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Question 1
ప్రశ్న 1
What is meant by steady radial groundwater flow toward a fully penetrating pumping well in a confined aquifer?
Explanation:
A pumping well creates a hydraulic-head depression around itself. Under radial-flow idealization, groundwater converges toward the well from different horizontal directions. Steady state means that hydraulic heads at fixed locations have ceased changing with time. The pumping rate is then supported by boundary inflow, induced recharge, reduced natural discharge, or an equivalent source maintaining equilibrium. Therefore Option A is correct.
వివరణ:
Question 2
ప్రశ్న 2
If the initial piezometric head of a confined aquifer is H and the pumping-induced piezometric head at a point is h, how is drawdown s defined?
Explanation:
Drawdown represents the decline in hydraulic head caused by pumping. It is measured relative to the original or reference piezometric head. Hence s = H - h. A larger decline in piezometric head produces a larger drawdown. Therefore Option A is correct.
వివరణ:
Question 3
ప్రశ్న 3
Which set of assumptions is most consistent with the classical steady Thiem solution for a confined aquifer?
Explanation:
The classical Thiem equation is based on an idealized aquifer and well system. Common assumptions include homogeneous and isotropic hydraulic properties and approximately constant confined-aquifer thickness. The pumping well is taken as fully penetrating, and flow toward it is treated as horizontal and radial. Pumping is constant and equilibrium or steady-state conditions are assumed. Therefore Option A is correct.
వివరణ:
Question 4
ప్రశ్న 4
For a homogeneous confined aquifer of hydraulic conductivity K and thickness b, which relation gives transmissivity T?
Explanation:
Transmissivity represents the ability of the entire saturated aquifer thickness to transmit groundwater. For a homogeneous confined aquifer, it is the product of hydraulic conductivity and thickness. Thus T = Kb. If K is expressed in m/day and b in metres, T has units of m²/day. Therefore Option B is correct.
వివరణ:
Question 5
ప్రశ్న 5
For horizontal radial flow through a confined aquifer of thickness b, what is the cross-sectional flow area at radial distance r from a fully penetrating well?
Explanation:
Groundwater approaching the well crosses an imaginary cylindrical surface centered on the well. The circumference of this cylinder is 2πr. Its vertical height is the confined-aquifer thickness b. The corresponding flow area is therefore 2πrb. This radial geometry is fundamental to the derivation of the Thiem equation, so Option B is correct.
వివరణ:
Question 6
ప్రశ్న 6
Two observation wells are located at radii r1 and r2 from a pumping well in a confined aquifer, where r2 > r1 and corresponding piezometric heads are h1 and h2. Which natural-logarithm form of the steady Thiem equation is correct?
Explanation:
Pumping lowers the head more strongly at the observation well nearer the pumping well. Thus for r2 greater than r1, the outer head h2 is normally greater than the inner head h1. Integration of Darcy's law for steady radial confined flow gives Q = 2πT(h2 - h1)/ln(r2/r1). The logarithmic radial dependence produces the characteristic cone of depression in the potentiometric surface. Therefore Option A is correct.
వివరణ:
Question 7
ప్రశ్న 7
Using drawdowns s1 and s2 at observation wells r1 and r2, with r2 > r1, which base-10 logarithm form is equivalent to the confined-aquifer Thiem equation?
Explanation:
Drawdown is larger near the pumping well, so s1 exceeds s2 when r1 is smaller than r2. Converting the natural-log Thiem equation to common logarithms introduces the coefficient approximately 2.73 in the discharge form. Thus Q = 2.73T(s1 - s2)/log10(r2/r1). This equation requires compatible units for Q and T. Therefore Option A is correct.
వివరణ:
Question 8
ప్రశ్న 8
A confined aquifer has transmissivity 300 m²/day. Under steady pumping, drawdowns at observation wells 50 m and 500 m from the well are 6 m and 4 m respectively. Using Q = 2.73T(s1 - s2)/log10(r2/r1), what is the pumping rate?
Explanation:
The radius ratio is 500/50 = 10, so log10(r2/r1) = 1. The drawdown difference is 6 - 4 = 2 m. Substitution gives Q = 2.73 × 300 × 2/1. This equals 1638 m³/day. Therefore Option C is correct.
వివరణ:
Question 9
ప్రశ్న 9
During a steady pumping test, Q = 1092 m³/day. Drawdowns at observation wells 20 m and 200 m from the pumping well are 5 m and 3 m respectively. What is the aquifer transmissivity?
Explanation:
For two observation wells, T = Q log10(r2/r1)/[2.73(s1 - s2)]. Here r2/r1 = 200/20 = 10, so the logarithm is 1. The drawdown difference is 5 - 3 = 2 m. Thus T = 1092/[2.73 × 2] = 200 m²/day. Therefore Option C is correct.
వివరణ:
Question 10
ప్రశ్న 10
A confined aquifer has T = 200 m²/day and is pumped steadily at Q = 546 m³/day. If drawdown at r1 = 20 m is 4 m, what is the drawdown at r2 = 200 m?
Explanation:
The Thiem drawdown difference is s1 - s2 = Q log10(r2/r1)/(2.73T). The radius ratio is 200/20 = 10, giving a common logarithm of 1. Hence s1 - s2 = 546/(2.73 × 200) = 1 m. Since s1 = 4 m, s2 = 4 - 1 = 3 m. Therefore Option C is correct.
వివరణ:
Question 11
ప్రశ్న 11
Under steady pumping from a confined aquifer, how does piezometric head generally vary with radial distance away from the pumping well within the cone of depression?
Explanation:
The largest pumping-induced head reduction occurs close to the pumping well. Drawdown decreases outward from the well. Since piezometric head equals the original head minus drawdown, the head therefore increases outward through the cone of depression. The radial hydraulic gradient drives groundwater toward the lower head at the pumping well. Therefore Option A is correct.
వివరణ:
Question 12
ప్రశ్న 12
For an ideal steady confined aquifer having radius of influence R and pumping-well radius rw, which equation gives pumping rate Q in terms of well drawdown sw and transmissivity T?
Explanation:
At the idealized radius of influence, pumping-induced drawdown is taken as negligible. Integrating radial flow from the well radius to that boundary gives the confined Thiem relation. In base-10 logarithmic form it is Q = 2.73Tsw/log10(R/rw). This expression represents aquifer drawdown and neglects additional mechanical or turbulent well losses. Therefore Option A is correct.
వివరణ:
Question 13
ప్రశ్న 13
A confined aquifer has T = 200 m²/day, radius of influence R = 200 m and pumping-well radius rw = 0.20 m. If the aquifer drawdown at the well is 4 m, what pumping rate is predicted by the steady Thiem equation?
Explanation:
The radius ratio is R/rw = 200/0.20 = 1000. Therefore log10(R/rw) = 3. The Thiem relation gives Q = 2.73 × 200 × 4/3. This equals 728 m³/day. Therefore Option C is correct.
వివరణ:
Question 14
ప్రశ్న 14
A confined aquifer is pumped at 819 m³/day. Its transmissivity is 300 m²/day, radius of influence is 300 m and well radius is 0.30 m. What aquifer drawdown at the well is predicted by the ideal steady Thiem equation?
Explanation:
The radius ratio is 300/0.30 = 1000 and its common logarithm is 3. Rearranging the Thiem relation gives sw = Q log10(R/rw)/(2.73T). Thus sw = 819 × 3/(2.73 × 300). The result is 3 m. Therefore Option C is correct.
వివరణ:
Question 15
ప్రశ్న 15
A confined aquifer has T = 200 m²/day and is pumped at Q = 546 m³/day. If the aquifer drawdown at a well of radius 0.20 m is 3 m, what radius of influence is implied by the ideal steady Thiem equation?
Explanation:
From the Thiem equation, log10(R/rw) = 2.73Tsw/Q. Substitution gives 2.73 × 200 × 3/546 = 3. Therefore R/rw = 10^3 = 1000. With rw = 0.20 m, R = 1000 × 0.20 = 200 m. Hence Option C is correct.
వివరణ:
Question 16
ప్రశ్న 16
For fixed pumping rate Q, well geometry and radius of influence, what happens to the ideal Thiem drawdown when aquifer transmissivity is doubled?
Explanation:
For fixed radii, the Thiem equation shows that drawdown is inversely proportional to transmissivity. A more transmissive aquifer can convey the same pumping rate with a smaller hydraulic-head gradient. Doubling T therefore reduces the predicted aquifer drawdown to one-half. This comparison assumes the other parameters remain unchanged. Therefore Option A is correct.
వివరణ:
Question 17
ప్రశ్న 17
Under the ideal steady Thiem relation, if pumping rate is doubled while transmissivity and all relevant radii remain unchanged, what happens to drawdown?
Explanation:
The Thiem equation is linear in pumping rate for fixed transmissivity and geometry. Drawdown is therefore directly proportional to Q. If Q is doubled, the calculated aquifer drawdown also doubles. This statement applies to the ideal linear aquifer response and excludes additional nonlinear well losses. Therefore Option C is correct.
వివరణ:
Question 18
ప్రశ్న 18
For fixed Q, T and radius of influence R, what does the ideal confined Thiem equation predict if the pumping-well radius rw is increased?
Explanation:
For fixed Q and T, ideal well drawdown is proportional to log10(R/rw). Increasing rw reduces the ratio R/rw. The logarithmic term therefore decreases, producing a smaller aquifer-loss component of drawdown in the ideal model. Actual measured drawdown may additionally contain well losses and construction effects. Therefore Option A is correct.
వివరణ:
Question 19
ప్రశ్న 19
A confined aquifer is 10 m thick and a well pumps steadily at 628.3 m³/day. What is the magnitude of Darcy flux through a cylindrical surface at radius 20 m from the well?
Explanation:
The cylindrical flow area at radius r is A = 2πrb. Here A = 2π × 20 × 10, which is approximately 1256.6 m². Darcy flux magnitude is q = Q/A = 628.3/1256.6. This gives approximately 0.50 m/day. Therefore Option B is correct.
వివరణ:
Question 20
ప్రశ్న 20
In an ideal confined aquifer of constant thickness carrying a constant pumping discharge, how does the radial Darcy flux magnitude at r = 10 m compare with that at r = 20 m?
Explanation:
For steady radial flow, the same total discharge crosses each cylindrical surface surrounding the well. The cylindrical area is proportional to radius because A = 2πrb. Therefore Darcy flux q = Q/(2πrb) varies inversely with r. Halving the radius from 20 m to 10 m doubles the flux magnitude. Hence Option C is correct.
వివరణ:
Question 21
ప్రశ్న 21
What is an important advantage of using two observation wells in a steady confined-aquifer pumping test?
Explanation:
The two-observation-well Thiem equation depends on the difference in drawdown and the ratio of radial distances. An explicit radius of influence is not required in that formulation. It also avoids relying on the pumped-well water level, which may include additional well losses. Once transmissivity is known, hydraulic conductivity can be obtained if aquifer thickness is known. Therefore Option A is correct.
వివరణ:
Question 22
ప్రశ్న 22
Why can aquifer storativity not normally be determined from the classical steady two-observation-well Thiem equation alone?
Explanation:
At true steady state, hydraulic heads are no longer changing with time. Consequently there is no continuing release of water from aquifer storage associated with changing head. The equilibrium Thiem distance-drawdown equation therefore contains transmissivity but not storativity. Time-dependent pumping-test methods such as Theis or Cooper-Jacob analysis are used when storage coefficient is required. Therefore Option A is correct.
వివరణ:
Question 23
ప్రశ్న 23
Which statement best describes true steady-state conditions around a continuously pumping well?
Explanation:
During early pumping, much of the withdrawn water may be supplied by changes in aquifer storage. True steady state requires hydraulic heads at fixed positions to become constant with time. A continuing pumping rate must then be balanced by water entering the groundwater system or by reduced natural groundwater discharge elsewhere. Thus no net time-dependent storage change is required within the modeled steady system. Therefore Option A is correct.
వివరణ:
Question 24
ప్రశ్న 24
Which interpretation of the radius of influence of a pumping well is most appropriate?
Explanation:
The radius of influence represents the approximate lateral extent over which pumping noticeably affects hydraulic head. In ideal steady Thiem calculations it can be treated as an outer boundary at which drawdown is zero or negligible. In real aquifers it is not a sharp universal physical boundary. Its effective value depends on aquifer properties, pumping conditions, time and nearby hydraulic boundaries. Therefore Option A is correct.
వివరణ:
Question 25
ప్రశ్న 25
Which combination of units is dimensionally consistent with the confined-aquifer Thiem equation Q = 2πTΔh/ln(r2/r1)?
Explanation:
The radius ratio r2/r1 is dimensionless, so its logarithm is also dimensionless. Transmissivity has dimensions of L²/T and head difference has dimensions of L. Their product therefore has dimensions L³/T, which are the dimensions of volumetric discharge. The two radii may be expressed in any common length unit because only their ratio appears. Therefore Option A is correct.
వివరణ:
Question 26
ప్రశ్న 26
Consider the following statements about steady confined-aquifer well flow: I. Drawdown is generally greatest near the pumping well. II. For a homogeneous confined aquifer, transmissivity equals hydraulic conductivity multiplied by aquifer thickness. III. At steady radial flow, the same pumping discharge crosses successive cylindrical surfaces surrounding the well. IV. The classical steady Thiem distance-drawdown equation can determine transmissivity but does not by itself determine storativity. Which option is correct?
Explanation:
Statement I is correct because pumping produces the greatest piezometric-head decline close to the well. Statement II correctly gives T = Kb for a homogeneous confined aquifer. Statement III follows from continuity under steady radial flow, since the same total discharge passes through each concentric cylindrical surface. Statement IV is correct because the equilibrium Thiem equation contains no time-dependent storage parameter. Therefore all four statements are correct and Option D is the valid answer.
వివరణ:
Answer Key సమాధానాల పట్టిక
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Question 1 ప్రశ్న 1Answer: A. Groundwater moves approximately horizontally toward the well from all radial directions and hydraulic heads no longer change with time సమాధానం: A.
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Question 2 ప్రశ్న 2Answer: A. s = H - h సమాధానం: A.
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Question 3 ప్రశ్న 3Answer: A. Homogeneous and isotropic aquifer of approximately uniform thickness, fully penetrating well, constant pumping rate, radial flow and steady conditions సమాధానం: A.
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Question 4 ప్రశ్న 4Answer: B. T = Kb సమాధానం: B.
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Question 5 ప్రశ్న 5Answer: B. 2πrb సమాధానం: B.
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Question 6 ప్రశ్న 6Answer: A. Q = 2πT(h2 - h1) / ln(r2/r1) సమాధానం: A.
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Question 7 ప్రశ్న 7Answer: A. Q = 2.73T(s1 - s2) / log10(r2/r1) సమాధానం: A.
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Question 8 ప్రశ్న 8Answer: C. 1638 m³/day సమాధానం: C.
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Question 9 ప్రశ్న 9Answer: C. 200 m²/day సమాధానం: C.
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Question 10 ప్రశ్న 10Answer: C. 3 m సమాధానం: C.
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Question 11 ప్రశ్న 11Answer: A. It generally increases with increasing radial distance from the pumping well సమాధానం: A.
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Question 12 ప్రశ్న 12Answer: A. Q = 2.73Tsw / log10(R/rw) సమాధానం: A.
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Question 13 ప్రశ్న 13Answer: C. 728 m³/day సమాధానం: C.
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Question 14 ప్రశ్న 14Answer: C. 3 m సమాధానం: C.
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Question 15 ప్రశ్న 15Answer: C. 200 m సమాధానం: C.
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Question 16 ప్రశ్న 16Answer: A. It is approximately halved సమాధానం: A.
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Question 17 ప్రశ్న 17Answer: C. It doubles సమాధానం: C.
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Question 18 ప్రశ్న 18Answer: A. The calculated aquifer drawdown at the well decreases because log10(R/rw) becomes smaller సమాధానం: A.
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Question 19 ప్రశ్న 19Answer: B. 0.50 m/day సమాధానం: B.
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Question 20 ప్రశ్న 20Answer: C. It is twice as large సమాధానం: C.
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Question 21 ప్రశ్న 21Answer: A. Transmissivity can be calculated from the difference in heads or drawdowns without requiring the radius of influence or the pumped-well water level సమాధానం: A.
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Question 22 ప్రశ్న 22Answer: A. The steady equation contains no time-dependent storage term సమాధానం: A.
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Question 23 ప్రశ్న 23Answer: A. Heads at fixed locations stop changing because the pumping withdrawal is balanced by boundary inflow, induced recharge or an equivalent reduction in natural discharge సమాధానం: A.
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Question 24 ప్రశ్న 24Answer: A. It is an approximate radial distance beyond which pumping-induced drawdown is negligible for the particular pumping and aquifer conditions సమాధానం: A.
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Question 25 ప్రశ్న 25Answer: A. Q in m³/day, T in m²/day, Δh in m and both radii in the same length unit సమాధానం: A.
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Question 26 ప్రశ్న 26Answer: D. I, II, III and IV సమాధానం: D.
