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Question 1
ప్రశ్న 1
Which situation most commonly justifies providing a combined RCC footing instead of two separate isolated footings?
Explanation:
A combined footing supports two or more columns on a common base. It is commonly adopted when separate isolated footings would overlap because the columns are relatively close. It is also useful when a property-line restriction prevents an exterior footing from extending sufficiently on one side. Combining the exterior column with an interior column can permit the foundation resultant and footing geometry to be proportioned more satisfactorily. Therefore Option B is correct.
వివరణ:
Question 2
ప్రశ్న 2
Under the conventional rigid-footing assumption, what condition permits a combined footing to develop a uniform soil-pressure distribution under vertical column loads?
Explanation:
Uniform contact pressure produces a resultant soil reaction acting through the centroid of the loaded footing area. For equilibrium, that soil-reaction resultant must coincide with the resultant of the applied vertical loads. If the two lines of action are separated, a moment exists and the pressure distribution cannot remain uniform under the rigid-base idealization. Accordingly, combined footings are proportioned so that the centre of area coincides with the resultant loading when uniform pressure is intended. Therefore Option C is correct.
వివరణ:
Question 3
ప్రశ్న 3
Two columns C1 and C2 carry service loads of 600 kN and 900 kN respectively and are 4.0 m apart. Neglecting other loads for locating the resultant, how far from C1 does the resultant of the two column loads act?
Explanation:
Take moments of the column loads about C1. The moment of the 900 kN load is 900 × 4 = 3600 kN·m. The total load is 600 + 900 = 1500 kN. Hence the resultant location is 3600/1500 = 2.40 m from C1 toward C2. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
For the columns in the previous question, the left edge of a proposed rectangular combined footing is fixed by a property line 0.50 m to the left of C1. What footing length will place the centroid of the rectangular footing at the resultant of the column loads?
Explanation:
The load resultant is 2.40 m to the right of C1. Since C1 itself is 0.50 m from the left footing edge, the resultant is 0.50 + 2.40 = 2.90 m from that edge. The centroid of a rectangular footing lies at one-half of its length. Therefore L/2 = 2.90 m, giving L = 5.80 m. Hence Option D is correct.
వివరణ:
Question 5
ప్రశ్న 5
For the same two columns, assume the required service-level footing area is based on the 1500 kN total column load plus an estimated 10 percent allowance for footing and backfill weight. If the allowable soil pressure is 200 kN/m² and the footing length is 5.80 m, what constant footing width is required approximately?
Explanation:
The estimated total service load for sizing is 1500 × 1.10 = 1650 kN. The required footing area is therefore 1650/200 = 8.25 m². With a rectangular footing length of 5.80 m, the required width is 8.25/5.80. This gives approximately 1.42 m. Therefore Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
Why may a trapezoidal combined footing be preferred to a rectangular combined footing in some two-column foundation layouts?
Explanation:
The centroid of a rectangular footing is fixed at its geometric centre. Site boundaries and unequal column loads may require the footing-area centroid to be located elsewhere. A trapezoidal plan allows the width to vary along the length and therefore permits adjustment of the centroid. The footing can then be proportioned so that the area centroid coincides with the resultant load when uniform pressure is desired. Therefore Option C is correct.
వివరణ:
Question 7
ప్రశ్న 7
A trapezoidal combined footing has length L and end widths B1 and B2. What is its plan area?
Explanation:
The footing plan is a trapezoid whose parallel sides are the two end widths B1 and B2. The area of a trapezoid is the average of its parallel sides multiplied by their separation. Here the separation is the footing length L. Thus A = L(B1 + B2)/2. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
For a trapezoidal footing whose width varies linearly from B1 at x = 0 to B2 at x = L, which expression gives the centroid distance measured from the B1 end?
Explanation:
The centroid of a trapezoid is not generally at its mid-length when the two end widths differ. Integrating the linearly varying width gives the first moment of area about the B1 end. Dividing that first moment by the trapezoidal area gives x̄ = L(B1 + 2B2)/[3(B1 + B2)]. The expression correctly moves the centroid toward the wider B2 end. Therefore Option D is correct.
వివరణ:
Question 9
ప్రశ్న 9
A trapezoidal combined footing is 6.0 m long and has a required area of 18 m². Its centroid must be 3.5 m from the end of width B1. What end widths B1 and B2 satisfy these requirements?
Explanation:
From the area equation, 18 = 6(B1 + B2)/2, so B1 + B2 = 6. The centroid equation gives 3.5 = 6(B1 + 2B2)/[3(B1 + B2)]. Since B1 + B2 = 6, this reduces to B1 + 2B2 = 10.5. Solving the two equations gives B2 = 4.5 m and B1 = 1.5 m. Therefore Option B is correct.
వివరణ:
Question 10
ప్రశ్న 10
The trapezoidal combined footing in the previous question supports a total service vertical load of 1800 kN, and its centroid coincides with the load resultant. What uniform service soil pressure results?
Explanation:
The footing area is 18 m². Since the load resultant passes through the area centroid, the stated rigid-footing idealization permits a uniform pressure distribution. The pressure is therefore total load divided by area. Thus q = 1800/18 = 100 kN/m². Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
For a rigid rectangular isolated footing of area A subjected to a vertical load P with eccentricity e about one centroidal axis, and with full soil contact maintained over a footing dimension L in the eccentricity direction, which expression gives the extreme pressures?
Explanation:
The contact pressure is obtained from direct pressure plus or minus bending pressure. For a rectangular base, the eccentric moment is M = Pe. Using the rectangular section modulus gives the familiar factor 6e/L for eccentricity about the relevant centroidal axis. The expression is applicable to the full-contact linear-pressure case. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
For a rectangular footing subjected to eccentricity e in one direction, what condition ensures that the resultant remains within the middle third so that the conventional linear pressure distribution has no tensile soil pressure?
Explanation:
Soil is ordinarily assumed unable to sustain significant tension at the footing interface. For a rectangular footing with linear pressure distribution, the minimum pressure becomes zero when e reaches L/6. If e is smaller than or equal to L/6, both extreme pressures remain non-negative. This region is commonly called the middle-third or kern condition for the considered direction. Therefore Option D is correct.
వివరణ:
Question 13
ప్రశ్న 13
A 3.0 m × 2.0 m isolated footing carries a vertical load of 1200 kN with eccentricity 0.20 m along the 3.0 m footing dimension. Assuming full contact and a linear pressure distribution, what are qmax and qmin?
Explanation:
The footing area is 3 × 2 = 6 m², so the average pressure is 1200/6 = 200 kN/m². The eccentricity factor is 6e/L = 6 × 0.20/3.0 = 0.40. Thus qmax = 200(1 + 0.40) = 280 kN/m². Similarly qmin = 200(1 - 0.40) = 120 kN/m². Therefore Option B is correct.
వివరణ:
Question 14
ప్రశ్న 14
For the same 3.0 m × 2.0 m footing and 1200 kN vertical load, what pressure distribution results when the eccentricity along the 3.0 m dimension is exactly L/6 = 0.50 m?
Explanation:
The average pressure remains P/A = 200 kN/m². At e = L/6, the factor 6e/L becomes exactly 1. The maximum pressure is therefore 200(1 + 1) = 400 kN/m². The minimum pressure becomes 200(1 - 1) = zero, producing a triangular distribution over the full base. Therefore Option C is correct.
వివరణ:
Question 15
ప్రశ్న 15
What is the correct interpretation if the resultant eccentricity of a footing exceeds L/6 in one direction?
Explanation:
When e exceeds L/6, the ordinary full-base linear expression predicts a negative pressure at one edge. Foundation soil is normally not relied upon to carry such tensile contact stress. The actual compression zone therefore becomes smaller than the full footing base. Pressure must then be evaluated using an appropriate compression-only contact model rather than accepting the fictitious tensile value. Therefore Option D is correct.
వివరణ:
Question 16
ప్రశ్న 16
A centrally loaded rectangular isolated footing is 3.0 m × 2.4 m in plan and supports a 0.40 m × 0.40 m column placed at its centre. What are the footing projections beyond the column faces in the 3.0 m and 2.4 m directions respectively?
Explanation:
The projection in each direction is half the difference between the footing dimension and corresponding column dimension. Along the 3.0 m direction, the projection is (3.0 - 0.40)/2 = 1.30 m. Along the 2.4 m direction, it is (2.4 - 0.40)/2 = 1.00 m. The unequal projections lead to different flexural demands in the two directions under the same uniform pressure. Therefore Option A is correct.
వివరణ:
Question 17
ప్రశ్న 17
The footing in the previous question carries a uniform factored soil pressure of 250 kN/m². What is the design bending moment per metre width at the column face for cantilever action in the direction having the 1.30 m projection?
Explanation:
For a one-metre strip, the upward line load is 250 kN/m. The footing projection acts as a cantilever of length 1.30 m from the column face for this simplified flexural calculation. The face moment is wL²/2. Thus Mu = 250 × 1.30²/2 = 211.25 kN·m per metre width. Therefore Option C is correct.
వివరణ:
Question 18
ప్రశ్న 18
An M25 footing strip 1000 mm wide has effective depth d = 500 mm and must resist Mu = 211.25 kN·m/m using Fe500 reinforcement. Using the singly reinforced Limit State equations, what flexural tension-steel area is required approximately, before any separate minimum-reinforcement check?
Explanation:
For a singly reinforced section, xu = 0.87fyAst/(0.36fckb). The moment capacity is Mu = 0.87fyAst(d - 0.42xu). Substituting b = 1000 mm, d = 500 mm, fck = 25 N/mm², fy = 500 N/mm² and Mu = 211.25 kN·m gives Ast of approximately 1013 mm²/m. The resulting neutral-axis depth is well within the limiting value for the stated steel grade. Therefore Option B is correct.
వివరణ:
Question 19
ప్రశ్న 19
For longitudinal analysis, how is a conventional combined footing commonly idealized structurally?
Explanation:
A combined footing receives concentrated downward actions from the supported columns. At the same time the soil provides an upward distributed reaction over the footing area. Along its length, these opposing actions generate shear forces and bending moments. The longitudinal footing is therefore analyzed in a beam-like manner using the load, shear and moment diagrams. Therefore Option A is correct.
వివరణ:
Question 20
ప్రశ్న 20
A 6.0 m long rectangular combined footing is 2.0 m wide and carries a uniform factored soil pressure of 200 kN/m². Two factored column loads of 1200 kN each act at x = 1.0 m and x = 5.0 m from the left edge. Taking upward soil reaction as positive, what is the shear force immediately to the right of the first column?
Explanation:
The upward soil reaction per metre length is qB = 200 × 2 = 400 kN/m. Over the first 1.0 m, this produces an upward resultant of 400 kN. Immediately to the right of the first column, the 1200 kN downward column force must also be included. Thus V = 400 - 1200 = -800 kN using the stated upward-positive convention. Therefore Option D is correct.
వివరణ:
Question 21
ప్రశ్న 21
For the combined footing described in the previous question, what is the longitudinal shear at x = 3.0 m from the left edge?
Explanation:
At x = 3.0 m, the upward soil reaction to the left of the section is 400 × 3 = 1200 kN. Only the first 1200 kN column load lies to the left of this section. The upward and downward forces therefore balance exactly. Hence the longitudinal shear at this section is zero. Therefore Option C is correct.
వివరణ:
Question 22
ప్రశ్న 22
For the same combined footing, what is the magnitude of the longitudinal bending moment at x = 3.0 m obtained from the forces to the left of the section?
Explanation:
The upward soil reaction over the first 3 m is 1200 kN and acts at its centroid, 1.5 m from the left edge. Its moment about the section at x = 3 m is therefore 1200 × 1.5 = 1800 kN·m. The first column load is 1200 kN at x = 1 m, giving an opposing moment of 1200 × 2 = 2400 kN·m about the section. The net moment has magnitude 2400 - 1800 = 600 kN·m. Therefore Option B is correct.
వివరణ:
Question 23
ప్రశ్న 23
For local transverse bending of an RCC footing adjacent to a concrete column, where is the critical section for the greatest design bending moment taken under IS 456?
Explanation:
IS 456 specifies the critical bending section for a footing supporting a concrete column or pedestal at the face of the support. The footing projection outside that face behaves locally as a cantilever under upward soil pressure. A section at distance d from the face is associated with the ordinary one-way shear check for a footing on soil, not the maximum bending moment. Punching shear is checked using a different critical perimeter. Therefore Option D is correct.
వివరణ:
Question 24
ప్రశ్న 24
For an interior column of a combined footing on soil, sufficiently far from footing edges, which statement correctly distinguishes the ordinary one-way and punching-shear critical locations?
Explanation:
Footing shear has both wide-beam and two-way punching modes. For a footing on soil, the ordinary one-way critical section is taken at distance d from the column or pedestal face under the amended IS 456 provision. The basic punching-shear perimeter is located at d/2 from the loaded-area periphery. Around that punching perimeter, the column force is considered together with the opposing soil reaction enclosed by the critical area. Therefore Option A is correct.
వివరణ:
Question 25
ప్రశ్న 25
Which reinforcement interpretation is most appropriate for a combined footing whose longitudinal bending-moment diagram changes sign along its length?
Explanation:
A combined footing can develop both positive and negative longitudinal bending because distributed upward reaction is interrupted by concentrated column loads. The tension face therefore changes as the bending-moment sign changes. Reinforcement has to follow that structural demand rather than being placed on only one face throughout without justification. Bars must also extend and be anchored sufficiently to develop their required force at the critical sections. Therefore Option C is correct.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: B. Individual footings would overlap, or an exterior column near a property line cannot be provided with a suitably concentric isolated footing సమాధానం: B.
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Question 2 ప్రశ్న 2Answer: C. The centroid of the footing area should coincide with the line of action of the resultant vertical load సమాధానం: C.
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Question 3 ప్రశ్న 3Answer: A. 2.40 m సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: D. 5.80 m సమాధానం: D.
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Question 5 ప్రశ్న 5Answer: B. 1.42 m సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: C. Because varying the footing width can shift the centroid of area to coincide with an eccentric load resultant when site geometry or unequal column loads make a suitable rectangle inconvenient సమాధానం: C.
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Question 7 ప్రశ్న 7Answer: A. A = L(B1 + B2)/2 సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: D. x̄ = L(B1 + 2B2)/[3(B1 + B2)] సమాధానం: D.
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Question 9 ప్రశ్న 9Answer: B. B1 = 1.5 m and B2 = 4.5 m సమాధానం: B.
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Question 10 ప్రశ్న 10Answer: C. 100 kN/m² సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. qmax,min = (P/A)(1 ± 6e/L) సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: D. e ≤ L/6 సమాధానం: D.
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Question 13 ప్రశ్న 13Answer: B. 280 kN/m² and 120 kN/m² సమాధానం: B.
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Question 14 ప్రశ్న 14Answer: C. A triangular distribution with qmax = 400 kN/m² and qmin = 0 సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: D. Part of the base tends to lose contact because soil tension is not normally relied upon, so a compression-only contact distribution must be considered సమాధానం: D.
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Question 16 ప్రశ్న 16Answer: A. 1.30 m and 1.00 m సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: C. 211.25 kN·m/m సమాధానం: C.
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Question 18 ప్రశ్న 18Answer: B. 1013 mm²/m సమాధానం: B.
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Question 19 ప్రశ్న 19Answer: A. As a continuous or beam-like member subjected to upward distributed soil reaction and downward concentrated column loads సమాధానం: A.
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Question 20 ప్రశ్న 20Answer: D. -800 kN సమాధానం: D.
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Question 21 ప్రశ్న 21Answer: C. 0 kN సమాధానం: C.
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Question 22 ప్రశ్న 22Answer: B. 600 kN·m సమాధానం: B.
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Question 23 ప్రశ్న 23Answer: D. At the face of the concrete column సమాధానం: D.
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Question 24 ప్రశ్న 24Answer: A. One-way shear is checked at distance d from the column face, while the basic punching-shear perimeter is at distance d/2 from the column periphery సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: C. Longitudinal reinforcement should be provided on the appropriate tension face in the positive- and negative-moment regions, with adequate anchorage and development length సమాధానం: C.
