanged along the reach considered సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: A. Hydraulic radius R = A/P and hydraulic depth D = A/T సమాధానం: A.
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Question 5 ప్రశ్న 5Answer: B. 0.857 m సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: B. A = 10.0 m² and R = 1.155 m సమాధానం: B.
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Question 7 ప్రశ్న 7Answer: B. R = 0.832 m and D = 1.000 m సమాధానం: B.
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Question 8 ప్రశ్న 8Answer: A. R is approximately equal to the flow depth సమాధానం: A.
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Question 9 ప్రశ్న 9Answer: A. The free water surface సమాధానం: A.
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Question 10 ప్రశ్న 10Answer: B. y సమాధానం: B.
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Question 11 ప్రశ్న 11Answer: A. In steady flow, flow properties at a specified section do not change with time; in unsteady flow, they do సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: A. Uniform flow has no variation of flow properties such as depth along the channel, whereas non-uniform flow has spatial variation సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: A. Steady and non-uniform సమాధానం: A.
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Question 14 ప్రశ్న 14Answer: A. A prismatic channel can carry either uniform or non-uniform flow depending on hydraulic conditions సమాధానం: A.
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Question 15 ప్రశ్న 15Answer: A. In gradually varied flow the depth changes over a relatively long distance, whereas in rapidly varied flow substantial depth change occurs over a short distance సమాధానం: A.
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Question 16 ప్రశ్న 16Answer: A. Flow depth, area and mean velocity remain constant, and the friction slope balances the channel-bed slope సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: A. Fr = V/√(gD) సమాధానం: A.
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Question 18 ప్రశ్న 18Answer: A. Fr < 1 subcritical, Fr = 1 critical, Fr > 1 supercritical సమాధానం: A.
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Question 19 ప్రశ్న 19Answer: B. Fr = 0.639; subcritical సమాధానం: B.
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Question 20 ప్రశ్న 20Answer: C. Fr = 1.355; supercritical సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: C. 3.43 m/s సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: B. 0.668 సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: C. 3.60 m³/s సమాధానం: C.
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Question 24 ప్రశ్న 24Answer: B. V = 2.50 m/s and Fr = 0.798 సమాధానం: B.
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Question 25 ప్రశ్న 25Answer: D. I, II, III and IV సమాధానం: D.
